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ajprincess

  • 2 years ago

Note to the viewers: This is nt a question. I made a mistake in certain portion of my previous post which was a tutorial on trigonometric identities and this is the correct version of it.

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  1. ajprincess
    • 2 years ago
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    jst a moment then.

  2. ajprincess
    • 2 years ago
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    \[sin(A+B)=sinAcosB+cosAsinB\] \[cos(A+B)=cosAcosB-sinAsinB\] \[sin(A-B)=sinAcosB-cosAsinB\] \[cos(A-B)=cosAcosB+sinAsinB\]

  3. Valpey
    • 2 years ago
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    You can also write: \[sin(A\pm B)=sinAcosB\pm cosAsinB\] \[cos(A\pm B)=cosAcosB\mp sinAsinB\]

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