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anonymous
 3 years ago
Solve log7 (x – 8) – log7 3 = log7 21
anonymous
 3 years ago
Solve log7 (x – 8) – log7 3 = log7 21

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Try to show you work :) Whenever you stop i will help ..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Nope. Show your work step by step to see which part is hard ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no this is where im stuck at

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm,Actually thats wrong and that mean that the previous step which lead to this was wrong..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Btw : here is hint \[Logx=Logy\] x=y

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well all i did was put log7(x8)over log7(3)=log7 21 then just took off the log7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Its not \[ \Large \frac{Log_{7}(x8)}{Log_{7}(3)}\] It is : \[ \Large Log_{7} \frac{(x8)}{(3)}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So now u have \[ \Large \frac{x8}{3}=21\] 63=x8 x=71

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok but were did you get 63

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ooh neverminod i got it thanks

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lets look over some basic properties such as log(a/b) = log a  log b and log(a*b)= log a + log b and if logx= log y then x=y just because everything is in the base of 7 we could use these properties as well so therefore from your question log7 (x – 8) – log7 3 = log7 21 let us use the first property on the left side and get log7((x8)/3) = log 7 21and now let us use the third property to obtain (x8)/3 = 21 and that will get us x8 = 63 and now solve for x to obtain x = 71 :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks for the help everyone.I really needed it
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