anonymous
  • anonymous
if f(x) approximate g(x) within 1/3000 for 10
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
you always come up with the damndest questions but lets say \(f(x)=0\) and \(g(x)=\frac{1}{3000}\) which is as far as it can be then \[\int_{10}^{12}f(x)dx=0\] and \[\int_{10}^{12}\frac{1}{3000}=\frac{2}{3000}\]
anonymous
  • anonymous
a more sophisticated way to answer would be to say that \[\int f -\int g =\int (f-g)\leq \int \frac{1}{3000}=\frac{2}{3000}\]
anonymous
  • anonymous
an even more sophisticated way to answer would be to use absolute values, but enough already

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anonymous
  • anonymous
did you get an answer to that series with the squares? that bedevilled me for a while
anonymous
  • anonymous
the series with squares? which one..i don't even remember..lol
anonymous
  • anonymous
\[x+2^2x^2+3^2x^3+4^2x^4+...\]
anonymous
  • anonymous
or maybe it started with 1, i don't remember but i could not figure out how to get that square there
anonymous
  • anonymous
i think the series is e^x expansion and minus first two term....lol right?
anonymous
  • anonymous
yeah right your questions vary from more or less immediately obvious to wtf with very little in between
anonymous
  • anonymous
maybe a bi-polar professor?
anonymous
  • anonymous
i don't know ..i'm taking an online calculus...it's really frustrate me

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