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Nick2019

Explain, in complete sentences, how you would use the two methods (distribution and box method) to find the product of (x – 2)(x – 3). Which method do you prefer and why?

  • one year ago
  • one year ago

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  1. jim_thompson5910
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    Distribution method: (x – 2)(x – 3) x(x-3) - 2(x-3) Distribute and simplify

    • one year ago
  2. jim_thompson5910
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    Box method |dw:1341862488934:dw|

    • one year ago
  3. jim_thompson5910
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    Each cell is found by multiplying the row header and the column header Ex: The upper right cell is found by multiplying the row header (x) by the column header (-2) to get -2x

    • one year ago
  4. jim_thompson5910
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    Once you've filled out the boxes, you add up all the terms

    • one year ago
  5. Nick2019
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    so can you do the box method and explain with the answer jim_thompson5910

    • one year ago
  6. jim_thompson5910
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    What is x times x?

    • one year ago
  7. TheViper
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    x^2

    • one year ago
  8. jim_thompson5910
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    I'm asking Nick2019 because I want to make sure he knows this (sorry, I don't mean to sound rude TheViper) So since x times x is x^2, this updates the boxes to get |dw:1341863362988:dw|

    • one year ago
  9. jim_thompson5910
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    Do the same with the other boxes and tell me what you get

    • one year ago
  10. Nick2019
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    lol sorry i left can i just get the asnwer lol

    • one year ago
  11. jim_thompson5910
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    what is x times -2 ?

    • one year ago
  12. Nick2019
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    -2x

    • one year ago
  13. jim_thompson5910
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    So the boxes updates to |dw:1341870148582:dw|

    • one year ago
  14. jim_thompson5910
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    What is -3 times x

    • one year ago
  15. Nick2019
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    -3x and then possitive 6

    • one year ago
  16. jim_thompson5910
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    so we then get |dw:1341870959503:dw|

    • one year ago
  17. jim_thompson5910
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    Now add up all the terms in the boxes x^2 + (-2x) + (-3x) + 6 x^2 - 2x - 3x + 6 x^2 - 5x + 6 So (x-2)(x-3) = x^2 - 5x + 6

    • one year ago
  18. Nick2019
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    thansk for the help i get it now

    • one year ago
  19. jim_thompson5910
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    yw

    • one year ago
  20. Nick2019
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    ?

    • one year ago
  21. jim_thompson5910
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    yw = you're welcome

    • one year ago
  22. Nick2019
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    OH OK Thanks

    • one year ago
  23. jim_thompson5910
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    sure thing

    • one year ago
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