## eliassaab Group Title What is the general form of a polynomial p(x) such that that$p(x^2)=p(x)^2$ 2 years ago 2 years ago

1. A.Avinash_Goutham Group Title

x^n

2. Limitless Group Title

Darn, I went to take a drink of OJ and Avinash wrote it first.

3. jlvm Group Title

$f(x)=x$

4. A.Avinash_Goutham Group Title

lol ok i l make up for that

5. Limitless Group Title

You're too nice, Avinash! :)

6. A.Avinash_Goutham Group Title

thanks i guess :)

7. jlvm Group Title

or rather $\left( f(x)\right) ^n=x^n$

8. brittneyy18rm Group Title

x^n

9. mukushla Group Title

@eliassaab how do we can prove that only root of polynomial is 0?

10. mukushla Group Title

Apart from 0 complex numbers with |a| = 1 are only possible roots but i cant cancel them. it seems easier than the other problems but i dony know...

11. mukushla Group Title

i think its trivial because there r infinite complex numbers with |a| = 1 and if one of them is root then the others must be too and this is not true because a polynomial can only have a finite number of roots

12. mukushla Group Title

@eliassaab thank u sir for the nice problems u put up