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lgbasallote

LGBADERIVATIVE: \[\huge \frac{\text d}{\text dx} x^{e^{x^2}}\]

  • one year ago
  • one year ago

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  1. satellite73
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    rewrite as \[e^{e^{x^2}\ln(x)}\] and use the chain rule

    • one year ago
  2. lgbasallote
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    do you mean \[\ln y = e^{x^2} \ln x?\]

    • one year ago
  3. cinar
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    \[\huge x^{e^{x^2}}*lnx* e^{x^2}*2x\]

    • one year ago
  4. lgbasallote
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    uhh how?

    • one year ago
  5. cinar
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    \[\huge y=a^{f(x)}\] \[\huge y'=a^{f(x)}*f'(x)*lna\]

    • one year ago
  6. lgbasallote
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    oh i see

    • one year ago
  7. lgbasallote
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    yeah that makes sense thanks

    • one year ago
  8. cinar
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    I made a mistake..

    • one year ago
  9. mukushla
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    x is not constant that formula is for constants

    • one year ago
  10. cinar
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    \[\huge x^{e^{x^2}}*\left( e^{x^2}*2x*lnx+\frac{e^{x2}}{x}\right)\]

    • one year ago
  11. cinar
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    @mukushla you're right, but still we need that formula..

    • one year ago
  12. cinar
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    |dw:1341688029055:dw|

    • one year ago
  13. mukushla
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    right

    • one year ago
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