Can anyone please explain the topic calendars ? eg: What was the day on 15th august 1947 ? Explain step by step - Intra month , inter month , inter year. Thanks.

- anonymous

- schrodinger

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- anonymous

like.......17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
in this way u can find for ur date

- anonymous

Thanks but I dint get anything :p But some other short cut ( easier way to understand) ?

- anonymous

oww wait let me think........

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- anonymous

If you could find some video related to it , it would be great !

- experimentX

the Gregorian calendar has same number of days in every month ... except for February (29)
total days = difference of today to 15 th august + 365.4*(2013 - 1947)
15 th august 1947 day = today's day + (total days) mod 7

- anonymous

Is it in accordance with the standard english calendar @experimentX ?

- experimentX

yes it is .. check every calendar, all months have the same number of days except February

- anonymous

My teacher told me a different method to calculate. He assumed that if all the months had 28 days then the extra days in each month would be : jan 3 , feb 0/1 , march 3 , april 2 , may 3 and so on ! Then he used this data to calculate the day on a particular date ( inter month ) . Iam not able to understand this method , if you get to know , please let me know @experimentX !

- experimentX

it is essentially same ... if all months were 28 then it's natural that extra days would be
jan 3 , feb 0/1 , march 3 , april 2 , may 3 ... and weeks repeat after 7 days, if it's dec last and it's sunday then ... feb 1 would be => 3+1 = thursday .. same principle ... it shortens the number.

- anonymous

that is alrite. But if for solving , in entrance papers , I need to solve via shortcuts. Please help in inter year section as well.

- anonymous

* but for solving

- experimentX

find the extra days in each year (total)

- anonymous

lets do an example.
its given that july 13 2012 is a friday , what day will it be on 17'th december 2012 ?

- anonymous

please explain step by step , by the method I mentioned above

- experimentX

no ... assume everymonth as 28 days, find the extra days in every month

- anonymous

no ?

- anonymous

What after finding extra days ?

- experimentX

well ... add 0.25 to feb

- anonymous

It would have been gr8 , if you could explain the basic method involved step by step.

- experimentX

okay .. give me the data first.

- anonymous

why 0.25 ?

- anonymous

its given that july 13 2012 is a friday , what day will it be on 17'th december 2012 ?

- experimentX

because of leap year.

- anonymous

see what I have followed from my class is that , I will start adding extra days from july till november ( not of december because its effect will be felt on jan ) . Feb is out of question because my data varies from july to december. Had it been jan , then concept of leap year would have taken into account. Now after adding total number of days = 13 , the calender will shift by 13 days. It means that we'll calculate the day on 13+13=26 july , ( adding 7 days 4times , will yield a friday again then -2days ) which will be a Wednesday. Now 26 december will be Wednesday , so 17th dec will come out to be saturday ! But its wrong ! It will be monday! Please help !

- experimentX

well ... i'm not sure about that. can you count from March to Jan?

- anonymous

that would be inter year ! Here iam discussing inter month. Both are slightly diff frm each other

- experimentX

not sure how you would do.

- anonymous

:-( Anyways thanks for your dedicated efforts ! :-)

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