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akl3644

  • 2 years ago

if f(x) approximate g(x) within 1/3000 for 10<x<12 then integral f(x)dx from 10 to 12 approximates integral g(x)dx from 10 to 12 to how many accurate decimals

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  1. satellite73
    • 2 years ago
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    you always come up with the damndest questions but lets say \(f(x)=0\) and \(g(x)=\frac{1}{3000}\) which is as far as it can be then \[\int_{10}^{12}f(x)dx=0\] and \[\int_{10}^{12}\frac{1}{3000}=\frac{2}{3000}\]

  2. satellite73
    • 2 years ago
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    a more sophisticated way to answer would be to say that \[\int f -\int g =\int (f-g)\leq \int \frac{1}{3000}=\frac{2}{3000}\]

  3. satellite73
    • 2 years ago
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    an even more sophisticated way to answer would be to use absolute values, but enough already

  4. satellite73
    • 2 years ago
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    did you get an answer to that series with the squares? that bedevilled me for a while

  5. akl3644
    • 2 years ago
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    the series with squares? which one..i don't even remember..lol

  6. satellite73
    • 2 years ago
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    \[x+2^2x^2+3^2x^3+4^2x^4+...\]

  7. satellite73
    • 2 years ago
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    or maybe it started with 1, i don't remember but i could not figure out how to get that square there

  8. akl3644
    • 2 years ago
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    i think the series is e^x expansion and minus first two term....lol right?

  9. satellite73
    • 2 years ago
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    yeah right your questions vary from more or less immediately obvious to wtf with very little in between

  10. satellite73
    • 2 years ago
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    maybe a bi-polar professor?

  11. akl3644
    • 2 years ago
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    i don't know ..i'm taking an online calculus...it's really frustrate me

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spraguer (Moderator)
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