lgbasallote
LGBADERIVATIVE:
\[\huge \frac{\text d}{\text dx} x^{e^{x^2}}\]



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anonymous
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rewrite as
\[e^{e^{x^2}\ln(x)}\] and use the chain rule

lgbasallote
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do you mean \[\ln y = e^{x^2} \ln x?\]

cinar
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\[\huge x^{e^{x^2}}*lnx* e^{x^2}*2x\]

lgbasallote
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uhh how?

cinar
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\[\huge y=a^{f(x)}\]
\[\huge y'=a^{f(x)}*f'(x)*lna\]

lgbasallote
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oh i see

lgbasallote
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yeah that makes sense thanks

cinar
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I made a mistake..

mukushla
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x is not constant
that formula is for constants

cinar
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\[\huge x^{e^{x^2}}*\left( e^{x^2}*2x*lnx+\frac{e^{x2}}{x}\right)\]

cinar
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@mukushla you're right, but still we need that formula..

cinar
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dw:1341688029055:dw

mukushla
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right