Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

lgbasalloteBest ResponseYou've already chosen the best response.0
im guessing ln again
 one year ago

frecklesBest ResponseYou've already chosen the best response.4
Well you can use log diff like I mention before Or you can use straight chain man
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
\[\ln y = k\tan \sqrt x\] now what...
 one year ago

frecklesBest ResponseYou've already chosen the best response.4
\[y=e^{f(x)} => y'=f'(x)e^{f(x)}\]
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i uess i make it \[\ln y = k\frac{\sin \sqrt x}{\cos \sqrt x}\]
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
this seems complicated :
 one year ago

frecklesBest ResponseYou've already chosen the best response.4
\[y=e^{f(x)}\] \[\ln(y)=\ln(e^{f(x)})\] \[\ln(y)=f(x) \cdot \ln(e)\] \[\ln(y)=f(x) (1)\] \[\ln(y)=f(x)\] \[\frac{y'}{y}=f'(x)\] \[y'=y f'(x)\] \[y'=e^{f(x)} f'(x)\]
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
so my problem is that f'(x) now..
 one year ago

ZarkonBest ResponseYou've already chosen the best response.1
\[\frac{d}{dx}\tan(u)=\sec^2(u)\frac{du}{dx}\]
 one year ago

frecklesBest ResponseYou've already chosen the best response.4
^ what zarkon said :)
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
uhmm oh yeah...how could i forget *facepalm*
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i need to take a rest hahahaha so it will be \[y' = \frac{e^{k\tan \sqrt x} k\sec^2 \sqrt x}{2\sqrt x}\] right?
 one year ago

frecklesBest ResponseYou've already chosen the best response.4
Yes that looks good to me I see no error
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.