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 2 years ago
Note to the viewers: This is nt a question. I made a mistake in certain portion of my previous post which was a tutorial on trigonometric identities and this is the correct version of it.
 2 years ago
Note to the viewers: This is nt a question. I made a mistake in certain portion of my previous post which was a tutorial on trigonometric identities and this is the correct version of it.

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ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.2\[sin(A+B)=sinAcosB+cosAsinB\] \[cos(A+B)=cosAcosBsinAsinB\] \[sin(AB)=sinAcosBcosAsinB\] \[cos(AB)=cosAcosB+sinAsinB\]

Valpey
 2 years ago
Best ResponseYou've already chosen the best response.0You can also write: \[sin(A\pm B)=sinAcosB\pm cosAsinB\] \[cos(A\pm B)=cosAcosB\mp sinAsinB\]
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