## moongazer 3 years ago question below :)

1. moongazer

|dw:1341855893671:dw|

2. moongazer

@myininaya could you help me ?

3. moongazer

|dw:1341856207758:dw|

4. Wired

$\LARGE{\frac{\sqrt{(95t)^{3}}}{\sqrt[3]{(27s^{3}t^{-4}}){^2}}*(\frac{3s^{-2}}{4\sqrt[3]{t}})^{-1}}$ Hard to read, but is that the equation?

5. moongazer

No, The 5 there should be s

6. moongazer

did you get it?

7. Wired

Both s's?

8. moongazer

$\sqrt{(9st)^3}$

9. Wired

Is this correct? $\LARGE{\frac{\sqrt{(9st)^{3}}}{\sqrt[3]{(27s^{3}t^{-4}}){^2}}*(\frac{3s^{-2}}{4\sqrt[3]{t}})^{-1}}$

10. moongazer

yup :)

11. moongazer

could you help me? because I think I am getting the wrong answer

12. Wired

Blah, gotta use pen and paper for this one lol, getting some crazy answer.

13. moongazer

My teacher always gives us crazy equations :)

14. Wired

$\LARGE{(\frac{3s^{-2}}{4\sqrt[3]{t}})^{-1} = \frac{(3s^{-2})^{-1}}{(4\sqrt[3]{t})^{-1}}} = \frac{4\sqrt[3]{t}}{3s^{-2}} = \frac{4s^{2}\sqrt[3]{t}}{3}$

15. Wired

$\Large{\sqrt{(9st)^{3}} = \sqrt{(9st)^{2}*(9st)} = 9st*\sqrt{9st}}$

16. moongazer

I understand it, please continue :)

17. Wired

$\Large{\sqrt[3]{(27s^{3}t^{-4})^{-2}} = \sqrt[3]{\frac{1}{(27s^{3}t^{-4})^{2}}}}$ Ack, gotta go!

18. moongazer

just continue it tomorrow if you want to :) what answer did you get ?

19. Wired

Didn't, that's all I did so far. Does it match up with what you have?

20. moongazer

I did another method tonight. But I already did that kind of method although but I didn't finish answering it. I'll just try answering this with that kind of way and the other way so I can check my answers :)

21. ganeshie8

final answer i am getting as : $$4st^4\sqrt{st}$$

22. Wired

$\Large{\sqrt[3]{\frac{1}{27^{2}(s^{3})^{2}(t^{-4})^{2}}} = \sqrt[3]{\frac{t^{8}}{9^{3}(s^{2})^{3}}} = \frac{t^{2}}{9s^{2}}\sqrt[3]{t^{2}}}$

23. Wired

$\LARGE{\frac{9st*\sqrt{9st}}{\frac{t^{2}}{9s^{2}}*\sqrt[3]{t^{2}}}*\frac{4s^{2}\sqrt[3]{t}}{3}} = \LARGE{\frac{108s^{5}\sqrt{9st}}{t\sqrt[3]{t}}}$ No idea if that's right or not. Didn't check every step.