anonymous
  • anonymous
Simplify 5 log2 k – 8 log2 m + 10 log2 n
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
First of all use the property : \[\huge \color{red}{2Logx=Logx^2}\]
anonymous
  • anonymous
Make sense ?
anonymous
  • anonymous
no

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anonymous
  • anonymous
Get the number to the log as a power As an example : \[\Large \color{blue}{5Log_{2}k=Log_{2}k^5}\] Can u do that to the rest ?
anonymous
  • anonymous
ok so its log2k^5-log2m^8+log2n^10 but how do i add and subtract this.
anonymous
  • anonymous
Great,So here is another property : \[\Large ==> \color{orange}{LogX+LogY=Log(X*Y)}\] \[\Large ==> \color{orange}{LogX-LogY=Log( \frac{x}{y})}\] If we collect both of them in one question As: \[\LARGE ==> \color{red}{LogX+LogY-LogZ-LogK= \frac{LogX*LogY}{LogZ*LogK}}\]
anonymous
  • anonymous
ooooh i got it thanks
anonymous
  • anonymous
Yw,Inform me when you need any help :).
anonymous
  • anonymous
ok thanks again

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