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  • uri

In figure 1if sin theta =0.5,what is the length of BC?

Mathematics
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  • uri
|dw:1341857013568:dw|
sin theta = opp/hypotenuse
\[\sin \theta= \frac{opposite~side}{hypotenuse}\]

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Other answers:

\[\sin (0.5) = \frac{1}{AB}\]Solve.
  • uri
I don't want the length of AB,I want the length of BC! @saifoo.khan
After you have AB, use Pythagoras to find it.
  • uri
if i get the value of theeta like theeta =arcsin(1/2) then i use tan theeta to find it how will i do it then @saifoo.khan
Look, sin x = opp/hyp. and you are given sin x = 1/2 This means that opp is 1 and hyp is 2.
Agree?
Now: b^2 + p^2 = h^2 1^2 + p^2 = 2^2 you will get p.
  • uri
\[\tan \Theta = perpendicular \div base \]
  • uri
|dw:1341858263323:dw|
tan = opp/adj.
You said you have to do it directly. -_-
  • uri
|dw:1341858302889:dw|
  • uri
BC=1.73 answer right
1.83
  • uri
Wrong answer! :D i dont have this Option :) a)1.25 b)1.73 c)1.41 d)1.50
Ugh! let me check.
1.73 is right :D
If diya says it's correct. Then i will go with her.
  • uri
huh? And when i said? :P
No, you were good for nothing.
Infact, you are good for nothing. :D
Well, like @saifoo.khan said by pythagorus theorem 2^2 = BC^2 + 1^2 BC^2= 2^2-1^2 BC^2= 4-1=3 BC = \(\sqrt{3}\)=1.73
:D
Perfect. so i must have made a tiny mistake.
  • uri
You did not know how to solve IT!! @saifoo.khan i tried to do! you should appreciate me..instead of degrading! :/
@uri , Okay. C'mon now.. Don't take things seriously. I was kidding..
@uri , i really appreciate your math solutions.. They are mind blowing..
  • uri
K.

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