## alfers101 Group Title A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance? 2 years ago 2 years ago

1. JustHere Group Title

I had a smiliar problem expect I was asked to find the R. I used R= (Delta V ^2 x time)/mc(T2-T1)

2. alfers101 Group Title

so that is the formula?

3. JustHere Group Title

My bad, that's not the correct formula for this type of problem. You aren't given the potential difference.

4. alfers101 Group Title

:( actually i can't understand the problem

5. kropot72 Group Title

$R _{t}=R _{0}+\alpha t$ $R _{t}-R _{0}=\alpha t$ 3 - 1.5 = 0.00375 * t Now solve for t

6. alfers101 Group Title

why 3?

7. kropot72 Group Title

Raising the temperature needs to double the resistance. 1.5 ohms * 2 = 3 ohms

8. alfers101 Group Title

t= 3-15 / 0.0037 ??

9. kropot72 Group Title

$t=\frac{3-1.5}{0.00375}$

10. alfers101 Group Title

thanks. so the unit must be degree celsius ?

11. kropot72 Group Title

Yes. The unit for the answer is degrees Celsius :)

12. alfers101 Group Title

wow thanks a lot. :D

13. kropot72 Group Title

You're welcome :)