LGBADERIVATIVE: \[\huge \frac{\text d}{\text dx} x^{e^{x^2}}\]

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LGBADERIVATIVE: \[\huge \frac{\text d}{\text dx} x^{e^{x^2}}\]

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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rewrite as \[e^{e^{x^2}\ln(x)}\] and use the chain rule
do you mean \[\ln y = e^{x^2} \ln x?\]
\[\huge x^{e^{x^2}}*lnx* e^{x^2}*2x\]

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Other answers:

uhh how?
\[\huge y=a^{f(x)}\] \[\huge y'=a^{f(x)}*f'(x)*lna\]
oh i see
yeah that makes sense thanks
I made a mistake..
x is not constant that formula is for constants
\[\huge x^{e^{x^2}}*\left( e^{x^2}*2x*lnx+\frac{e^{x2}}{x}\right)\]
@mukushla you're right, but still we need that formula..
|dw:1341688029055:dw|
right

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