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Does it start from rest?

|dw:1342006345931:dw|

thanks

Wait

Its wrong

Use the formula v = ut + 0.5at^2

Assuming a start from rest: \[d=Vi(t)+\frac{1}{2}at^2=0m/s^2+\frac{1}{2}(4m/s^2)(10s)^2=200m\]

Oops sorry

lol yes firstly u found the mistake

x = ut + 0.5at^2

Or, you can use: \[d=\frac{V_i+V_f}{2}t=\frac{0m/s+40m/s}{2}(10s)=200m\]

Which part isn't clear?

well plzzz make it clear from the beggining

Well he used this formula x = ut + 0.5at^2

u = 0m/s , becausehe assumed the car started from rest

t = 10s

a = 4m/s^2

Then he plugged in the numbers x = 0.5*4* 100 = 200m

@baddinlol: thanks...working with someone else at the moment :)

not 40 m/s2

no no

The final velocity is 40m/s

40m/s is the final velocity...

okay lol