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virtus
Group Title
perpendicular distance from point B(0,5) to the line x+3y5=0
 2 years ago
 2 years ago
virtus Group Title
perpendicular distance from point B(0,5) to the line x+3y5=0
 2 years ago
 2 years ago

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ash2326 Group TitleBest ResponseYou've already chosen the best response.2
@virtus Are you here?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
@virtus There maybe a direct formula for this, but I don't remember that. I'll start from the basics. Do you have time for this?
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.2
sure, thanks ash2326
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
Can I give the formula??
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Thanks virtus, let's begin. I recommend that you understand the problem, you'll remember it always. What do you want?
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
Go ahead @ash2326 ..
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
dw:1341645333105:dw Let AB be our line and C is the point for which we need to find the perpendicular distance. Do you understand the diagram?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
You can see that the perpendicular line from the point C is intersecting the line AB at a point. Let it be D If we could find the coordinates of D, then we can easily find the distance. do you have any ideas what should we do?
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.2
find the Point Of Intersection
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
Ha ha ha ha..
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Yeah:) @virtus For that we need to find the equation of the line CD, do you have any idea how to do that?
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.2
well you know what point C is and the gradient of line CD would be 1/ gradient of line AB
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.2
oh wait do we know what C is ?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Awesome:D Could you do that? We have AB as \(x+3y5=0\) Yeah we know C as (0, 5)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Oops, You made a mistake I can see that perpendicular line's slope is same as AB, it's to be 1/ slope AB Check again :)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
No problem, :D find it again?
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.2
y5 =3(x0) y=3x +5 3xy+5=0
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Correct:D Now find the intersection of the line (3xy+5=0) and (x+3y5=0) this will give us D
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Great work:D now find the distance between (0, 5) and (1, 2) using distance formula.
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
That will be the perpendicular distance:D
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.2
ngawwwwwww! I SEE!!!! so that's how you do it ;) oh btw i got square root 10
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Yeah, that's correct:D Great work btw:D
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.2
thanks so much for your invaluble help @ash2326 :D
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
@virtus you did all the work. I just guided you:D You are a good student:D
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
you can also use the formula from analytic geometry that the distance from a given point to a given line in general form \(\large Ax+By+C=0 \) is given by Distance = \(\large \frac{Ax_0+By_0+C}{\pm \sqrt{A^2+B^2}} \) where \(\ (x_0, y_0) \) are the coordinates of the given point.
 2 years ago
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