alfers101
A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance?
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JustHere
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I had a smiliar problem expect I was asked to find the R. I used R= (Delta V ^2 x time)/mc(T2-T1)
alfers101
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so that is the formula?
JustHere
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My bad, that's not the correct formula for this type of problem. You aren't given the potential difference.
alfers101
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:( actually i can't understand the problem
kropot72
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\[R _{t}=R _{0}+\alpha t\]
\[R _{t}-R _{0}=\alpha t\]
3 - 1.5 = 0.00375 * t
Now solve for t
alfers101
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why 3?
kropot72
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Raising the temperature needs to double the resistance. 1.5 ohms * 2 = 3 ohms
alfers101
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t= 3-15 / 0.0037 ??
kropot72
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\[t=\frac{3-1.5}{0.00375}\]
alfers101
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thanks. so the unit must be degree celsius ?
kropot72
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Yes. The unit for the answer is degrees Celsius :)
alfers101
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wow thanks a lot. :D
kropot72
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You're welcome :)