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saifoo.khan Group Title

Questions coming..

  • 2 years ago
  • 2 years ago

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  1. saifoo.khan Group Title
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    • 2 years ago
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  2. Raja99 Group Title
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    awe some introduction waiting for it!

    • 2 years ago
  3. Rohangrr Group Title
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    7 th thats 1st one

    • 2 years ago
  4. FoolAroundMath Group Title
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    \(\tau(5)=2, \tau(7) = 2, \tau(12)=6,\tau(35)=4, \tau(6)=4, \tau(4)=3 \) So, for Q7. \(I, II\) are correct. For Q8, \(\tau (\tau (\tau(12))) = \tau(\tau(6)) = \tau(4) = 3\)

    • 2 years ago
  5. saifoo.khan Group Title
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    @FoolAroundMath , can you please explain what you wrote?

    • 2 years ago
  6. Rohangrr Group Title
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    ques 8 thats 4

    • 2 years ago
  7. anonymoustwo44 Group Title
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    its 3 at question 8....

    • 2 years ago
  8. saifoo.khan Group Title
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    @FoolAroundMath ??

    • 2 years ago
  9. wasiqss Group Title
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    saif bhai i told you is type k questions nahi aye gai

    • 2 years ago
  10. Raja99 Group Title
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    first calculate the divisors for each of the no shown.... Divisors of 5: 1, 5 Divisors of 7: 1, 7 Divisors of 35: 1, 5, 7, 35 Divisors of 12: 1, 2, 3, 4, 6, 12 Divisors of 6: 1, 2, 3, 6

    • 2 years ago
  11. saifoo.khan Group Title
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    @wasiqss ; hehe. This is SAT 1.

    • 2 years ago
  12. Raja99 Group Title
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    and then count the no of divisors for each one then the ans by @FoolAroundMath follows

    • 2 years ago
  13. wasiqss Group Title
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    ohhh saif sat giving?

    • 2 years ago
  14. saifoo.khan Group Title
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    @wasiqss ; Most probably.

    • 2 years ago
  15. wasiqss Group Title
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    cool~

    • 2 years ago
  16. mukushla Group Title
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    for \[\large n=\prod_{k=1}^{m} p_{k}^{\alpha_{k}} \\ \tau(n)=(1+\alpha_{1})(1+\alpha_{2})...(1+\alpha_{m})\] for example \[12=2^2*3^1 \\ \tau(12)=(2+1)(1+1)=6\]

    • 2 years ago
  17. saifoo.khan Group Title
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    @mukushla ; Sorry i don't get it . :D

    • 2 years ago
  18. mukushla Group Title
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    no problem

    • 2 years ago
  19. saifoo.khan Group Title
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    @Raja99 , okay i get till the divisor thing.. what's next?

    • 2 years ago
  20. Raja99 Group Title
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    is it a way to fing the divisors @mukushla

    • 2 years ago
  21. Raja99 Group Title
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    then the value of the tau(5)=no of divisors of 5(Pl count it) and subsitute to chk the conditions.

    • 2 years ago
  22. Raja99 Group Title
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    for tau(5)=2 and tau(7)=2 and tau(35)=4 like that

    • 2 years ago
  23. Raja99 Group Title
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    and chk 2*2=4 then option is true...

    • 2 years ago
  24. saifoo.khan Group Title
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    Ah, nice., so; 1. 2 = 2 2. 2*2 = 4 3. 2+2 =/= 6 Perfect.

    • 2 years ago
  25. FoolAroundMath Group Title
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    I was typing the whole thing out when OS crashed again. I'll leave it to the others to do that then ;)

    • 2 years ago
  26. saifoo.khan Group Title
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    @FoolAroundMath , Oh. okay. No Problem. (:

    • 2 years ago
  27. saifoo.khan Group Title
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    @Raja99 : Moving on to Question 8?

    • 2 years ago
  28. Raja99 Group Title
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    Divisors of 12: 1, 2, 3, 4, 6, 12 Divisors of 6: 1, 2, 3, 6 Divisors of 4: 1, 2, 4 ok then tau(12)=6 then tau(6)=4 then tau(4)=3 there fore ans is 3 option c

    • 2 years ago
  29. saifoo.khan Group Title
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    Perfect man! Thanks a ton. @Raja99

    • 2 years ago
  30. lgbasallote Group Title
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    @saifoo.khan what math is this?

    • 2 years ago
  31. saifoo.khan Group Title
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    @lgbasallote : SAT.

    • 2 years ago
  32. Raja99 Group Title
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    sat?@saifoo.khan

    • 2 years ago
  33. lgbasallote Group Title
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    correct me if im wrong but isnt SAT..uhmm a test?

    • 2 years ago
  34. saifoo.khan Group Title
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    http://en.wikipedia.org/wiki/SAT

    • 2 years ago
  35. saifoo.khan Group Title
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    Scholastic Aptitude "Test" @lgbasallote

    • 2 years ago
  36. lgbasallote Group Title
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    ohh

    • 2 years ago
  37. Raja99 Group Title
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    umm

    • 2 years ago
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