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anjali_pant
Group Title
Can anyone please explain the topic calendars ? eg: What was the day on 15th august 1947 ? Explain step by step  Intra month , inter month , inter year. Thanks.
 2 years ago
 2 years ago
anjali_pant Group Title
Can anyone please explain the topic calendars ? eg: What was the day on 15th august 1947 ? Explain step by step  Intra month , inter month , inter year. Thanks.
 2 years ago
 2 years ago

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adityanaik28 Group TitleBest ResponseYou've already chosen the best response.0
like.......17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998) Odd days in 1600 years = 0 Odd days in 300 years = (5 x 3) 1 97 years has 24 leap years + 73 ordinary years. Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days. Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days 168 days = 24 weeks = 0 odd day. Total number of odd days = (0 + 1 + 2 + 0) = 3. in this way u can find for ur date
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
Thanks but I dint get anything :p But some other short cut ( easier way to understand) ?
 2 years ago

adityanaik28 Group TitleBest ResponseYou've already chosen the best response.0
oww wait let me think........
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
If you could find some video related to it , it would be great !
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
the Gregorian calendar has same number of days in every month ... except for February (29) total days = difference of today to 15 th august + 365.4*(2013  1947) 15 th august 1947 day = today's day + (total days) mod 7
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
Is it in accordance with the standard english calendar @experimentX ?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
yes it is .. check every calendar, all months have the same number of days except February
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
My teacher told me a different method to calculate. He assumed that if all the months had 28 days then the extra days in each month would be : jan 3 , feb 0/1 , march 3 , april 2 , may 3 and so on ! Then he used this data to calculate the day on a particular date ( inter month ) . Iam not able to understand this method , if you get to know , please let me know @experimentX !
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
it is essentially same ... if all months were 28 then it's natural that extra days would be jan 3 , feb 0/1 , march 3 , april 2 , may 3 ... and weeks repeat after 7 days, if it's dec last and it's sunday then ... feb 1 would be => 3+1 = thursday .. same principle ... it shortens the number.
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
that is alrite. But if for solving , in entrance papers , I need to solve via shortcuts. Please help in inter year section as well.
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
* but for solving
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
find the extra days in each year (total)
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
lets do an example. its given that july 13 2012 is a friday , what day will it be on 17'th december 2012 ?
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
please explain step by step , by the method I mentioned above
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
no ... assume everymonth as 28 days, find the extra days in every month
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
What after finding extra days ?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
well ... add 0.25 to feb
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
It would have been gr8 , if you could explain the basic method involved step by step.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
okay .. give me the data first.
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
why 0.25 ?
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
its given that july 13 2012 is a friday , what day will it be on 17'th december 2012 ?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
because of leap year.
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
see what I have followed from my class is that , I will start adding extra days from july till november ( not of december because its effect will be felt on jan ) . Feb is out of question because my data varies from july to december. Had it been jan , then concept of leap year would have taken into account. Now after adding total number of days = 13 , the calender will shift by 13 days. It means that we'll calculate the day on 13+13=26 july , ( adding 7 days 4times , will yield a friday again then 2days ) which will be a Wednesday. Now 26 december will be Wednesday , so 17th dec will come out to be saturday ! But its wrong ! It will be monday! Please help !
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
well ... i'm not sure about that. can you count from March to Jan?
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
that would be inter year ! Here iam discussing inter month. Both are slightly diff frm each other
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
not sure how you would do.
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
:( Anyways thanks for your dedicated efforts ! :)
 2 years ago
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