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Raja99
 2 years ago
Best ResponseYou've already chosen the best response.3awe some introduction waiting for it!

FoolAroundMath
 2 years ago
Best ResponseYou've already chosen the best response.1\(\tau(5)=2, \tau(7) = 2, \tau(12)=6,\tau(35)=4, \tau(6)=4, \tau(4)=3 \) So, for Q7. \(I, II\) are correct. For Q8, \(\tau (\tau (\tau(12))) = \tau(\tau(6)) = \tau(4) = 3\)

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1@FoolAroundMath , can you please explain what you wrote?

anonymoustwo44
 2 years ago
Best ResponseYou've already chosen the best response.0its 3 at question 8....

wasiqss
 2 years ago
Best ResponseYou've already chosen the best response.0saif bhai i told you is type k questions nahi aye gai

Raja99
 2 years ago
Best ResponseYou've already chosen the best response.3first calculate the divisors for each of the no shown.... Divisors of 5: 1, 5 Divisors of 7: 1, 7 Divisors of 35: 1, 5, 7, 35 Divisors of 12: 1, 2, 3, 4, 6, 12 Divisors of 6: 1, 2, 3, 6

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1@wasiqss ; hehe. This is SAT 1.

Raja99
 2 years ago
Best ResponseYou've already chosen the best response.3and then count the no of divisors for each one then the ans by @FoolAroundMath follows

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1@wasiqss ; Most probably.

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.0for \[\large n=\prod_{k=1}^{m} p_{k}^{\alpha_{k}} \\ \tau(n)=(1+\alpha_{1})(1+\alpha_{2})...(1+\alpha_{m})\] for example \[12=2^2*3^1 \\ \tau(12)=(2+1)(1+1)=6\]

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1@mukushla ; Sorry i don't get it . :D

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1@Raja99 , okay i get till the divisor thing.. what's next?

Raja99
 2 years ago
Best ResponseYou've already chosen the best response.3is it a way to fing the divisors @mukushla

Raja99
 2 years ago
Best ResponseYou've already chosen the best response.3then the value of the tau(5)=no of divisors of 5(Pl count it) and subsitute to chk the conditions.

Raja99
 2 years ago
Best ResponseYou've already chosen the best response.3for tau(5)=2 and tau(7)=2 and tau(35)=4 like that

Raja99
 2 years ago
Best ResponseYou've already chosen the best response.3and chk 2*2=4 then option is true...

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1Ah, nice., so; 1. 2 = 2 2. 2*2 = 4 3. 2+2 =/= 6 Perfect.

FoolAroundMath
 2 years ago
Best ResponseYou've already chosen the best response.1I was typing the whole thing out when OS crashed again. I'll leave it to the others to do that then ;)

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1@FoolAroundMath , Oh. okay. No Problem. (:

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1@Raja99 : Moving on to Question 8?

Raja99
 2 years ago
Best ResponseYou've already chosen the best response.3Divisors of 12: 1, 2, 3, 4, 6, 12 Divisors of 6: 1, 2, 3, 6 Divisors of 4: 1, 2, 4 ok then tau(12)=6 then tau(6)=4 then tau(4)=3 there fore ans is 3 option c

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1Perfect man! Thanks a ton. @Raja99

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0@saifoo.khan what math is this?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1@lgbasallote : SAT.

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0correct me if im wrong but isnt SAT..uhmm a test?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1Scholastic Aptitude "Test" @lgbasallote
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