uri
In figure 1if sin theta =0.5,what is the length of BC?



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uri
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dw:1341857013568:dw

saifoo.khan
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sin theta = opp/hypotenuse

Diyadiya
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\[\sin \theta= \frac{opposite~side}{hypotenuse}\]

saifoo.khan
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\[\sin (0.5) = \frac{1}{AB}\]Solve.

uri
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I don't want the length of AB,I want the length of BC! @saifoo.khan

saifoo.khan
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After you have AB, use Pythagoras to find it.

uri
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if i get the value of theeta like theeta =arcsin(1/2)
then i use tan theeta to find it how will i do it then
@saifoo.khan

saifoo.khan
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Look, sin x = opp/hyp.
and you are given sin x = 1/2
This means that opp is 1 and hyp is 2.

saifoo.khan
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Agree?

saifoo.khan
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Now:
b^2 + p^2 = h^2
1^2 + p^2 = 2^2
you will get p.

uri
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\[\tan \Theta = perpendicular \div base \]

uri
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dw:1341858263323:dw

saifoo.khan
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tan = opp/adj.

saifoo.khan
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You said you have to do it directly. _

uri
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dw:1341858302889:dw

uri
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BC=1.73 answer right

saifoo.khan
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1.83

uri
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Wrong answer! :D i dont have this Option :) a)1.25 b)1.73 c)1.41 d)1.50

saifoo.khan
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Ugh! let me check.

Diyadiya
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1.73 is right :D

saifoo.khan
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If diya says it's correct. Then i will go with her.

uri
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huh? And when i said? :P

saifoo.khan
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No, you were good for nothing.

saifoo.khan
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Infact, you are good for nothing. :D

Diyadiya
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Well, like @saifoo.khan said
by pythagorus theorem
2^2 = BC^2 + 1^2
BC^2= 2^21^2
BC^2= 41=3
BC = \(\sqrt{3}\)=1.73

Diyadiya
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:D

saifoo.khan
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Perfect. so i must have made a tiny mistake.

uri
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You did not know how to solve IT!! @saifoo.khan i tried to do! you should appreciate me..instead of degrading! :/

saifoo.khan
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@uri , Okay. C'mon now.. Don't take things seriously. I was kidding..

saifoo.khan
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@uri , i really appreciate your math solutions.. They are mind blowing..

uri
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K.