harrym 3 years ago I have 3 questions and I have a pretty good idea of an answer for some of them but im not 100% sure if they are right so ill see if I get the same answer: 1. If bh=42 what is de 2.If ab=36 what is jf 3.If ab=36 what is ke

1. sterna

Do you have a diagram to go with this question?

2. harrym

Yea I posted an attachment ill repost it

3. sterna

thanks - didn't see it before

4. harrym

I think it was my fault so dont worry hahah

5. sterna

looks like you've got 6 congruent segments across the bottom with a total length of 42, so what do you think DE equals?

6. harrym

I believe de = 7 but Its important that I get it right so thats why I posted this

7. sterna

yep

8. sterna

Now for the others. You have a triangle with one side of 36 (that's AB) and another side of 42 (BH). All the other triangles as you move across from left to right are similar to the biggest triangle (ABH.) Are you with me?

9. harrym

Yea

10. sterna

Since all the triangles are similar, the proportions of their sides are the same. So 36/42, which reduces to 6/7, is a common proportion in all of the triangles. For example, triangle JFH

11. sterna

has a base of 14 (7*2) so to find jf, set up a proportion of 6/7=x/14 to get JF.

12. sterna

so JF would be?

13. harrym

12

14. sterna

good! Now do the same thing for KE. Figure the length of the base of triangle KEH and solve the proportion

15. sterna

you doing OK?

16. harrym

Yea I got 18 but im not really sure if its right

17. sterna

that's what I got as well: x/21=6/7. x=18 I think you've got it!

18. harrym

Alright well thank you so much!

19. sterna

my pleasure!