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anonymous
 3 years ago
okay @lgbasallote @Shane_B @baddinlol
A racing car has a uniform acc.. of \[ 4 \quad m/s^2\]. What's the distance she will cover 10s later
anonymous
 3 years ago
okay @lgbasallote @Shane_B @baddinlol A racing car has a uniform acc.. of \[ 4 \quad m/s^2\]. What's the distance she will cover 10s later

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Does it start from rest?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1342006345931:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Use the formula v = ut + 0.5at^2

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.1Assuming a start from rest: \[d=Vi(t)+\frac{1}{2}at^2=0m/s^2+\frac{1}{2}(4m/s^2)(10s)^2=200m\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol yes firstly u found the mistake

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Shane_B can u make it more clearer

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.1Or, you can use: \[d=\frac{V_i+V_f}{2}t=\frac{0m/s+40m/s}{2}(10s)=200m\]

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.1Which part isn't clear?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well plzzz make it clear from the beggining

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well he used this formula x = ut + 0.5at^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u = 0m/s , becausehe assumed the car started from rest

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Then he plugged in the numbers x = 0.5*4* 100 = 200m

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.1@baddinlol: thanks...working with someone else at the moment :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Shane_B ITS \[\huge 4 \quad m/s^2 \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The final velocity is 40m/s

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.140m/s is the final velocity...
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