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rtraylor3
 3 years ago
Find the measure please, I got 3 but it's wrong?
rtraylor3
 3 years ago
Find the measure please, I got 3 but it's wrong?

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eseidl
 3 years ago
Best ResponseYou've already chosen the best response.2find the measure of what?

rtraylor3
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry the area of triangle DEF

eseidl
 3 years ago
Best ResponseYou've already chosen the best response.2ok, so A=12 is the area of the first triangle

rtraylor3
 3 years ago
Best ResponseYou've already chosen the best response.1Yes. I went by the side of the first and second. The first was 4 and the second was 1 so I thought that the first triangle was 4 times greater than the second. 12/4=3

eseidl
 3 years ago
Best ResponseYou've already chosen the best response.2each side of the triangle on the right is scaled down by a factor of 1/4.

eseidl
 3 years ago
Best ResponseYou've already chosen the best response.2Area of a triangle is base*height/2 so,\[\frac{\left AC \right4*\sin A}{2}=12\]for the triangle on the left. The triangle on the right is:\[\frac{\left DF \right1*\sin D}{2}=?\]Sow the sides AC and DF are related. DF=(1/4)AC and the angles A and D (and therefore their sines) are equal. so, we can write the second equation above as:\[\frac{(1/4)\left AC \right1*\sin A}{2}=?\]comparing this with the first equation, we see that 2AC*sinA=12 and (1/8)AC*sinA=?. Now we see that the second equation is 1/16 of the first one. So the area of the second triangle must be 12/16=3/4

eseidl
 3 years ago
Best ResponseYou've already chosen the best response.2So, in summary, if one side of a triangle is scaled by a factor of x, then the area of the second triangle is x^2*area of the first.

eseidl
 3 years ago
Best ResponseYou've already chosen the best response.2where x=1/4 in this example.

rtraylor3
 3 years ago
Best ResponseYou've already chosen the best response.1Thanks so much!! I got it now!

eseidl
 3 years ago
Best ResponseYou've already chosen the best response.2and if you are scaling volumes, it is the same type of argument. Only now you use x^3 instead of x^2 because there is an extra dimension.
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