## moongazer Group Title question below :) 2 years ago 2 years ago

1. moongazer Group Title

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2. moongazer Group Title

@myininaya could you help me ?

3. moongazer Group Title

|dw:1341856207758:dw|

4. Wired Group Title

$\LARGE{\frac{\sqrt{(95t)^{3}}}{\sqrt[3]{(27s^{3}t^{-4}}){^2}}*(\frac{3s^{-2}}{4\sqrt[3]{t}})^{-1}}$ Hard to read, but is that the equation?

5. moongazer Group Title

No, The 5 there should be s

6. moongazer Group Title

did you get it?

7. Wired Group Title

Both s's?

8. moongazer Group Title

$\sqrt{(9st)^3}$

9. Wired Group Title

Is this correct? $\LARGE{\frac{\sqrt{(9st)^{3}}}{\sqrt[3]{(27s^{3}t^{-4}}){^2}}*(\frac{3s^{-2}}{4\sqrt[3]{t}})^{-1}}$

10. moongazer Group Title

yup :)

11. moongazer Group Title

could you help me? because I think I am getting the wrong answer

12. Wired Group Title

Blah, gotta use pen and paper for this one lol, getting some crazy answer.

13. moongazer Group Title

My teacher always gives us crazy equations :)

14. Wired Group Title

$\LARGE{(\frac{3s^{-2}}{4\sqrt[3]{t}})^{-1} = \frac{(3s^{-2})^{-1}}{(4\sqrt[3]{t})^{-1}}} = \frac{4\sqrt[3]{t}}{3s^{-2}} = \frac{4s^{2}\sqrt[3]{t}}{3}$

15. Wired Group Title

$\Large{\sqrt{(9st)^{3}} = \sqrt{(9st)^{2}*(9st)} = 9st*\sqrt{9st}}$

16. moongazer Group Title

I understand it, please continue :)

17. Wired Group Title

$\Large{\sqrt[3]{(27s^{3}t^{-4})^{-2}} = \sqrt[3]{\frac{1}{(27s^{3}t^{-4})^{2}}}}$ Ack, gotta go!

18. moongazer Group Title

just continue it tomorrow if you want to :) what answer did you get ?

19. Wired Group Title

Didn't, that's all I did so far. Does it match up with what you have?

20. moongazer Group Title

I did another method tonight. But I already did that kind of method although but I didn't finish answering it. I'll just try answering this with that kind of way and the other way so I can check my answers :)

21. ganeshie8 Group Title

final answer i am getting as : $$4st^4\sqrt{st}$$

22. Wired Group Title

$\Large{\sqrt[3]{\frac{1}{27^{2}(s^{3})^{2}(t^{-4})^{2}}} = \sqrt[3]{\frac{t^{8}}{9^{3}(s^{2})^{3}}} = \frac{t^{2}}{9s^{2}}\sqrt[3]{t^{2}}}$

23. Wired Group Title

$\LARGE{\frac{9st*\sqrt{9st}}{\frac{t^{2}}{9s^{2}}*\sqrt[3]{t^{2}}}*\frac{4s^{2}\sqrt[3]{t}}{3}} = \LARGE{\frac{108s^{5}\sqrt{9st}}{t\sqrt[3]{t}}}$ No idea if that's right or not. Didn't check every step.