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FlyinSolo_424
Group Title
simplify completely x^2 + 4x  5 / 5x^2 8x + 3 ( multiplied ) 20 x  12 / x^2  6x  55
 2 years ago
 2 years ago
FlyinSolo_424 Group Title
simplify completely x^2 + 4x  5 / 5x^2 8x + 3 ( multiplied ) 20 x  12 / x^2  6x  55
 2 years ago
 2 years ago

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Wired Group TitleBest ResponseYou've already chosen the best response.1
\[\Large \frac{x^{2}+4x5}{5x^{2}8x+3}*\frac{20x12}{x^{2}6x55}\] Sidenote: This is what I put into Equation: Large frac{x^{2}+4x5}{5x^{2}8x+3}*frac{20x12}{x^{2}6x55}
 2 years ago

Wired Group TitleBest ResponseYou've already chosen the best response.1
Ok, so same thing as before: Break down each section of the equation and factor them out.
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
im slowly trying to figure this out . Like I said before Idk Why but im better when There is a variable in there , from when its like this ...
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
I dont think Im Doing this right.
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
diagnally add or multiply/divide?
 2 years ago

Wired Group TitleBest ResponseYou've already chosen the best response.1
There is a variable there, X. Step 1: Factor the polynomials. That will help you simplify the equation. \[\Large x^{2}+4x5\] What are the two factors of this? (x ? )(x+ ? )
 2 years ago

Wired Group TitleBest ResponseYou've already chosen the best response.1
You COULD multiply it all out first, but that would just get confusing quick. Always better to see if there's any factors you can cancel out first before it gets confusing.
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
how about how to simplify the first denominator
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
cause I got for the first numerator (x+5)(x1) and then Idk how to do the first denominator becasue 8 and 5 dont have anything they can both be divided from. the second numerator 4(x3) and the second denominator (x11)(x+5) .. right so far?
 2 years ago

Wired Group TitleBest ResponseYou've already chosen the best response.1
Second Numerator would be 4(5x3).
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
Crap I need to pay more attention that was.. just me not paying attention _
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
First Denominator?
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
I need to hurry got to get off in 10 mins _ one more question on math
 2 years ago

Wired Group TitleBest ResponseYou've already chosen the best response.1
Quadratic equation for that gets you: (x1)(5x3) Quadratic equation: \[ax^{2}+bx+c\] \[\frac{b\pm\sqrt{b^{2}4ac}}{2a}\]
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
\[4 \div x11\] is this correct?
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
dw:1341907059174:dw
 2 years ago

Wired Group TitleBest ResponseYou've already chosen the best response.1
\[\Large \frac{(x+5)(x1)}{(x1)(5x3)}*\frac{4(5x3)}{(x11)(x+5)} = \frac{1}{1}*\frac{4}{(x11)}\] Yep.
 2 years ago

FlyinSolo_424 Group TitleBest ResponseYou've already chosen the best response.0
;D thank you. so much ! and now I know to use the quadratic formula if I cant simplify like that. Thank you :D
 2 years ago

Wired Group TitleBest ResponseYou've already chosen the best response.1
No problem at all. Have you covered the quadratic equation yet?
 2 years ago
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