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okay @lgbasallote @Shane_B @baddinlol
A racing car has a uniform acc.. of \[ 4 \quad m/s^2\]. What's the distance she will cover 10s later
 one year ago
 one year ago
okay @lgbasallote @Shane_B @baddinlol A racing car has a uniform acc.. of \[ 4 \quad m/s^2\]. What's the distance she will cover 10s later
 one year ago
 one year ago

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baddinlolBest ResponseYou've already chosen the best response.1
Does it start from rest?
 one year ago

RohangrrBest ResponseYou've already chosen the best response.4
dw:1342006345931:dw
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
Use the formula v = ut + 0.5at^2
 one year ago

Shane_BBest ResponseYou've already chosen the best response.1
Assuming a start from rest: \[d=Vi(t)+\frac{1}{2}at^2=0m/s^2+\frac{1}{2}(4m/s^2)(10s)^2=200m\]
 one year ago

RohangrrBest ResponseYou've already chosen the best response.4
lol yes firstly u found the mistake
 one year ago

RohangrrBest ResponseYou've already chosen the best response.4
@Shane_B can u make it more clearer
 one year ago

Shane_BBest ResponseYou've already chosen the best response.1
Or, you can use: \[d=\frac{V_i+V_f}{2}t=\frac{0m/s+40m/s}{2}(10s)=200m\]
 one year ago

Shane_BBest ResponseYou've already chosen the best response.1
Which part isn't clear?
 one year ago

RohangrrBest ResponseYou've already chosen the best response.4
well plzzz make it clear from the beggining
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
Well he used this formula x = ut + 0.5at^2
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
u = 0m/s , becausehe assumed the car started from rest
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
Then he plugged in the numbers x = 0.5*4* 100 = 200m
 one year ago

Shane_BBest ResponseYou've already chosen the best response.1
@baddinlol: thanks...working with someone else at the moment :)
 one year ago

RohangrrBest ResponseYou've already chosen the best response.4
@Shane_B ITS \[\huge 4 \quad m/s^2 \]
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
The final velocity is 40m/s
 one year ago

Shane_BBest ResponseYou've already chosen the best response.1
40m/s is the final velocity...
 one year ago
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