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uri Group Title

In figure 1if sin theta =0.5,what is the length of BC?

  • 2 years ago
  • 2 years ago

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  1. uri Group Title
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    |dw:1341857013568:dw|

    • 2 years ago
  2. saifoo.khan Group Title
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    sin theta = opp/hypotenuse

    • 2 years ago
  3. Diyadiya Group Title
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    \[\sin \theta= \frac{opposite~side}{hypotenuse}\]

    • 2 years ago
  4. saifoo.khan Group Title
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    \[\sin (0.5) = \frac{1}{AB}\]Solve.

    • 2 years ago
  5. uri Group Title
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    I don't want the length of AB,I want the length of BC! @saifoo.khan

    • 2 years ago
  6. saifoo.khan Group Title
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    After you have AB, use Pythagoras to find it.

    • 2 years ago
  7. uri Group Title
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    if i get the value of theeta like theeta =arcsin(1/2) then i use tan theeta to find it how will i do it then @saifoo.khan

    • 2 years ago
  8. saifoo.khan Group Title
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    Look, sin x = opp/hyp. and you are given sin x = 1/2 This means that opp is 1 and hyp is 2.

    • 2 years ago
  9. saifoo.khan Group Title
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    Agree?

    • 2 years ago
  10. saifoo.khan Group Title
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    Now: b^2 + p^2 = h^2 1^2 + p^2 = 2^2 you will get p.

    • 2 years ago
  11. uri Group Title
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    \[\tan \Theta = perpendicular \div base \]

    • 2 years ago
  12. uri Group Title
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    |dw:1341858263323:dw|

    • 2 years ago
  13. saifoo.khan Group Title
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    tan = opp/adj.

    • 2 years ago
  14. saifoo.khan Group Title
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    You said you have to do it directly. -_-

    • 2 years ago
  15. uri Group Title
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    |dw:1341858302889:dw|

    • 2 years ago
  16. uri Group Title
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    BC=1.73 answer right

    • 2 years ago
  17. saifoo.khan Group Title
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    1.83

    • 2 years ago
  18. uri Group Title
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    Wrong answer! :D i dont have this Option :) a)1.25 b)1.73 c)1.41 d)1.50

    • 2 years ago
  19. saifoo.khan Group Title
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    Ugh! let me check.

    • 2 years ago
  20. Diyadiya Group Title
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    1.73 is right :D

    • 2 years ago
  21. saifoo.khan Group Title
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    If diya says it's correct. Then i will go with her.

    • 2 years ago
  22. uri Group Title
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    huh? And when i said? :P

    • 2 years ago
  23. saifoo.khan Group Title
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    No, you were good for nothing.

    • 2 years ago
  24. saifoo.khan Group Title
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    Infact, you are good for nothing. :D

    • 2 years ago
  25. Diyadiya Group Title
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    Well, like @saifoo.khan said by pythagorus theorem 2^2 = BC^2 + 1^2 BC^2= 2^2-1^2 BC^2= 4-1=3 BC = \(\sqrt{3}\)=1.73

    • 2 years ago
  26. Diyadiya Group Title
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    :D

    • 2 years ago
  27. saifoo.khan Group Title
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    Perfect. so i must have made a tiny mistake.

    • 2 years ago
  28. uri Group Title
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    You did not know how to solve IT!! @saifoo.khan i tried to do! you should appreciate me..instead of degrading! :/

    • 2 years ago
  29. saifoo.khan Group Title
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    @uri , Okay. C'mon now.. Don't take things seriously. I was kidding..

    • 2 years ago
  30. saifoo.khan Group Title
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    @uri , i really appreciate your math solutions.. They are mind blowing..

    • 2 years ago
  31. uri Group Title
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    K.

    • 2 years ago
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