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zakeyadorsey

  • 3 years ago

Solve log7 (x – 8) – log7 3 = log7 21

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  1. Eyad
    • 3 years ago
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    Try to show you work :) Whenever you stop i will help ..

  2. zakeyadorsey
    • 3 years ago
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    ok

  3. zakeyadorsey
    • 3 years ago
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    x-8/3=21

  4. Eyad
    • 3 years ago
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    Nope. Show your work step by step to see which part is hard ?

  5. zakeyadorsey
    • 3 years ago
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    no this is where im stuck at

  6. Eyad
    • 3 years ago
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    hmm,Actually thats wrong and that mean that the previous step which lead to this was wrong..

  7. Eyad
    • 3 years ago
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    Btw : here is hint \[Logx=Logy\] x=y

  8. zakeyadorsey
    • 3 years ago
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    well all i did was put log7(x-8)over log7(3)=log7 21 then just took off the log7

  9. Eyad
    • 3 years ago
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    Its not \[ \Large \frac{Log_{7}(x-8)}{Log_{7}(3)}\] It is : \[ \Large Log_{7} \frac{(x-8)}{(3)}\]

  10. Eyad
    • 3 years ago
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    So now u have \[ \Large \frac{x-8}{3}=21\] 63=x-8 x=71

  11. zakeyadorsey
    • 3 years ago
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    ok but were did you get 63

  12. zakeyadorsey
    • 3 years ago
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    ooh neverminod i got it thanks

  13. Eyad
    • 3 years ago
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    21*3

  14. hamza_b23
    • 3 years ago
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    lets look over some basic properties such as log(a/b) = log a - log b and log(a*b)= log a + log b and if logx= log y then x=y just because everything is in the base of 7 we could use these properties as well so therefore from your question log7 (x – 8) – log7 3 = log7 21 let us use the first property on the left side and get log7((x-8)/3) = log 7 21and now let us use the third property to obtain (x-8)/3 = 21 and that will get us x-8 = 63 and now solve for x to obtain x = 71 :)

  15. zakeyadorsey
    • 3 years ago
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    thanks for the help everyone.I really needed it

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