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A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance?
 one year ago
 one year ago
A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance?
 one year ago
 one year ago

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JustHereBest ResponseYou've already chosen the best response.0
I had a smiliar problem expect I was asked to find the R. I used R= (Delta V ^2 x time)/mc(T2T1)
 one year ago

alfers101Best ResponseYou've already chosen the best response.0
so that is the formula?
 one year ago

JustHereBest ResponseYou've already chosen the best response.0
My bad, that's not the correct formula for this type of problem. You aren't given the potential difference.
 one year ago

alfers101Best ResponseYou've already chosen the best response.0
:( actually i can't understand the problem
 one year ago

kropot72Best ResponseYou've already chosen the best response.1
\[R _{t}=R _{0}+\alpha t\] \[R _{t}R _{0}=\alpha t\] 3  1.5 = 0.00375 * t Now solve for t
 one year ago

kropot72Best ResponseYou've already chosen the best response.1
Raising the temperature needs to double the resistance. 1.5 ohms * 2 = 3 ohms
 one year ago

kropot72Best ResponseYou've already chosen the best response.1
\[t=\frac{31.5}{0.00375}\]
 one year ago

alfers101Best ResponseYou've already chosen the best response.0
thanks. so the unit must be degree celsius ?
 one year ago

kropot72Best ResponseYou've already chosen the best response.1
Yes. The unit for the answer is degrees Celsius :)
 one year ago

alfers101Best ResponseYou've already chosen the best response.0
wow thanks a lot. :D
 one year ago
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