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simplify completely x^2 + 4x - 5 / 5x^2 -8x + 3 ( multiplied ) 20 x - 12 / x^2 - 6x - 55

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\[\Large \frac{x^{2}+4x-5}{5x^{2}-8x+3}*\frac{20x-12}{x^{2}-6x-55}\] Sidenote: This is what I put into Equation: Large frac{x^{2}+4x-5}{5x^{2}-8x+3}*frac{20x-12}{x^{2}-6x-55}
Ok, so same thing as before: Break down each section of the equation and factor them out.
im slowly trying to figure this out . Like I said before Idk Why but im better when There is a variable in there , from when its like this ...

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Other answers:

I dont think Im Doing this right.
diagnally add or multiply/divide?
There is a variable there, X. Step 1: Factor the polynomials. That will help you simplify the equation. \[\Large x^{2}+4x-5\] What are the two factors of this? (x- ? )(x+ ? )
You COULD multiply it all out first, but that would just get confusing quick. Always better to see if there's any factors you can cancel out first before it gets confusing.
how about how to simplify the first denominator
cause I got for the first numerator (x+5)(x-1) and then Idk how to do the first denominator becasue 8 and 5 dont have anything they can both be divided from. the second numerator 4(x-3) and the second denominator (x-11)(x+5) .. right so far?
Second Numerator would be 4(5x-3).
Crap I need to pay more attention that was.. just me not paying attention -_-
First Denominator?
I need to hurry got to get off in 10 mins -_- one more question on math
Quadratic equation for that gets you: (x-1)(5x-3) Quadratic equation: \[ax^{2}+bx+c\] \[\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\]
\[4 \div x-11\] is this correct?
\[\Large \frac{(x+5)(x-1)}{(x-1)(5x-3)}*\frac{4(5x-3)}{(x-11)(x+5)} = \frac{1}{1}*\frac{4}{(x-11)}\] Yep.
;D thank you. so much ! and now I know to use the quadratic formula if I cant simplify like that. Thank you :D
No problem at all. Have you covered the quadratic equation yet?

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