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TuringTestBest ResponseYou've already chosen the best response.1
I'm kind of weak in this area, so I'm just going to shoot you a link http://tutorial.math.lamar.edu/Classes/LinAlg/Diagonalization.aspx I'm sure somebody can explain it in their own words though... @UnkleRhaukus @nbouscal
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
@Callisto @Chlorophyll how are you guys with linear algebra? wanna help?
 one year ago

liliyBest ResponseYou've already chosen the best response.0
im totally lost. fml. my final is tomoro!!
 one year ago

eliassaabBest ResponseYou've already chosen the best response.1
Why don't you ask a specific question? Your question is too general and it takes time to answer all aspects of it.
 one year ago

liliyBest ResponseYou've already chosen the best response.0
okay: use the diagonlization theomr to find eignevalues of A and baisis for each eignespace: A= [ 2 1 1 1 4 1 1 1 2] =[ 1 1 0 [ 3 0 0 [ 0 1 1 1 1 1 0 2 0 1 1 1 0 1 1] 0 0 3] 1 1 0]
 one year ago

liliyBest ResponseYou've already chosen the best response.0
i dont even understand what to do here!
 one year ago

eliassaabBest ResponseYou've already chosen the best response.1
First find \[Det( A  \lambda I) \]
 one year ago

liliyBest ResponseYou've already chosen the best response.0
bec the 3 matrix udner it is: PD(P1)
 one year ago

eliassaabBest ResponseYou've already chosen the best response.1
\[ Det(A\lambda I)=\lambda ^3+8 \lambda ^221 \lambda +18=(\lambda 3)^2 (2\lambda ) \] So it has 3 as a double eigenvalue and 2.
 one year ago

liliyBest ResponseYou've already chosen the best response.0
\[\lambda^3+8\lambda^220\lambda+18\]
 one year ago

liliyBest ResponseYou've already chosen the best response.0
dang it. how? isnt it 4 lambda 8 and 8 ?
 one year ago

eliassaabBest ResponseYou've already chosen the best response.1
Now we have to find the eigenspace of 2 and the eigenspace of 3
 one year ago

liliyBest ResponseYou've already chosen the best response.0
okay so how do we do it?
 one year ago

eliassaabBest ResponseYou've already chosen the best response.1
Find X such that AX = 2 X and Y such AY =3Y Y1={1, 0, 1} Y2={1, 1, 0} X={1, 1, 1} Y1, and Y2 is a basis for the eigenspace of 3 X is a basis for the eigensapce 2
 one year ago

liliyBest ResponseYou've already chosen the best response.0
wooahhh. hold on. how did u do that? where are those y1 vextor from??
 one year ago

eliassaabBest ResponseYou've already chosen the best response.1
I have to go to sleep now. Try to unersatnd how I got what I got. Bye.
 one year ago
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