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Rohangrr
 2 years ago
Best ResponseYou've already chosen the best response.3Arithmetic formula: \[ t_n = t_1 + (n  1)d \] \[t_n \] is the nth term, \[t_1 \] is the first term, and d is the common difference

Rohangrr
 2 years ago
Best ResponseYou've already chosen the best response.3Geometric formula: \[ t_n = t_1 . r^(n  1) \] \[t_n \] is the nth term, \[t_1 \] is the first term, and r is the common ratio.

Rohangrr
 2 years ago
Best ResponseYou've already chosen the best response.3Did you get the concept @kenneyfamily

shruti
 2 years ago
Best ResponseYou've already chosen the best response.1Arithmetic sequences have a constant difference between terms: 1, 3, 5, 7,... The difference between successive terms is 2. The general formula for the nth term is a(n) = a(1) + d·(n1) where a(1) = the initial term , d = difference between terms. So to find the 5th term (which we can see in the sequence should be 9), we plug in n = 5 a(5) = 1 + 2·(51) = 1+2·4 = 9 WHEREAS Geometric sequences have a constant ratio between terms: 2, 6, 18, 54, ... The ratio between successive terms is 3. The general formula for the nth term is a(n) = a(1)·r^(n1), where a(1) is the first term and r is the ratio. So to find the 5th term (which we can see in the sequence should be 162), we plug in n = 5 EXAMPLE.. a(5) = 2·3^(51) = 2·3^4 = 2·81 = 162

angela210793
 2 years ago
Best ResponseYou've already chosen the best response.1arithmetic sequence is a sequence of numbers such tht the difference of two condegutive numbers is a constantdw:1341738867627:dw geometirc sequence is a sequence of numbers such tht the quotient between two consegutive numbers is a constantdw:1341739044301:dw

Rohangrr
 2 years ago
Best ResponseYou've already chosen the best response.3if more Arithmetic sequences have a constant difference between terms: 1, 3, 5, 7,... The difference between successive terms is 2. The general formula for the nth term is a(n) = a(1) + d·(n1) where a(1) = the initial term, d = difference between terms. So to find the 5th term (which we can see in the sequence should be 9), we plug in n = 5 a(5) = 1 + 2·(51) = 1+2·4 = 9 Geometric sequences have a constant ratio between terms: 2, 6, 18, 54, ... The ratio between successive terms is 3. The general formula for the nth term is a(n) = a(1)·r^(n1), where a(1) is the first term and r is the ratio. So to find the 5th term (which we can see in the sequence should be 162), we plug in n = 5 a(5) = 2·3^(51) = 2·3^4 = 2·81 = 162

kenneyfamily
 2 years ago
Best ResponseYou've already chosen the best response.0AWESOME GUYS...THANK YOU SO MUCH!!! :)

angela210793
 2 years ago
Best ResponseYou've already chosen the best response.1did u guys copy=pasted the same thing O.o

TransendentialPI
 2 years ago
Best ResponseYou've already chosen the best response.0Two videos worth watching: http://patrickjmt.com/quickintrotoarithmeticsequences/ http://patrickjmt.com/aquickintrotogeometricsequences/
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