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kenneyfamily

  • 3 years ago

What is the difference between an arithmetic and geometric sequence?

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  1. Rohangrr
    • 3 years ago
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    Arithmetic formula: \[ t_n = t_1 + (n - 1)d \] \[t_n \] is the nth term, \[t_1 \] is the first term, and d is the common difference

  2. Rohangrr
    • 3 years ago
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    Geometric formula: \[ t_n = t_1 . r^(n - 1) \] \[t_n \] is the nth term, \[t_1 \] is the first term, and r is the common ratio.

  3. Rohangrr
    • 3 years ago
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    Did you get the concept @kenneyfamily

  4. kenneyfamily
    • 3 years ago
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    yes!

  5. shruti
    • 3 years ago
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    Arithmetic sequences have a constant difference between terms: 1, 3, 5, 7,... The difference between successive terms is 2. The general formula for the nth term is a(n) = a(1) + d·(n-1) where a(1) = the initial term , d = difference between terms. So to find the 5th term (which we can see in the sequence should be 9), we plug in n = 5 a(5) = 1 + 2·(5-1) = 1+2·4 = 9 WHEREAS Geometric sequences have a constant ratio between terms: 2, 6, 18, 54, ... The ratio between successive terms is 3. The general formula for the nth term is a(n) = a(1)·r^(n-1), where a(1) is the first term and r is the ratio. So to find the 5th term (which we can see in the sequence should be 162), we plug in n = 5 EXAMPLE.. a(5) = 2·3^(5-1) = 2·3^4 = 2·81 = 162

  6. angela210793
    • 3 years ago
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    arithmetic sequence is a sequence of numbers such tht the difference of two condegutive numbers is a constant|dw:1341738867627:dw| geometirc sequence is a sequence of numbers such tht the quotient between two consegutive numbers is a constant|dw:1341739044301:dw|

  7. Rohangrr
    • 3 years ago
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    if more Arithmetic sequences have a constant difference between terms: 1, 3, 5, 7,... The difference between successive terms is 2. The general formula for the nth term is a(n) = a(1) + d·(n-1) where a(1) = the initial term, d = difference between terms. So to find the 5th term (which we can see in the sequence should be 9), we plug in n = 5 a(5) = 1 + 2·(5-1) = 1+2·4 = 9 Geometric sequences have a constant ratio between terms: 2, 6, 18, 54, ... The ratio between successive terms is 3. The general formula for the nth term is a(n) = a(1)·r^(n-1), where a(1) is the first term and r is the ratio. So to find the 5th term (which we can see in the sequence should be 162), we plug in n = 5 a(5) = 2·3^(5-1) = 2·3^4 = 2·81 = 162

  8. kenneyfamily
    • 3 years ago
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    AWESOME GUYS...THANK YOU SO MUCH!!! :)

  9. angela210793
    • 3 years ago
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    did u guys copy=pasted the same thing O.o

  10. TransendentialPI
    • 3 years ago
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    Two videos worth watching: http://patrickjmt.com/quick-intro-to-arithmetic-sequences/ http://patrickjmt.com/a-quick-intro-to-geometric-sequences/

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