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anonymous
 3 years ago
A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance?
anonymous
 3 years ago
A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I had a smiliar problem expect I was asked to find the R. I used R= (Delta V ^2 x time)/mc(T2T1)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so that is the formula?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0My bad, that's not the correct formula for this type of problem. You aren't given the potential difference.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0:( actually i can't understand the problem

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.1\[R _{t}=R _{0}+\alpha t\] \[R _{t}R _{0}=\alpha t\] 3  1.5 = 0.00375 * t Now solve for t

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.1Raising the temperature needs to double the resistance. 1.5 ohms * 2 = 3 ohms

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.1\[t=\frac{31.5}{0.00375}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks. so the unit must be degree celsius ?

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.1Yes. The unit for the answer is degrees Celsius :)
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