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anonymous
 4 years ago
Solve for b.
a = a+b+c/3
A.) 3A  a  c = b
B.) c / 3 = b
C.) A  c / 3 = b
C.) 3  c = b
anonymous
 4 years ago
Solve for b. a = a+b+c/3 A.) 3A  a  c = b B.) c / 3 = b C.) A  c / 3 = b C.) 3  c = b

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ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0We have \[a=a+b+\frac c3\] Subtract both sides by a \[aa=aa+b+\frac c3\] We get \[0=0+b+\frac c3\] now subtract both sides by c/3 \[0\frac c3=b+\frac c3\frac c3\] we get finally \[\frac c3=b\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Pass the a that is in the denominator multiplying the letter "a"
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