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FlyinSolo_424
 3 years ago
simplify completely x^2 + 4x  5 / 5x^2 8x + 3 ( multiplied ) 20 x  12 / x^2  6x  55
FlyinSolo_424
 3 years ago
simplify completely x^2 + 4x  5 / 5x^2 8x + 3 ( multiplied ) 20 x  12 / x^2  6x  55

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Wired
 3 years ago
Best ResponseYou've already chosen the best response.1\[\Large \frac{x^{2}+4x5}{5x^{2}8x+3}*\frac{20x12}{x^{2}6x55}\] Sidenote: This is what I put into Equation: Large frac{x^{2}+4x5}{5x^{2}8x+3}*frac{20x12}{x^{2}6x55}

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1Ok, so same thing as before: Break down each section of the equation and factor them out.

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0im slowly trying to figure this out . Like I said before Idk Why but im better when There is a variable in there , from when its like this ...

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0I dont think Im Doing this right.

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0diagnally add or multiply/divide?

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1There is a variable there, X. Step 1: Factor the polynomials. That will help you simplify the equation. \[\Large x^{2}+4x5\] What are the two factors of this? (x ? )(x+ ? )

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1You COULD multiply it all out first, but that would just get confusing quick. Always better to see if there's any factors you can cancel out first before it gets confusing.

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0how about how to simplify the first denominator

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0cause I got for the first numerator (x+5)(x1) and then Idk how to do the first denominator becasue 8 and 5 dont have anything they can both be divided from. the second numerator 4(x3) and the second denominator (x11)(x+5) .. right so far?

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1Second Numerator would be 4(5x3).

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0Crap I need to pay more attention that was.. just me not paying attention _

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0First Denominator?

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0I need to hurry got to get off in 10 mins _ one more question on math

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1Quadratic equation for that gets you: (x1)(5x3) Quadratic equation: \[ax^{2}+bx+c\] \[\frac{b\pm\sqrt{b^{2}4ac}}{2a}\]

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0\[4 \div x11\] is this correct?

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1341907059174:dw

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1\[\Large \frac{(x+5)(x1)}{(x1)(5x3)}*\frac{4(5x3)}{(x11)(x+5)} = \frac{1}{1}*\frac{4}{(x11)}\] Yep.

FlyinSolo_424
 3 years ago
Best ResponseYou've already chosen the best response.0;D thank you. so much ! and now I know to use the quadratic formula if I cant simplify like that. Thank you :D

Wired
 3 years ago
Best ResponseYou've already chosen the best response.1No problem at all. Have you covered the quadratic equation yet?
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