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\[\sum_{i=1}^{\infty}12\left(\frac{3}{5}\right)^{i-1}\]

\sum_{i=1}^{\infty}12\left(\frac{3}{5}\right)^{i-1}

this is a geometric sum

\[\sum_{i=1}^{\infty}a\left(r\right)^{i-1}=\frac{a}{1-r}\]
for \(|r|<1\)

compair your question to what I typed above

I'm confused, which question is that one ^

that is the sum in question #3 of the file you posted

I don't get this at all >.<

have you had a lecture on how to computer geometric series?

*compute

http://tutorial.math.lamar.edu/Classes/CalcII/Series_Special.aspx