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asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.2the trick with these is to look at the number under the square root sign and see if you can express it as a product of a number that is a perfect square.

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.2so think of how you can form 63 as a product of two numbers, one of which is a perfect square

janessia
 2 years ago
Best ResponseYou've already chosen the best response.1nope its not a perfect square

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.263 is not a perfect square, but can you express 63 as the product of two other numbers, one of which is a perfect square?

janessia
 2 years ago
Best ResponseYou've already chosen the best response.1can i do a factor tree?

janessia
 2 years ago
Best ResponseYou've already chosen the best response.1i got dw:1341559648703:dw

janessia
 2 years ago
Best ResponseYou've already chosen the best response.1thts wat i got? ignore the bottom part

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.2not quite:\[\sqrt{63}=\sqrt{9*7}=\sqrt{3^2*7}=3\sqrt{7}\]

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.2you have swapped the 3 and 7

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.2ok, now don't forget you also have to multiply by that 5 in the original question

janessia
 2 years ago
Best ResponseYou've already chosen the best response.1so 5 times the answer we got?

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.2so what do you get for your final answer?

janessia
 2 years ago
Best ResponseYou've already chosen the best response.1ohk hold on dnt leave yet

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.2I won't  don't worry :)

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.2leave the answer in radical form
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