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saifoo.khanBest ResponseYou've already chosen the best response.2
sin theta = opp/hypotenuse
 one year ago

DiyadiyaBest ResponseYou've already chosen the best response.1
\[\sin \theta= \frac{opposite~side}{hypotenuse}\]
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
\[\sin (0.5) = \frac{1}{AB}\]Solve.
 one year ago

uriBest ResponseYou've already chosen the best response.0
I don't want the length of AB,I want the length of BC! @saifoo.khan
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
After you have AB, use Pythagoras to find it.
 one year ago

uriBest ResponseYou've already chosen the best response.0
if i get the value of theeta like theeta =arcsin(1/2) then i use tan theeta to find it how will i do it then @saifoo.khan
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Look, sin x = opp/hyp. and you are given sin x = 1/2 This means that opp is 1 and hyp is 2.
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Now: b^2 + p^2 = h^2 1^2 + p^2 = 2^2 you will get p.
 one year ago

uriBest ResponseYou've already chosen the best response.0
\[\tan \Theta = perpendicular \div base \]
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
You said you have to do it directly. _
 one year ago

uriBest ResponseYou've already chosen the best response.0
Wrong answer! :D i dont have this Option :) a)1.25 b)1.73 c)1.41 d)1.50
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Ugh! let me check.
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
If diya says it's correct. Then i will go with her.
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
No, you were good for nothing.
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Infact, you are good for nothing. :D
 one year ago

DiyadiyaBest ResponseYou've already chosen the best response.1
Well, like @saifoo.khan said by pythagorus theorem 2^2 = BC^2 + 1^2 BC^2= 2^21^2 BC^2= 41=3 BC = \(\sqrt{3}\)=1.73
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
Perfect. so i must have made a tiny mistake.
 one year ago

uriBest ResponseYou've already chosen the best response.0
You did not know how to solve IT!! @saifoo.khan i tried to do! you should appreciate me..instead of degrading! :/
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
@uri , Okay. C'mon now.. Don't take things seriously. I was kidding..
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.2
@uri , i really appreciate your math solutions.. They are mind blowing..
 one year ago
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