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virtus

find the equation of the locus of a point that moves so that it is always 5 units from (-1,3). Describe the shape of this locus.

  • one year ago
  • one year ago

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  1. ganeshie8
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    Lets call that point P (x, y)

    • one year ago
  2. ganeshie8
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    distance from (-1, 3) to P(x, y) is always 5

    • one year ago
  3. ganeshie8
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    you know the distance formula ?

    • one year ago
  4. virtus
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    yes

    • one year ago
  5. ganeshie8
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    Okay good. distance between (-1, 3) and P(x, y) : \(\sqrt{(x2-x1)^2+(y2-y1)^2}\) = 5 \(\sqrt{(x-(-1))^2+(y-3)^2}\) = 5 \(\sqrt{(x+1)^2+(y-3)^2}\) = 5 squating on both sides, \((x+1)^2+(y-3)^2\) = 25

    • one year ago
  6. Ron.mystery
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    POINTS TO REMEMBER: A locus or curve is the set of points and only those points satisfying a given condition or a well defined property. This is the locus definition in geometry. Example of locus is provided below: (1) A,B are two fixed points. Let a set of points equidistant from A and B. Locus is the perpendicular bisector of AB . Every point on the perpendicular bisector of AB obeys the condition. (2) The locus of a set of points which are at a constant distance from a fixed point,is a circle.

    • one year ago
  7. ganeshie8
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    @virtus thats our locus equation.

    • one year ago
  8. ganeshie8
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    can you tell... what shape it can be ?

    • one year ago
  9. virtus
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    THANK YOU SO MUCH GANESHIE8 ! =D

    • one year ago
  10. ganeshie8
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    i dont think, from equation its shape is obvious... we need to know about circle to be able to visualize the shape. np :)

    • one year ago
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