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FlyinSolo_424

  • 2 years ago

simplify completely x^2 + 4x - 5 / 5x^2 -8x + 3 ( multiplied ) 20 x - 12 / x^2 - 6x - 55

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  1. Wired
    • 2 years ago
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    \[\Large \frac{x^{2}+4x-5}{5x^{2}-8x+3}*\frac{20x-12}{x^{2}-6x-55}\] Sidenote: This is what I put into Equation: Large frac{x^{2}+4x-5}{5x^{2}-8x+3}*frac{20x-12}{x^{2}-6x-55}

  2. Wired
    • 2 years ago
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    Ok, so same thing as before: Break down each section of the equation and factor them out.

  3. FlyinSolo_424
    • 2 years ago
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    im slowly trying to figure this out . Like I said before Idk Why but im better when There is a variable in there , from when its like this ...

  4. FlyinSolo_424
    • 2 years ago
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    I dont think Im Doing this right.

  5. FlyinSolo_424
    • 2 years ago
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    diagnally add or multiply/divide?

  6. Wired
    • 2 years ago
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    There is a variable there, X. Step 1: Factor the polynomials. That will help you simplify the equation. \[\Large x^{2}+4x-5\] What are the two factors of this? (x- ? )(x+ ? )

  7. Wired
    • 2 years ago
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    You COULD multiply it all out first, but that would just get confusing quick. Always better to see if there's any factors you can cancel out first before it gets confusing.

  8. FlyinSolo_424
    • 2 years ago
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    how about how to simplify the first denominator

  9. FlyinSolo_424
    • 2 years ago
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    cause I got for the first numerator (x+5)(x-1) and then Idk how to do the first denominator becasue 8 and 5 dont have anything they can both be divided from. the second numerator 4(x-3) and the second denominator (x-11)(x+5) .. right so far?

  10. Wired
    • 2 years ago
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    Second Numerator would be 4(5x-3).

  11. FlyinSolo_424
    • 2 years ago
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    Crap I need to pay more attention that was.. just me not paying attention -_-

  12. FlyinSolo_424
    • 2 years ago
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    First Denominator?

  13. FlyinSolo_424
    • 2 years ago
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    I need to hurry got to get off in 10 mins -_- one more question on math

  14. Wired
    • 2 years ago
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    Quadratic equation for that gets you: (x-1)(5x-3) Quadratic equation: \[ax^{2}+bx+c\] \[\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\]

  15. FlyinSolo_424
    • 2 years ago
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    \[4 \div x-11\] is this correct?

  16. FlyinSolo_424
    • 2 years ago
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    |dw:1341907059174:dw|

  17. Wired
    • 2 years ago
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    \[\Large \frac{(x+5)(x-1)}{(x-1)(5x-3)}*\frac{4(5x-3)}{(x-11)(x+5)} = \frac{1}{1}*\frac{4}{(x-11)}\] Yep.

  18. FlyinSolo_424
    • 2 years ago
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    ;D thank you. so much ! and now I know to use the quadratic formula if I cant simplify like that. Thank you :D

  19. Wired
    • 2 years ago
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    No problem at all. Have you covered the quadratic equation yet?

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