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Does it start from rest?
|dw:1342006345931:dw|
thanks

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Other answers:

Wait
Its wrong
Use the formula v = ut + 0.5at^2
Assuming a start from rest: \[d=Vi(t)+\frac{1}{2}at^2=0m/s^2+\frac{1}{2}(4m/s^2)(10s)^2=200m\]
Oops sorry
lol yes firstly u found the mistake
x = ut + 0.5at^2
@Shane_B can u make it more clearer
Or, you can use: \[d=\frac{V_i+V_f}{2}t=\frac{0m/s+40m/s}{2}(10s)=200m\]
Which part isn't clear?
well plzzz make it clear from the beggining
Well he used this formula x = ut + 0.5at^2
u = 0m/s , becausehe assumed the car started from rest
t = 10s
a = 4m/s^2
Then he plugged in the numbers x = 0.5*4* 100 = 200m
@baddinlol: thanks...working with someone else at the moment :)
@Shane_B ITS \[\huge 4 \quad m/s^2 \]
not 40 m/s2
no no
The final velocity is 40m/s
40m/s is the final velocity...
okay lol

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