log subscript 6 x + log6 (x-5)=2

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log subscript 6 x + log6 (x-5)=2

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Use The property : LogX+LogY=Log(x*Y) Can U do it now ?
not sure but ill try
Anyway ,Here is The Answer :: \[\Large Log_{6}x+Log_{6}(x-5)=2\] Using the Property that i posted : \[\Large Log_{6}(x*(x-5))=2\] Change it to Exponential: \[\Large 6^2=x^2-5x\] now factorize and solve it and get the value of x.

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lost
where ?
i multiplied the logs and got 0.6 put it in for x and the answers werent coming up
Did U follow My Steps ?
:/ yes

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