janessia
need help with simplifying radicals
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janessia
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|dw:1341559210514:dw|
asnaseer
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the trick with these is to look at the number under the square root sign and see if you can express it as a product of a number that is a perfect square.
asnaseer
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so think of how you can form 63 as a product of two numbers, one of which is a perfect square
janessia
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nope its not a perfect square
asnaseer
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63 is not a perfect square, but can you express 63 as the product of two other numbers, one of which is a perfect square?
janessia
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can i do a factor tree?
asnaseer
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yes
janessia
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ohk hold on
asnaseer
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ok
janessia
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i got |dw:1341559648703:dw|
janessia
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thts wat i got?
ignore the bottom part
asnaseer
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not quite:\[\sqrt{63}=\sqrt{9*7}=\sqrt{3^2*7}=3\sqrt{7}\]
asnaseer
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you have swapped the 3 and 7
janessia
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yea thts wat i meant
asnaseer
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ok, now don't forget you also have to multiply by that 5 in the original question
janessia
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so 5 times the answer we got?
asnaseer
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yes - thats right
asnaseer
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so what do you get for your final answer?
janessia
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ohk hold on dnt leave yet
asnaseer
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I won't - don't worry :)
janessia
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i got a decimal?
asnaseer
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leave the answer in radical form
janessia
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ohhhhh
janessia
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|dw:1341559908464:dw|
asnaseer
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perfect! well done!
janessia
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thnk u!!!!
asnaseer
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yw :)