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ranyai12

  • 3 years ago

Can someone please help me solve this problem!! Find | z| and Arg( z) for z=3/(4+2i) |z|= Arg(z)= (Recall −pi< Arg( z)<=pi )

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  1. hellow
    • 3 years ago
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    mod(z) or |z| is the distance of the line joining the (0,0) to z when z is drawn in the complex plane. Arg(z) is the angle from the positive x-axis to the ray from (0,0) to z in the complex plane. (Arg(z) is the principle angle, so it must be in the range you specified.) So z=3/(4+2i) = 3/(4+2i)*(4-2i)/(4-2i) = 3(4-2i)/(20) = 3(2-i)/10 = 3/5 - i3/10 Thus |z|= sqrt[(3/5)^2 + (-3/10)^2]. (You can simplify.) and Arg(z) =arctan[(-3/10)/(3/5)] = -pi/4

  2. ranyai12
    • 3 years ago
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    Thank you!!

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