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dariyana

  • 2 years ago

What kind of triangle is shown? right isosceles scalene equilateral

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  1. dariyana
    • 2 years ago
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  2. Trexy
    • 2 years ago
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    i think is Scalene.. Here is the sites It might help you: http://www.mathsisfun.com/triangle.html

  3. Wired
    • 2 years ago
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    The distance between two points can be calculated like so: \[Distance = \sqrt{(dx)^{2} + (dy)^{2}}\] dx = the DIFFERENCE between X in the two points. This can be written as: \[|x _{1}-x_{2}|\] Since you'll be squaring the value, you can just ignore the signs and use this equation: \[Distance = \sqrt{(x _{1}-x_{2})^{2} + (y _{1}-y_{2})^{2}}\] Do that for each side of the equation.

  4. dariyana
    • 2 years ago
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    do any one disagree with @Trexy

  5. NyKole
    • 2 years ago
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    Trexy is right.. is this from flvs?

  6. dariyana
    • 2 years ago
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    lol yeah

  7. Wired
    • 2 years ago
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    The math says that's not the answer.

  8. NyKole
    • 2 years ago
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    Its prob isosceles?

  9. Wired
    • 2 years ago
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    Or you could do the math. It would only take a couple of minutes.

  10. Trexy
    • 2 years ago
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    hahha... dont give me wrong cuz Im not sure if that the right answer so yeah.. @dariyana just ask @Wired ?

  11. dariyana
    • 2 years ago
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    lol ok

  12. Wired
    • 2 years ago
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    \[\sqrt{(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}\] Start with (-10,8) and (-10,3). \[\sqrt{(-10-(-10))^{2}+(8-3)^{2}}\]

  13. Trexy
    • 2 years ago
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    its really freaks me out everytime i look at your picture icon @Wired ..its looks like your the strict person here lol.. hahah

  14. Wired
    • 2 years ago
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    LOL I know, but those aren't eyebrows!

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