A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
This is a problem that i want to solve but i can't really answer it. It's a sample problem from my book:
The density of a copper is 8.89 is 8.89 g/cm^3 and the ρ=1924μΩcm. Determine the length(m) and resistance of 12kg of copper; the crosssection of which in 2.09mm^2.
 2 years ago
This is a problem that i want to solve but i can't really answer it. It's a sample problem from my book: The density of a copper is 8.89 is 8.89 g/cm^3 and the ρ=1924μΩcm. Determine the length(m) and resistance of 12kg of copper; the crosssection of which in 2.09mm^2.

This Question is Closed

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3Copper wire can be considered as a cylinder. Here we have cross section given as 2.09 mm^2 To find length, we need to find the volume We have the density as 8.89 g/ cm^2 Mass= 12 kg Could you find the volume? Do remember to change mass in kg to grams, this will give you volume in cm^3

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3Yeah, now find volume Volume= mass/density

theyatin
 2 years ago
Best ResponseYou've already chosen the best response.0density hai mass hai volume= length into cross section you can find length

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1@ash2326 @theyatin what do you think?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3Yeah you're right. Sorry My battery was out of juice

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1than after i got the volume, whats next? getting the length?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3\[\text{Volume}= \text{Area of Cross section} \times \text{length}\]

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1length=volume/ area of cross section?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3Yeah, remember to convert cross section into cm^2, it's given in mm^2 Then you'll get length in cm

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1length= 1,349.83 cm^2/0.209cm^2 ??

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.31 mm = 1/ 10 cm \[1 mm^2= \frac{1}{10\times 10} cm^2\]

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3area of cross section=2.09 mm^2=2.09/100 cm^2

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3yeah now you find length

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1length= 1,349.83 cm^2/0.0209cm^2 ?

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1what would be the unit?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3\[\frac{cm^3}{cm^2}\]???

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1oh i get it. its cm. cause i saw both cm^2

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3good, now you have the length. You need to find the resistance. Do you have any idea, how to find that?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3that's right but there is one more relation relating resistance with the property of material and the dimensions of the wire. \[R=\rho(\text{micro ohmscm}) \times \frac{\text{Length (in cm)}}{\text{Area of cross section(in cm^2)}}\] From this you'll get resistance in micro ohms

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1R=ρ(micro ohmscm)×3090199.522 cm ?

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1then multiply it to 1924 ?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3Yeah this is right but this in micro ohms. Divide by 10^6 to get resistance in ohms

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1why divide it by 10^6 ?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3Because resistance we found is in micro ohms \[1 micro ohm=\frac{1}{10^6} \text{ohms}\]

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1oh okay thanks so the answer will be 5945.54 ohms ?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3Yeah that's all we found length and resistance Wait a min, we need to find length in meters. For that divide length in cm by 100 as 1 meter= 100 cms

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1so that must be 645.8517 ?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.364585.17/100=>64.581517 meters

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3yeah, you're right. Sorry :(

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1its alright :) then whats next? we will repeat it again? because we got the wrong length?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.3nope, we found the resistance correctly. question asked length in meters that's why we changed it

alfers101
 2 years ago
Best ResponseYou've already chosen the best response.1oh thanks a lot. :D a massive thank you! God bless :D
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.