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lgbasallote

  • 3 years ago

LGBADERIVATIVE: \[\huge f(t) = \sin (e^t) + e^{\sin t}\]

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  1. freckles
    • 3 years ago
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    Whats this mean?

  2. lgbasallote
    • 3 years ago
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    i know the first term is \[e^t \cos (e^t)\]

  3. freckles
    • 3 years ago
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    What is a LGBADERIVATIVE?

  4. lgbasallote
    • 3 years ago
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    derivative lol

  5. freckles
    • 3 years ago
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    Oh I would break it up And use log differentiation

  6. lgbasallote
    • 3 years ago
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    \[a = e^{\sin t}\] \[\ln a = \sin t\] \[a' = \sin t \cos t?\]

  7. freckles
    • 3 years ago
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    well for the first one we don't need log differentiation but the second one we do

  8. waterineyes
    • 3 years ago
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    Second will be: \[\huge cost(e^{sint})\]

  9. lgbasallote
    • 3 years ago
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    oops yeah that's what i meant

  10. freckles
    • 3 years ago
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    \[g=e^{\sin(t)}\] \[\ln(g)=\ln(e^{\sin(t)})\] Or you can use the short way whatever lol

  11. lgbasallote
    • 3 years ago
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    \[\huge e^t \cos t + \cos t (e^{\sin t})\]

  12. lgbasallote
    • 3 years ago
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    right?

  13. waterineyes
    • 3 years ago
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    No first one is not..

  14. waterineyes
    • 3 years ago
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    \[\huge e^t(cose^t)\]

  15. lgbasallote
    • 3 years ago
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    oh argument is e^t

  16. lgbasallote
    • 3 years ago
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    \[\huge e^t \cos (e^t) + \cos t(e^{\sin t})\]

  17. waterineyes
    • 3 years ago
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    Now it is okay..

  18. lgbasallote
    • 3 years ago
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    wonderful

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