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A silverwire has a resistance of 1.5Ω at 0°C and a temperature coefficient of resistance of 0.00375/°C. To what temperature must be the raised to double the resistance?

Physics
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I had a smiliar problem expect I was asked to find the R. I used R= (Delta V ^2 x time)/mc(T2-T1)
so that is the formula?
My bad, that's not the correct formula for this type of problem. You aren't given the potential difference.

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Other answers:

:( actually i can't understand the problem
\[R _{t}=R _{0}+\alpha t\] \[R _{t}-R _{0}=\alpha t\] 3 - 1.5 = 0.00375 * t Now solve for t
why 3?
Raising the temperature needs to double the resistance. 1.5 ohms * 2 = 3 ohms
t= 3-15 / 0.0037 ??
\[t=\frac{3-1.5}{0.00375}\]
thanks. so the unit must be degree celsius ?
Yes. The unit for the answer is degrees Celsius :)
wow thanks a lot. :D
You're welcome :)

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