Here's the question you clicked on:
akl3644
if f(x) approximate g(x) within 1/3000 for 10<x<12 then integral f(x)dx from 10 to 12 approximates integral g(x)dx from 10 to 12 to how many accurate decimals
you always come up with the damndest questions but lets say \(f(x)=0\) and \(g(x)=\frac{1}{3000}\) which is as far as it can be then \[\int_{10}^{12}f(x)dx=0\] and \[\int_{10}^{12}\frac{1}{3000}=\frac{2}{3000}\]
a more sophisticated way to answer would be to say that \[\int f -\int g =\int (f-g)\leq \int \frac{1}{3000}=\frac{2}{3000}\]
an even more sophisticated way to answer would be to use absolute values, but enough already
did you get an answer to that series with the squares? that bedevilled me for a while
the series with squares? which one..i don't even remember..lol
\[x+2^2x^2+3^2x^3+4^2x^4+...\]
or maybe it started with 1, i don't remember but i could not figure out how to get that square there
i think the series is e^x expansion and minus first two term....lol right?
yeah right your questions vary from more or less immediately obvious to wtf with very little in between
maybe a bi-polar professor?
i don't know ..i'm taking an online calculus...it's really frustrate me