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let that point be P (x, y)

distance from a point to a line = \(\frac{Ax+By+C}{\sqrt{A^2 + B^2}}\)

can you put the equation for distance ?
from point P(x, y) to line 3x-4y+9=0

oh so it would be (3x-4y+9)/square root( 3^2 +(-4)^2)

(3x -4y+9)/5 =5
3x -4y+9 =25
3x-4y -16 =0

is that right ganeshi8?

btw i thought there was an ABSOLUTE SIGN around Ax + By + C for the formula

yep! u r right.. we must get two lines

|(3x -4y+9)|/5 =5

3x-4y+9 = 25, and, 3x-4y + 9 = -25

ngawww i get it !

it tricked me.... i was thinking there should be two lines at the very end.
nice catch :)

lol fine i get it nw :))

|dw:1341791339629:dw|

two lines we just got... which are at a distance of 5 from the given line...
they look as above