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saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2sin theta = opp/hypotenuse

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sin \theta= \frac{opposite~side}{hypotenuse}\]

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2\[\sin (0.5) = \frac{1}{AB}\]Solve.

uri
 2 years ago
Best ResponseYou've already chosen the best response.0I don't want the length of AB,I want the length of BC! @saifoo.khan

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2After you have AB, use Pythagoras to find it.

uri
 2 years ago
Best ResponseYou've already chosen the best response.0if i get the value of theeta like theeta =arcsin(1/2) then i use tan theeta to find it how will i do it then @saifoo.khan

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2Look, sin x = opp/hyp. and you are given sin x = 1/2 This means that opp is 1 and hyp is 2.

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2Now: b^2 + p^2 = h^2 1^2 + p^2 = 2^2 you will get p.

uri
 2 years ago
Best ResponseYou've already chosen the best response.0\[\tan \Theta = perpendicular \div base \]

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2You said you have to do it directly. _

uri
 2 years ago
Best ResponseYou've already chosen the best response.0Wrong answer! :D i dont have this Option :) a)1.25 b)1.73 c)1.41 d)1.50

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2If diya says it's correct. Then i will go with her.

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2No, you were good for nothing.

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2Infact, you are good for nothing. :D

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.1Well, like @saifoo.khan said by pythagorus theorem 2^2 = BC^2 + 1^2 BC^2= 2^21^2 BC^2= 41=3 BC = \(\sqrt{3}\)=1.73

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2Perfect. so i must have made a tiny mistake.

uri
 2 years ago
Best ResponseYou've already chosen the best response.0You did not know how to solve IT!! @saifoo.khan i tried to do! you should appreciate me..instead of degrading! :/

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2@uri , Okay. C'mon now.. Don't take things seriously. I was kidding..

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.2@uri , i really appreciate your math solutions.. They are mind blowing..
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