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sharee2012

  • 3 years ago

log subscript 6 x + log6 (x-5)=2

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  1. Eyad
    • 3 years ago
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    Use The property : LogX+LogY=Log(x*Y) Can U do it now ?

  2. sharee2012
    • 3 years ago
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    not sure but ill try

  3. Eyad
    • 3 years ago
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    Anyway ,Here is The Answer :: \[\Large Log_{6}x+Log_{6}(x-5)=2\] Using the Property that i posted : \[\Large Log_{6}(x*(x-5))=2\] Change it to Exponential: \[\Large 6^2=x^2-5x\] now factorize and solve it and get the value of x.

  4. sharee2012
    • 3 years ago
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    lost

  5. Eyad
    • 3 years ago
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    where ?

  6. sharee2012
    • 3 years ago
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    i multiplied the logs and got 0.6 put it in for x and the answers werent coming up

  7. Eyad
    • 3 years ago
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    Did U follow My Steps ?

  8. sharee2012
    • 3 years ago
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    :/ yes

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