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jkev1
Write an equation of the line that passes through the pair of points. (2,3), (4,-2)? a.y=- 5/2x-1/8 b.y=- 5/2 x-8 c.y= - 5/2x+8 d.y=5/2x+8
i'm so confused:( @waterineyes
Slope is given by: \[\huge \color{blue}{Slope = \frac{y_2-y_1}{x_2 - x_1}}\]
Can you find slope now or not?? Just plug in the values, \[(x_1,y_1) = (2,3)\] \[(x_2,y_2) = (4,-2)\]
I have to leave now... So, I am solving this for you: \[m = \frac{-2-3}{4-2} = \frac{-5}{2}\] The equation with one point and one slope is given by: \[\large \color{green}{y - y_1 = m(x - x_1)}\] Putting the first point \((2,3)\) in this: \[y - 3 = m(x - 2) \implies y - 3 = \frac{-5}{2}(x - 2)\] \[y - 3= \frac{-5}{2}x + 5 \implies y = \frac{-5}{2}x + 8\]