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eseidlBest ResponseYou've already chosen the best response.2
find the measure of what?
 one year ago

rtraylor3Best ResponseYou've already chosen the best response.1
Sorry the area of triangle DEF
 one year ago

eseidlBest ResponseYou've already chosen the best response.2
ok, so A=12 is the area of the first triangle
 one year ago

rtraylor3Best ResponseYou've already chosen the best response.1
Yes. I went by the side of the first and second. The first was 4 and the second was 1 so I thought that the first triangle was 4 times greater than the second. 12/4=3
 one year ago

eseidlBest ResponseYou've already chosen the best response.2
each side of the triangle on the right is scaled down by a factor of 1/4.
 one year ago

eseidlBest ResponseYou've already chosen the best response.2
Area of a triangle is base*height/2 so,\[\frac{\left AC \right4*\sin A}{2}=12\]for the triangle on the left. The triangle on the right is:\[\frac{\left DF \right1*\sin D}{2}=?\]Sow the sides AC and DF are related. DF=(1/4)AC and the angles A and D (and therefore their sines) are equal. so, we can write the second equation above as:\[\frac{(1/4)\left AC \right1*\sin A}{2}=?\]comparing this with the first equation, we see that 2AC*sinA=12 and (1/8)AC*sinA=?. Now we see that the second equation is 1/16 of the first one. So the area of the second triangle must be 12/16=3/4
 one year ago

eseidlBest ResponseYou've already chosen the best response.2
So, in summary, if one side of a triangle is scaled by a factor of x, then the area of the second triangle is x^2*area of the first.
 one year ago

eseidlBest ResponseYou've already chosen the best response.2
where x=1/4 in this example.
 one year ago

rtraylor3Best ResponseYou've already chosen the best response.1
Thanks so much!! I got it now!
 one year ago

eseidlBest ResponseYou've already chosen the best response.2
and if you are scaling volumes, it is the same type of argument. Only now you use x^3 instead of x^2 because there is an extra dimension.
 one year ago
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