A community for students.
Here's the question you clicked on:
 0 viewing
moongazer
 3 years ago
question below :)
moongazer
 3 years ago
question below :)

This Question is Closed

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1341855893671:dw

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.0@myininaya could you help me ?

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1341856207758:dw

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1\[\LARGE{\frac{\sqrt{(95t)^{3}}}{\sqrt[3]{(27s^{3}t^{4}}){^2}}*(\frac{3s^{2}}{4\sqrt[3]{t}})^{1}}\] Hard to read, but is that the equation?

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.0No, The 5 there should be s

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1Is this correct? \[\LARGE{\frac{\sqrt{(9st)^{3}}}{\sqrt[3]{(27s^{3}t^{4}}){^2}}*(\frac{3s^{2}}{4\sqrt[3]{t}})^{1}} \]

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.0could you help me? because I think I am getting the wrong answer

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1Blah, gotta use pen and paper for this one lol, getting some crazy answer.

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.0My teacher always gives us crazy equations :)

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1\[\LARGE{(\frac{3s^{2}}{4\sqrt[3]{t}})^{1} = \frac{(3s^{2})^{1}}{(4\sqrt[3]{t})^{1}}} = \frac{4\sqrt[3]{t}}{3s^{2}} = \frac{4s^{2}\sqrt[3]{t}}{3} \]

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1\[\Large{\sqrt{(9st)^{3}} = \sqrt{(9st)^{2}*(9st)} = 9st*\sqrt{9st}}\]

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.0I understand it, please continue :)

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1\[\Large{\sqrt[3]{(27s^{3}t^{4})^{2}} = \sqrt[3]{\frac{1}{(27s^{3}t^{4})^{2}}}}\] Ack, gotta go!

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.0just continue it tomorrow if you want to :) what answer did you get ?

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1Didn't, that's all I did so far. Does it match up with what you have?

moongazer
 3 years ago
Best ResponseYou've already chosen the best response.0I did another method tonight. But I already did that kind of method although but I didn't finish answering it. I'll just try answering this with that kind of way and the other way so I can check my answers :)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0final answer i am getting as : \(4st^4\sqrt{st}\)

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1\[\Large{\sqrt[3]{\frac{1}{27^{2}(s^{3})^{2}(t^{4})^{2}}} = \sqrt[3]{\frac{t^{8}}{9^{3}(s^{2})^{3}}} = \frac{t^{2}}{9s^{2}}\sqrt[3]{t^{2}}}\]

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1\[\LARGE{\frac{9st*\sqrt{9st}}{\frac{t^{2}}{9s^{2}}*\sqrt[3]{t^{2}}}*\frac{4s^{2}\sqrt[3]{t}}{3}} = \LARGE{\frac{108s^{5}\sqrt{9st}}{t\sqrt[3]{t}}}\] No idea if that's right or not. Didn't check every step.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.