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 2 years ago
if f(x) approximate g(x) within 1/3000 for 10<x<12 then integral f(x)dx from 10 to 12 approximates integral g(x)dx from 10 to 12 to how many accurate decimals
 2 years ago
if f(x) approximate g(x) within 1/3000 for 10<x<12 then integral f(x)dx from 10 to 12 approximates integral g(x)dx from 10 to 12 to how many accurate decimals

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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.3you always come up with the damndest questions but lets say \(f(x)=0\) and \(g(x)=\frac{1}{3000}\) which is as far as it can be then \[\int_{10}^{12}f(x)dx=0\] and \[\int_{10}^{12}\frac{1}{3000}=\frac{2}{3000}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.3a more sophisticated way to answer would be to say that \[\int f \int g =\int (fg)\leq \int \frac{1}{3000}=\frac{2}{3000}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.3an even more sophisticated way to answer would be to use absolute values, but enough already

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.3did you get an answer to that series with the squares? that bedevilled me for a while

akl3644
 2 years ago
Best ResponseYou've already chosen the best response.0the series with squares? which one..i don't even remember..lol

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.3\[x+2^2x^2+3^2x^3+4^2x^4+...\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.3or maybe it started with 1, i don't remember but i could not figure out how to get that square there

akl3644
 2 years ago
Best ResponseYou've already chosen the best response.0i think the series is e^x expansion and minus first two term....lol right?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.3yeah right your questions vary from more or less immediately obvious to wtf with very little in between

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.3maybe a bipolar professor?

akl3644
 2 years ago
Best ResponseYou've already chosen the best response.0i don't know ..i'm taking an online calculus...it's really frustrate me
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