saifoo.khan
  • saifoo.khan
Questions coming..
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
saifoo.khan
  • saifoo.khan
1 Attachment
anonymous
  • anonymous
awe some introduction waiting for it!
anonymous
  • anonymous
7 th thats 1st one

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

FoolAroundMath
  • FoolAroundMath
\(\tau(5)=2, \tau(7) = 2, \tau(12)=6,\tau(35)=4, \tau(6)=4, \tau(4)=3 \) So, for Q7. \(I, II\) are correct. For Q8, \(\tau (\tau (\tau(12))) = \tau(\tau(6)) = \tau(4) = 3\)
saifoo.khan
  • saifoo.khan
@FoolAroundMath , can you please explain what you wrote?
anonymous
  • anonymous
ques 8 thats 4
anonymous
  • anonymous
its 3 at question 8....
saifoo.khan
  • saifoo.khan
@FoolAroundMath ??
wasiqss
  • wasiqss
saif bhai i told you is type k questions nahi aye gai
anonymous
  • anonymous
first calculate the divisors for each of the no shown.... Divisors of 5: 1, 5 Divisors of 7: 1, 7 Divisors of 35: 1, 5, 7, 35 Divisors of 12: 1, 2, 3, 4, 6, 12 Divisors of 6: 1, 2, 3, 6
saifoo.khan
  • saifoo.khan
@wasiqss ; hehe. This is SAT 1.
anonymous
  • anonymous
and then count the no of divisors for each one then the ans by @FoolAroundMath follows
wasiqss
  • wasiqss
ohhh saif sat giving?
saifoo.khan
  • saifoo.khan
@wasiqss ; Most probably.
wasiqss
  • wasiqss
cool~
anonymous
  • anonymous
for \[\large n=\prod_{k=1}^{m} p_{k}^{\alpha_{k}} \\ \tau(n)=(1+\alpha_{1})(1+\alpha_{2})...(1+\alpha_{m})\] for example \[12=2^2*3^1 \\ \tau(12)=(2+1)(1+1)=6\]
saifoo.khan
  • saifoo.khan
@mukushla ; Sorry i don't get it . :D
anonymous
  • anonymous
no problem
saifoo.khan
  • saifoo.khan
@Raja99 , okay i get till the divisor thing.. what's next?
anonymous
  • anonymous
is it a way to fing the divisors @mukushla
anonymous
  • anonymous
then the value of the tau(5)=no of divisors of 5(Pl count it) and subsitute to chk the conditions.
anonymous
  • anonymous
for tau(5)=2 and tau(7)=2 and tau(35)=4 like that
anonymous
  • anonymous
and chk 2*2=4 then option is true...
saifoo.khan
  • saifoo.khan
Ah, nice., so; 1. 2 = 2 2. 2*2 = 4 3. 2+2 =/= 6 Perfect.
FoolAroundMath
  • FoolAroundMath
I was typing the whole thing out when OS crashed again. I'll leave it to the others to do that then ;)
saifoo.khan
  • saifoo.khan
@FoolAroundMath , Oh. okay. No Problem. (:
saifoo.khan
  • saifoo.khan
@Raja99 : Moving on to Question 8?
anonymous
  • anonymous
Divisors of 12: 1, 2, 3, 4, 6, 12 Divisors of 6: 1, 2, 3, 6 Divisors of 4: 1, 2, 4 ok then tau(12)=6 then tau(6)=4 then tau(4)=3 there fore ans is 3 option c
saifoo.khan
  • saifoo.khan
Perfect man! Thanks a ton. @Raja99
lgbasallote
  • lgbasallote
@saifoo.khan what math is this?
saifoo.khan
  • saifoo.khan
@lgbasallote : SAT.
anonymous
  • anonymous
sat?@saifoo.khan
lgbasallote
  • lgbasallote
correct me if im wrong but isnt SAT..uhmm a test?
saifoo.khan
  • saifoo.khan
http://en.wikipedia.org/wiki/SAT
saifoo.khan
  • saifoo.khan
Scholastic Aptitude "Test" @lgbasallote
lgbasallote
  • lgbasallote
ohh
anonymous
  • anonymous
umm

Looking for something else?

Not the answer you are looking for? Search for more explanations.