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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0rewrite as \[e^{e^{x^2}\ln(x)}\] and use the chain rule

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0do you mean \[\ln y = e^{x^2} \ln x?\]

cinar
 2 years ago
Best ResponseYou've already chosen the best response.1\[\huge x^{e^{x^2}}*lnx* e^{x^2}*2x\]

cinar
 2 years ago
Best ResponseYou've already chosen the best response.1\[\huge y=a^{f(x)}\] \[\huge y'=a^{f(x)}*f'(x)*lna\]

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0yeah that makes sense thanks

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.0x is not constant that formula is for constants

cinar
 2 years ago
Best ResponseYou've already chosen the best response.1\[\huge x^{e^{x^2}}*\left( e^{x^2}*2x*lnx+\frac{e^{x2}}{x}\right)\]

cinar
 2 years ago
Best ResponseYou've already chosen the best response.1@mukushla you're right, but still we need that formula..
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