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alfers101
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A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance?
 2 years ago
 2 years ago
alfers101 Group Title
A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance?
 2 years ago
 2 years ago

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JustHere Group TitleBest ResponseYou've already chosen the best response.0
I had a smiliar problem expect I was asked to find the R. I used R= (Delta V ^2 x time)/mc(T2T1)
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
so that is the formula?
 2 years ago

JustHere Group TitleBest ResponseYou've already chosen the best response.0
My bad, that's not the correct formula for this type of problem. You aren't given the potential difference.
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
:( actually i can't understand the problem
 2 years ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.1
\[R _{t}=R _{0}+\alpha t\] \[R _{t}R _{0}=\alpha t\] 3  1.5 = 0.00375 * t Now solve for t
 2 years ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.1
Raising the temperature needs to double the resistance. 1.5 ohms * 2 = 3 ohms
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
t= 315 / 0.0037 ??
 2 years ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.1
\[t=\frac{31.5}{0.00375}\]
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
thanks. so the unit must be degree celsius ?
 2 years ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.1
Yes. The unit for the answer is degrees Celsius :)
 2 years ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
wow thanks a lot. :D
 2 years ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.1
You're welcome :)
 2 years ago
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