moongazer
  • moongazer
If tan (theta) =5/4 and cos (theta) < 0 . Find the other trig. functions. Could someone check my answers?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
moongazer
  • moongazer
am I right that theta is in quadrant 3 ?
anonymous
  • anonymous
Yup, so Sin (theta) < 0 as well
moongazer
  • moongazer
Could you show your answers so that I can check my answers?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
No.. you should give your answers so that we can check.. Go ahead..
moongazer
  • moongazer
ok
moongazer
  • moongazer
\[\sin \theta =(-5\sqrt{41})/41\] \[\cos \theta = (-4\sqrt{41})/41\] \[\tan \theta = 5/4\] \[\csc \theta = -\sqrt{41}/5\] \[\sec \theta =-\sqrt{41}/4\] \[\cot \theta = 4/5\]
moongazer
  • moongazer
Am I correct?
anonymous
  • anonymous
|dw:1341743660142:dw| Just remember "All Science Teachers Crazy" so in the first quad all trig functions are positive, in the 2nd all Sine functions are positive, in the 3rd all Tangent functions are positive so in the 4th all Cosine functions are positive.
moongazer
  • moongazer
Are all my answers correct?
moongazer
  • moongazer
Could someone check it?
moongazer
  • moongazer
@mathslover Are my answers correct?
mathslover
  • mathslover
when cos theta is negative then theta lies in 2nd quadrant ..
moongazer
  • moongazer
@mathslover why?
mathslover
  • mathslover
please wait
moongazer
  • moongazer
ok thanks :)
mathslover
  • mathslover
Remember this :Quadrant 1: Cosine is positive and Sine is positive. (x > 0 ; y > 0) just as ( cos(theta) > 0 ; sin(theta) > 0) Quadrant 2: Cosine is negative and Sine is positive. (x < 0; y > 0) just as ( cos(theta) < 0 ; sin(theta) > 0) Quadrant 3: Cosine is negative and Sine is negative. (x < 0 ; y < 0) just as ( cos(theta) < 0 ; sin(theta)< 0) Quadrant 4: Cosine is positive and Sine is negative. ( x > 0 ; y < 0 ) just as ( cos(theta) > 0 ; sin(theta) < 0)
mathslover
  • mathslover
@moongazer
moongazer
  • moongazer
I am here
mathslover
  • mathslover
So did u get that quadrant 2 : cos theta is negative ?
moongazer
  • moongazer
i'm still reading it :)
mathslover
  • mathslover
Take ur time
moongazer
  • moongazer
But in quadrant 3 cos theta is also negative so why I can't choose it as the location of theta?
moongazer
  • moongazer
isn't it that tan theta is positive in quadrant 3 and according to the given tan theta is positive. So choosing that theta is in quadrant 3 is better?
mathslover
  • mathslover
oh yes u r also right but i am not perfect in this topic may be @lalaly do it for u
moongazer
  • moongazer
@lalaly My answers are correct right?
lalaly
  • lalaly
u can describe this as a right triangle \[\tan (\theta)=\frac{opposite}{adjacent}=\frac{5}{4}\]so from this u know that opposite=5 and adjacent =4 |dw:1341746704835:dw|
lalaly
  • lalaly
now use those values to find the ratios for the other trig functions
moongazer
  • moongazer
But isn't it I can also view as|dw:1341747710304:dw|
moongazer
  • moongazer
Are my answers right or wrong?
ash2326
  • ash2326
@moongazer you are correct :D
moongazer
  • moongazer
@ash2326 Thanks for that!
ash2326
  • ash2326
you wanna see, the pic I made to check this?
moongazer
  • moongazer
ok, let me see it :)
ash2326
  • ash2326
here it is
1 Attachment
moongazer
  • moongazer
That is also what I am thinking :)
ash2326
  • ash2326
Yay:D

Looking for something else?

Not the answer you are looking for? Search for more explanations.