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LGBADERIVATIVE: \[\huge f(t) = \sin (e^t) + e^{\sin t}\]

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Whats this mean?
i know the first term is \[e^t \cos (e^t)\]

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Other answers:

derivative lol
Oh I would break it up And use log differentiation
\[a = e^{\sin t}\] \[\ln a = \sin t\] \[a' = \sin t \cos t?\]
well for the first one we don't need log differentiation but the second one we do
Second will be: \[\huge cost(e^{sint})\]
oops yeah that's what i meant
\[g=e^{\sin(t)}\] \[\ln(g)=\ln(e^{\sin(t)})\] Or you can use the short way whatever lol
\[\huge e^t \cos t + \cos t (e^{\sin t})\]
No first one is not..
\[\huge e^t(cose^t)\]
oh argument is e^t
\[\huge e^t \cos (e^t) + \cos t(e^{\sin t})\]
Now it is okay..

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