lgbasallote
  • lgbasallote
LGBADERIVATIVE: \[\huge f(t) = \sin (e^t) + e^{\sin t}\]
Mathematics
schrodinger
  • schrodinger
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freckles
  • freckles
Whats this mean?
lgbasallote
  • lgbasallote
i know the first term is \[e^t \cos (e^t)\]
freckles
  • freckles
What is a LGBADERIVATIVE?

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lgbasallote
  • lgbasallote
derivative lol
freckles
  • freckles
Oh I would break it up And use log differentiation
lgbasallote
  • lgbasallote
\[a = e^{\sin t}\] \[\ln a = \sin t\] \[a' = \sin t \cos t?\]
freckles
  • freckles
well for the first one we don't need log differentiation but the second one we do
anonymous
  • anonymous
Second will be: \[\huge cost(e^{sint})\]
lgbasallote
  • lgbasallote
oops yeah that's what i meant
freckles
  • freckles
\[g=e^{\sin(t)}\] \[\ln(g)=\ln(e^{\sin(t)})\] Or you can use the short way whatever lol
lgbasallote
  • lgbasallote
\[\huge e^t \cos t + \cos t (e^{\sin t})\]
lgbasallote
  • lgbasallote
right?
anonymous
  • anonymous
No first one is not..
anonymous
  • anonymous
\[\huge e^t(cose^t)\]
lgbasallote
  • lgbasallote
oh argument is e^t
lgbasallote
  • lgbasallote
\[\huge e^t \cos (e^t) + \cos t(e^{\sin t})\]
anonymous
  • anonymous
Now it is okay..
lgbasallote
  • lgbasallote
wonderful

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