moongazer
  • moongazer
question below :)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
moongazer
  • moongazer
|dw:1341855893671:dw|
moongazer
  • moongazer
@myininaya could you help me ?
moongazer
  • moongazer
|dw:1341856207758:dw|

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More answers

anonymous
  • anonymous
\[\LARGE{\frac{\sqrt{(95t)^{3}}}{\sqrt[3]{(27s^{3}t^{-4}}){^2}}*(\frac{3s^{-2}}{4\sqrt[3]{t}})^{-1}}\] Hard to read, but is that the equation?
moongazer
  • moongazer
No, The 5 there should be s
moongazer
  • moongazer
did you get it?
anonymous
  • anonymous
Both s's?
moongazer
  • moongazer
\[\sqrt{(9st)^3}\]
anonymous
  • anonymous
Is this correct? \[\LARGE{\frac{\sqrt{(9st)^{3}}}{\sqrt[3]{(27s^{3}t^{-4}}){^2}}*(\frac{3s^{-2}}{4\sqrt[3]{t}})^{-1}} \]
moongazer
  • moongazer
yup :)
moongazer
  • moongazer
could you help me? because I think I am getting the wrong answer
anonymous
  • anonymous
Blah, gotta use pen and paper for this one lol, getting some crazy answer.
moongazer
  • moongazer
My teacher always gives us crazy equations :)
anonymous
  • anonymous
\[\LARGE{(\frac{3s^{-2}}{4\sqrt[3]{t}})^{-1} = \frac{(3s^{-2})^{-1}}{(4\sqrt[3]{t})^{-1}}} = \frac{4\sqrt[3]{t}}{3s^{-2}} = \frac{4s^{2}\sqrt[3]{t}}{3} \]
anonymous
  • anonymous
\[\Large{\sqrt{(9st)^{3}} = \sqrt{(9st)^{2}*(9st)} = 9st*\sqrt{9st}}\]
moongazer
  • moongazer
I understand it, please continue :)
anonymous
  • anonymous
\[\Large{\sqrt[3]{(27s^{3}t^{-4})^{-2}} = \sqrt[3]{\frac{1}{(27s^{3}t^{-4})^{2}}}}\] Ack, gotta go!
moongazer
  • moongazer
just continue it tomorrow if you want to :) what answer did you get ?
anonymous
  • anonymous
Didn't, that's all I did so far. Does it match up with what you have?
moongazer
  • moongazer
I did another method tonight. But I already did that kind of method although but I didn't finish answering it. I'll just try answering this with that kind of way and the other way so I can check my answers :)
ganeshie8
  • ganeshie8
final answer i am getting as : \(4st^4\sqrt{st}\)
anonymous
  • anonymous
\[\Large{\sqrt[3]{\frac{1}{27^{2}(s^{3})^{2}(t^{-4})^{2}}} = \sqrt[3]{\frac{t^{8}}{9^{3}(s^{2})^{3}}} = \frac{t^{2}}{9s^{2}}\sqrt[3]{t^{2}}}\]
anonymous
  • anonymous
\[\LARGE{\frac{9st*\sqrt{9st}}{\frac{t^{2}}{9s^{2}}*\sqrt[3]{t^{2}}}*\frac{4s^{2}\sqrt[3]{t}}{3}} = \LARGE{\frac{108s^{5}\sqrt{9st}}{t\sqrt[3]{t}}}\] No idea if that's right or not. Didn't check every step.

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