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baddinlol
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Specify a hybrid function over the maximal domain of f(x), where f(x) = 2/(sqrt(1x^2))
 2 years ago
 2 years ago
baddinlol Group Title
Specify a hybrid function over the maximal domain of f(x), where f(x) = 2/(sqrt(1x^2))
 2 years ago
 2 years ago

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baddinlol Group TitleBest ResponseYou've already chosen the best response.0
\[2 \div \sqrt(1x^2)\]
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
I got 2/ sqrt(1x^2) between x E (0,1)
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
How do i get the other one?
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
I have the solution by the way
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
I just don't know how to get it.
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
The other solution somehow is 2/ sqrt(1x^2) between x E (1,0)
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
I have no idea how though
 2 years ago

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@lgbasallote
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
what lesson is this?
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
Its calculus
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
differential?
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
Yes, its in the differential chapter
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i do not know this sorry
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
Ok, thanks anyway
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
@.Sam. do you know this?
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
I suppose you start with the fact that 1x^2 must be greater than zero. Don't really see how the function can take negative values.
 2 years ago
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