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FlyinSolo_424

simplify completely x^2 + 4x - 5 / 5x^2 -8x + 3 ( multiplied ) 20 x - 12 / x^2 - 6x - 55

  • one year ago
  • one year ago

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  1. Wired
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    \[\Large \frac{x^{2}+4x-5}{5x^{2}-8x+3}*\frac{20x-12}{x^{2}-6x-55}\] Sidenote: This is what I put into Equation: Large frac{x^{2}+4x-5}{5x^{2}-8x+3}*frac{20x-12}{x^{2}-6x-55}

    • one year ago
  2. Wired
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    Ok, so same thing as before: Break down each section of the equation and factor them out.

    • one year ago
  3. FlyinSolo_424
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    im slowly trying to figure this out . Like I said before Idk Why but im better when There is a variable in there , from when its like this ...

    • one year ago
  4. FlyinSolo_424
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    I dont think Im Doing this right.

    • one year ago
  5. FlyinSolo_424
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    diagnally add or multiply/divide?

    • one year ago
  6. Wired
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    There is a variable there, X. Step 1: Factor the polynomials. That will help you simplify the equation. \[\Large x^{2}+4x-5\] What are the two factors of this? (x- ? )(x+ ? )

    • one year ago
  7. Wired
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    You COULD multiply it all out first, but that would just get confusing quick. Always better to see if there's any factors you can cancel out first before it gets confusing.

    • one year ago
  8. FlyinSolo_424
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    how about how to simplify the first denominator

    • one year ago
  9. FlyinSolo_424
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    cause I got for the first numerator (x+5)(x-1) and then Idk how to do the first denominator becasue 8 and 5 dont have anything they can both be divided from. the second numerator 4(x-3) and the second denominator (x-11)(x+5) .. right so far?

    • one year ago
  10. Wired
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    Second Numerator would be 4(5x-3).

    • one year ago
  11. FlyinSolo_424
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    Crap I need to pay more attention that was.. just me not paying attention -_-

    • one year ago
  12. FlyinSolo_424
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    First Denominator?

    • one year ago
  13. FlyinSolo_424
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    I need to hurry got to get off in 10 mins -_- one more question on math

    • one year ago
  14. Wired
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    Quadratic equation for that gets you: (x-1)(5x-3) Quadratic equation: \[ax^{2}+bx+c\] \[\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\]

    • one year ago
  15. FlyinSolo_424
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    \[4 \div x-11\] is this correct?

    • one year ago
  16. FlyinSolo_424
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    |dw:1341907059174:dw|

    • one year ago
  17. Wired
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    \[\Large \frac{(x+5)(x-1)}{(x-1)(5x-3)}*\frac{4(5x-3)}{(x-11)(x+5)} = \frac{1}{1}*\frac{4}{(x-11)}\] Yep.

    • one year ago
  18. FlyinSolo_424
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    ;D thank you. so much ! and now I know to use the quadratic formula if I cant simplify like that. Thank you :D

    • one year ago
  19. Wired
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    No problem at all. Have you covered the quadratic equation yet?

    • one year ago
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