A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
What is the general form of a polynomial p(x) such that that\[ p(x^2)=p(x)^2\]
 2 years ago
What is the general form of a polynomial p(x) such that that\[ p(x^2)=p(x)^2\]

This Question is Closed

Limitless
 2 years ago
Best ResponseYou've already chosen the best response.1Darn, I went to take a drink of OJ and Avinash wrote it first.

A.Avinash_Goutham
 2 years ago
Best ResponseYou've already chosen the best response.6lol ok i l make up for that

Limitless
 2 years ago
Best ResponseYou've already chosen the best response.1You're too nice, Avinash! :)

A.Avinash_Goutham
 2 years ago
Best ResponseYou've already chosen the best response.6thanks i guess :)

jlvm
 2 years ago
Best ResponseYou've already chosen the best response.0or rather \[\left( f(x)\right) ^n=x^n\]

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.0@eliassaab how do we can prove that only root of polynomial is 0?

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.0Apart from 0 complex numbers with a = 1 are only possible roots but i cant cancel them. it seems easier than the other problems but i dony know...

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.0i think its trivial because there r infinite complex numbers with a = 1 and if one of them is root then the others must be too and this is not true because a polynomial can only have a finite number of roots

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.0@eliassaab thank u sir for the nice problems u put up
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.