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HammerG Group Title

Simplify. 5 1/3 + (-3 9/18) A. 1 5/6 B. 2 8/15 C. 3 8/13 D. 8 5/6

  • 2 years ago
  • 2 years ago

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  1. HammerG Group Title
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    |dw:1341642729696:dw|

    • 2 years ago
  2. Raja99 Group Title
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    it is 18 or 8

    • 2 years ago
  3. Raja99 Group Title
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    |dw:1341642903689:dw|

    • 2 years ago
  4. HammerG Group Title
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    yes

    • 2 years ago
  5. HammerG Group Title
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    18 sorry

    • 2 years ago
  6. Raja99 Group Title
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    b is ans

    • 2 years ago
  7. HammerG Group Title
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    Thanks N why tho?

    • 2 years ago
  8. Raja99 Group Title
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    ??

    • 2 years ago
  9. HammerG Group Title
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    I mean why B sorry I kinda like to know why just so I understand ^ ^

    • 2 years ago
  10. Wired Group Title
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    The answer is NOT B. I'll explain in my next post.

    • 2 years ago
  11. Wired Group Title
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    Since any number divided by itself equals 1, you can rewrite 1 as a fraction, e.g. \[1 = \frac{2}{2} = \frac{3}{3} = \frac{6}{6}\] Any whole number can be rewritten as a fraction by multiplying it by 1 in the form of a fraction. 5 can be made into a fraction like so: \[5 * 1 = 5*\frac{3}{3} = \frac{15}{3}\] \[5\frac{1}{3} = \frac{15}{3} + \frac{1}{3} = \frac{15+1}{3} = \frac{16}{3}\]

    • 2 years ago
  12. Wired Group Title
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    Similarly, fractions can also be rewritten by multiplying them by 1 in the form of a fraction. In this case we'll need to multiply it by something to get the denominator to equal 18. What fraction do you think it should be @HammerG ?

    • 2 years ago
  13. HammerG Group Title
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    yeh its C from what I got.

    • 2 years ago
  14. Wired Group Title
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    Nope. If you show your work I can help you figure out where you went of the rails, so to speak.

    • 2 years ago
  15. Raja99 Group Title
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    no its b

    • 2 years ago
  16. Wired Group Title
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    5 and one third minus three and nine eighteenths cannot possibly be B. Even Wolfram Alpha agrees with me.

    • 2 years ago
  17. Wired Group Title
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    \[5 + \frac{1}{3}-(3+\frac{9}{18})\]

    • 2 years ago
  18. HammerG Group Title
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    8 5/6

    • 2 years ago
  19. Raja99 Group Title
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    @wired yo did a big flaw

    • 2 years ago
  20. Raja99 Group Title
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    its not(3+9/18)

    • 2 years ago
  21. Raja99 Group Title
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    that term value comes out to (16/3)-(63/18) =1.833

    • 2 years ago
  22. lgbasallote Group Title
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    \[\huge 5 \frac{1}{3} = \frac{16}{3}\] \[\huge -3\frac{9}{18} \implies -3\frac 12 = -\frac{7}{2}\] \[\huge \frac{16}{3} - \frac{7}{2} = \frac{32}{6} - \frac{21}{6}\]

    • 2 years ago
  23. lgbasallote Group Title
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    \[\huge 1.833 \ne 2\frac{8}{15}\]

    • 2 years ago
  24. Raja99 Group Title
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    another big flaw@igbasallote..it is not fraction to cancel like that(3 9/18)...it is a mixed fraction

    • 2 years ago
  25. lgbasallote Group Title
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    \[3\frac{9}{18} = 3\frac{1}{2}\]

    • 2 years ago
  26. lgbasallote Group Title
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    try it

    • 2 years ago
  27. lgbasallote Group Title
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    see for yourself

    • 2 years ago
  28. Raja99 Group Title
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    no yaar

    • 2 years ago
  29. Wired Group Title
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    \[\frac{9}{18} = \frac{1}{2}\] \[3\frac{1}{2} = \frac{6}{2}+\frac{1}{2}=\frac{7}{2}\] \[\frac{16}{3}+-\frac{7}{2} = \frac{16}{3}-\frac{7}{2} = \frac{32}{6}-\frac{21}{6} = \frac{11}{6}=1\frac{5}{6}\] @Raja99 What are you talking about? We KNOW it's a mixed fraction, hence why we're showing our work converting it to fractions, giving them equal denominators, and then adding them together and turning them back into a mixed fraction!

    • 2 years ago
  30. lgbasallote Group Title
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    http://www.wolframalpha.com/input/?i=5+1%2F3++-+3+9%2F18

    • 2 years ago
  31. lgbasallote Group Title
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    ^exactly what i wrote

    • 2 years ago
  32. HammerG Group Title
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    1 5/6 is the answer

    • 2 years ago
  33. Wired Group Title
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    @HammerG Yes.

    • 2 years ago
  34. HammerG Group Title
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    okay don't want to get confused lol.

    • 2 years ago
  35. Wired Group Title
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    All I can tell you is that @lgbasallote and I got the same answer, Wolfram Alpha got the same answer, and we showed how we got it, whereas Raja99 hasn't shown any of his work.

    • 2 years ago
  36. Raja99 Group Title
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    @igbasallote is correct

    • 2 years ago
  37. prettydarkD Group Title
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    Can one person write out the whole problem step by step so i can kno exatly how to it an whats the answer is

    • one year ago
  38. prettydarkD Group Title
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    can one person show the whole work for this work please

    • one year ago
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