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janessia

  • 3 years ago

Solve 5+8i-4+2i

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  1. apoorvk
    • 3 years ago
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    Simply add/subtract the real and imaginary parts separately and express in "a+ib" form!

  2. janessia
    • 3 years ago
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    so 1+10i?

  3. lgbasallote
    • 3 years ago
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    ^that's right

  4. apoorvk
    • 3 years ago
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    yeah correct-o!

  5. janessia
    • 3 years ago
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    wat about i7? 7 is an exponent

  6. apoorvk
    • 3 years ago
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    you mean \(\iota^7\) right?

  7. janessia
    • 3 years ago
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    yea i guess

  8. apoorvk
    • 3 years ago
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    okay do you know that i^2 =-1, i^3=-i, i^4=1, i^5=i again, i^6=-i... and so on? what would i^7 be according to this trend?

  9. janessia
    • 3 years ago
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    -1?

  10. lgbasallote
    • 3 years ago
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    here's a hint for you!! if the exponent is odd (except for 3) the answer is -i if the exponent is even (other than 2) the answer is 1

  11. janessia
    • 3 years ago
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    ohk so its -i

  12. apoorvk
    • 3 years ago
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    yes -i!

  13. janessia
    • 3 years ago
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    ohk thnx!

  14. apoorvk
    • 3 years ago
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    anytime!

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