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simplify completely x^2 + 4x  5 / 5x^2 8x + 3 ( multiplied ) 20 x  12 / x^2  6x  55
 one year ago
 one year ago
simplify completely x^2 + 4x  5 / 5x^2 8x + 3 ( multiplied ) 20 x  12 / x^2  6x  55
 one year ago
 one year ago

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WiredBest ResponseYou've already chosen the best response.1
\[\Large \frac{x^{2}+4x5}{5x^{2}8x+3}*\frac{20x12}{x^{2}6x55}\] Sidenote: This is what I put into Equation: Large frac{x^{2}+4x5}{5x^{2}8x+3}*frac{20x12}{x^{2}6x55}
 one year ago

WiredBest ResponseYou've already chosen the best response.1
Ok, so same thing as before: Break down each section of the equation and factor them out.
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
im slowly trying to figure this out . Like I said before Idk Why but im better when There is a variable in there , from when its like this ...
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
I dont think Im Doing this right.
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
diagnally add or multiply/divide?
 one year ago

WiredBest ResponseYou've already chosen the best response.1
There is a variable there, X. Step 1: Factor the polynomials. That will help you simplify the equation. \[\Large x^{2}+4x5\] What are the two factors of this? (x ? )(x+ ? )
 one year ago

WiredBest ResponseYou've already chosen the best response.1
You COULD multiply it all out first, but that would just get confusing quick. Always better to see if there's any factors you can cancel out first before it gets confusing.
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
how about how to simplify the first denominator
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
cause I got for the first numerator (x+5)(x1) and then Idk how to do the first denominator becasue 8 and 5 dont have anything they can both be divided from. the second numerator 4(x3) and the second denominator (x11)(x+5) .. right so far?
 one year ago

WiredBest ResponseYou've already chosen the best response.1
Second Numerator would be 4(5x3).
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
Crap I need to pay more attention that was.. just me not paying attention _
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
First Denominator?
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
I need to hurry got to get off in 10 mins _ one more question on math
 one year ago

WiredBest ResponseYou've already chosen the best response.1
Quadratic equation for that gets you: (x1)(5x3) Quadratic equation: \[ax^{2}+bx+c\] \[\frac{b\pm\sqrt{b^{2}4ac}}{2a}\]
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
\[4 \div x11\] is this correct?
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
dw:1341907059174:dw
 one year ago

WiredBest ResponseYou've already chosen the best response.1
\[\Large \frac{(x+5)(x1)}{(x1)(5x3)}*\frac{4(5x3)}{(x11)(x+5)} = \frac{1}{1}*\frac{4}{(x11)}\] Yep.
 one year ago

FlyinSolo_424Best ResponseYou've already chosen the best response.0
;D thank you. so much ! and now I know to use the quadratic formula if I cant simplify like that. Thank you :D
 one year ago

WiredBest ResponseYou've already chosen the best response.1
No problem at all. Have you covered the quadratic equation yet?
 one year ago
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