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eliassaab

  • 2 years ago

What is the general form of a polynomial p(x) such that that\[ p(x^2)=p(x)^2\]

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  1. A.Avinash_Goutham
    • 2 years ago
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    x^n

  2. Limitless
    • 2 years ago
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    Darn, I went to take a drink of OJ and Avinash wrote it first.

  3. jlvm
    • 2 years ago
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    \[f(x)=x\]

  4. A.Avinash_Goutham
    • 2 years ago
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    lol ok i l make up for that

  5. Limitless
    • 2 years ago
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    You're too nice, Avinash! :)

  6. A.Avinash_Goutham
    • 2 years ago
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    thanks i guess :)

  7. jlvm
    • 2 years ago
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    or rather \[\left( f(x)\right) ^n=x^n\]

  8. brittneyy18rm
    • 2 years ago
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    x^n

  9. mukushla
    • 2 years ago
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    @eliassaab how do we can prove that only root of polynomial is 0?

  10. mukushla
    • 2 years ago
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    Apart from 0 complex numbers with |a| = 1 are only possible roots but i cant cancel them. it seems easier than the other problems but i dony know...

  11. mukushla
    • 2 years ago
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    i think its trivial because there r infinite complex numbers with |a| = 1 and if one of them is root then the others must be too and this is not true because a polynomial can only have a finite number of roots

  12. mukushla
    • 2 years ago
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    @eliassaab thank u sir for the nice problems u put up

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