Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Rohangrr Group Title

okay @lgbasallote @Shane_B @baddinlol A racing car has a uniform acc.. of \[ 4 \quad m/s^2\]. What's the distance she will cover 10s later

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Does it start from rest?

    • 2 years ago
  2. Rohangrr Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    |dw:1342006345931:dw|

    • 2 years ago
  3. Rohangrr Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    thanks

    • 2 years ago
  4. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Wait

    • 2 years ago
  5. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Its wrong

    • 2 years ago
  6. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Use the formula v = ut + 0.5at^2

    • 2 years ago
  7. Shane_B Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Assuming a start from rest: \[d=Vi(t)+\frac{1}{2}at^2=0m/s^2+\frac{1}{2}(4m/s^2)(10s)^2=200m\]

    • 2 years ago
  8. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Oops sorry

    • 2 years ago
  9. Rohangrr Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    lol yes firstly u found the mistake

    • 2 years ago
  10. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    x = ut + 0.5at^2

    • 2 years ago
  11. Rohangrr Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    @Shane_B can u make it more clearer

    • 2 years ago
  12. Shane_B Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Or, you can use: \[d=\frac{V_i+V_f}{2}t=\frac{0m/s+40m/s}{2}(10s)=200m\]

    • 2 years ago
  13. Shane_B Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Which part isn't clear?

    • 2 years ago
  14. Rohangrr Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    well plzzz make it clear from the beggining

    • 2 years ago
  15. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Well he used this formula x = ut + 0.5at^2

    • 2 years ago
  16. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    u = 0m/s , becausehe assumed the car started from rest

    • 2 years ago
  17. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    t = 10s

    • 2 years ago
  18. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    a = 4m/s^2

    • 2 years ago
  19. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Then he plugged in the numbers x = 0.5*4* 100 = 200m

    • 2 years ago
  20. Shane_B Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @baddinlol: thanks...working with someone else at the moment :)

    • 2 years ago
  21. Rohangrr Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    @Shane_B ITS \[\huge 4 \quad m/s^2 \]

    • 2 years ago
  22. Rohangrr Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    not 40 m/s2

    • 2 years ago
  23. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    no no

    • 2 years ago
  24. baddinlol Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    The final velocity is 40m/s

    • 2 years ago
  25. Shane_B Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    40m/s is the final velocity...

    • 2 years ago
  26. Rohangrr Group Title
    Best Response
    You've already chosen the best response.
    Medals 4

    okay lol

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.