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Rohangrr Group Title

A train starting from rest is moving with a uniform acceleration of 0.2 m/s^2 for 5 mins , Calculate the speed acquired and the distance traveled in this time... @Shane_B @angela210793 @lgbasallote @baddinlol

  • 2 years ago
  • 2 years ago

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  1. Ganpat Group Title
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    in what time ?? i mean how much time.. ??

    • 2 years ago
  2. Ganpat Group Title
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    a= (v - u)/ t.. this might help..

    • 2 years ago
  3. Rohangrr Group Title
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    \[\huge NOW??\]

    • 2 years ago
  4. Rohangrr Group Title
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    you can solve it further @Ganpat

    • 2 years ago
  5. Ganpat Group Title
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    k, so t = 5 min.. a= 0.2, u = 0 and v = ?? so, 0.2 = (v-0)/ (5* 30) v = 150 * 0.2 V = 75 m /s..

    • 2 years ago
  6. Rohangrr Group Title
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    okay is that alllllll

    • 2 years ago
  7. Rohangrr Group Title
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    @baddinlol is he correct

    • 2 years ago
  8. baddinlol Group Title
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    @Ganpat, doesn't time have to be in seconds?

    • 2 years ago
  9. Rohangrr Group Title
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    okay

    • 2 years ago
  10. baddinlol Group Title
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    You used it in minutes..

    • 2 years ago
  11. Rohangrr Group Title
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    Your answer

    • 2 years ago
  12. baddinlol Group Title
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    Wait let me solve it.

    • 2 years ago
  13. baddinlol Group Title
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    For speed required

    • 2 years ago
  14. Ganpat Group Title
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    @baddinlol: yes, so i multiplied t by 60..

    • 2 years ago
  15. baddinlol Group Title
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    Use v = u + at

    • 2 years ago
  16. Ganpat Group Title
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    i have done calculation mistake.. sorry

    • 2 years ago
  17. baddinlol Group Title
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    ohh...

    • 2 years ago
  18. Ganpat Group Title
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    k, so t = 5 min.. a= 0.2, u = 0 and v = ?? so, 0.2 = (v-0)/ (5* 60) v = 300 * 0.2 V = 150 m /s.. this is right

    • 2 years ago
  19. Rohangrr Group Title
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    ooooooooppppppssssssssss

    • 2 years ago
  20. Rohangrr Group Title
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    |dw:1342008049684:dw|

    • 2 years ago
  21. baddinlol Group Title
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    Still wrong?

    • 2 years ago
  22. baddinlol Group Title
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    v = u + at = 300*0.2 = 60m/s

    • 2 years ago
  23. Rohangrr Group Title
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    okay then

    • 2 years ago
  24. Ganpat Group Title
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    ha ha, sorry, guys little messed up..

    • 2 years ago
  25. Rohangrr Group Title
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    lol

    • 2 years ago
  26. Rohangrr Group Title
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    its all f9999

    • 2 years ago
  27. baddinlol Group Title
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    Ok so you need to find distance now

    • 2 years ago
  28. baddinlol Group Title
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    Use x = ut+0.5at^2

    • 2 years ago
  29. Ganpat Group Title
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    x = ut + 1/2 * at2..

    • 2 years ago
  30. baddinlol Group Title
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    x = 0.5*0.2*(300^2)= 9000m

    • 2 years ago
  31. Rohangrr Group Title
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    can u give a solution in one comment

    • 2 years ago
  32. Rohangrr Group Title
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    plzzz @baddinlol or @Ganpat

    • 2 years ago
  33. baddinlol Group Title
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    x = 0.5*0.2*(300^2)= 9000m

    • 2 years ago
  34. Rohangrr Group Title
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    @lgbasallote plzzz help

    • 2 years ago
  35. Ganpat Group Title
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    @Rohangrr : what exactly u want ?? speed = 60m/s and distance traveled in 5 min = 9000m... at uniform acceleration of 0.2 m/s2

    • 2 years ago
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