Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 1 viewing
Lecture 3: Problem solving. When professor Guttag talked about bisection search at about 41 minutes. He said the number of guesses of the square root of 12345 is 26. And then he said something about the size of the search space, which is roughly 12345 divided 0.01 square. and the answer is 26.89.... Can someone explain this formula to me? because I can't get the answer. Is it 12345/(0.01**2) or (12345/0.01)**2?
 one year ago
 one year ago
Lecture 3: Problem solving. When professor Guttag talked about bisection search at about 41 minutes. He said the number of guesses of the square root of 12345 is 26. And then he said something about the size of the search space, which is roughly 12345 divided 0.01 square. and the answer is 26.89.... Can someone explain this formula to me? because I can't get the answer. Is it 12345/(0.01**2) or (12345/0.01)**2?
 one year ago
 one year ago

This Question is Open

MakaiMcClintockBest ResponseYou've already chosen the best response.1
The formula is not the important point, rather the concept that bisection search can make programs much faster is. :)
 one year ago

WeltgeistBest ResponseYou've already chosen the best response.1
the maximum (and probably approximate) number of guesses is log base 2 of the search field which makes sense intuitively if you think about what log2 is:)
 one year ago

guilloBest ResponseYou've already chosen the best response.1
The value obtained by teacher results from log base 2 of (12345 / (0.01 ** 2)) import math aa = ( 12345 / (0.01 ** 2) ) bb = math.log(aa,2) print (bb)
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.