## anonymous 4 years ago A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance?

1. anonymous

I had a smiliar problem expect I was asked to find the R. I used R= (Delta V ^2 x time)/mc(T2-T1)

2. anonymous

so that is the formula?

3. anonymous

My bad, that's not the correct formula for this type of problem. You aren't given the potential difference.

4. anonymous

:( actually i can't understand the problem

5. kropot72

$R _{t}=R _{0}+\alpha t$ $R _{t}-R _{0}=\alpha t$ 3 - 1.5 = 0.00375 * t Now solve for t

6. anonymous

why 3?

7. kropot72

Raising the temperature needs to double the resistance. 1.5 ohms * 2 = 3 ohms

8. anonymous

t= 3-15 / 0.0037 ??

9. kropot72

$t=\frac{3-1.5}{0.00375}$

10. anonymous

thanks. so the unit must be degree celsius ?

11. kropot72

Yes. The unit for the answer is degrees Celsius :)

12. anonymous

wow thanks a lot. :D

13. kropot72

You're welcome :)