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anjali_pant
Can anyone please explain the topic calendars ? eg: What was the day on 15th august 1947 ? Explain step by step - Intra month , inter month , inter year. Thanks.
like.......17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998) Odd days in 1600 years = 0 Odd days in 300 years = (5 x 3) 1 97 years has 24 leap years + 73 ordinary years. Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days. Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days 168 days = 24 weeks = 0 odd day. Total number of odd days = (0 + 1 + 2 + 0) = 3. in this way u can find for ur date
Thanks but I dint get anything :p But some other short cut ( easier way to understand) ?
oww wait let me think........
If you could find some video related to it , it would be great !
the Gregorian calendar has same number of days in every month ... except for February (29) total days = difference of today to 15 th august + 365.4*(2013 - 1947) 15 th august 1947 day = today's day + (total days) mod 7
Is it in accordance with the standard english calendar @experimentX ?
yes it is .. check every calendar, all months have the same number of days except February
My teacher told me a different method to calculate. He assumed that if all the months had 28 days then the extra days in each month would be : jan 3 , feb 0/1 , march 3 , april 2 , may 3 and so on ! Then he used this data to calculate the day on a particular date ( inter month ) . Iam not able to understand this method , if you get to know , please let me know @experimentX !
it is essentially same ... if all months were 28 then it's natural that extra days would be jan 3 , feb 0/1 , march 3 , april 2 , may 3 ... and weeks repeat after 7 days, if it's dec last and it's sunday then ... feb 1 would be => 3+1 = thursday .. same principle ... it shortens the number.
that is alrite. But if for solving , in entrance papers , I need to solve via shortcuts. Please help in inter year section as well.
find the extra days in each year (total)
lets do an example. its given that july 13 2012 is a friday , what day will it be on 17'th december 2012 ?
please explain step by step , by the method I mentioned above
no ... assume everymonth as 28 days, find the extra days in every month
What after finding extra days ?
well ... add 0.25 to feb
It would have been gr8 , if you could explain the basic method involved step by step.
okay .. give me the data first.
its given that july 13 2012 is a friday , what day will it be on 17'th december 2012 ?
because of leap year.
see what I have followed from my class is that , I will start adding extra days from july till november ( not of december because its effect will be felt on jan ) . Feb is out of question because my data varies from july to december. Had it been jan , then concept of leap year would have taken into account. Now after adding total number of days = 13 , the calender will shift by 13 days. It means that we'll calculate the day on 13+13=26 july , ( adding 7 days 4times , will yield a friday again then -2days ) which will be a Wednesday. Now 26 december will be Wednesday , so 17th dec will come out to be saturday ! But its wrong ! It will be monday! Please help !
well ... i'm not sure about that. can you count from March to Jan?
that would be inter year ! Here iam discussing inter month. Both are slightly diff frm each other
not sure how you would do.
:-( Anyways thanks for your dedicated efforts ! :-)