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Rohangrr

A train starting from rest is moving with a uniform acceleration of 0.2 m/s^2 for 5 mins , Calculate the speed acquired and the distance traveled in this time... @Shane_B @angela210793 @lgbasallote @baddinlol

  • one year ago
  • one year ago

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  1. Ganpat
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    in what time ?? i mean how much time.. ??

    • one year ago
  2. Ganpat
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    a= (v - u)/ t.. this might help..

    • one year ago
  3. Rohangrr
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    \[\huge NOW??\]

    • one year ago
  4. Rohangrr
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    you can solve it further @Ganpat

    • one year ago
  5. Ganpat
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    k, so t = 5 min.. a= 0.2, u = 0 and v = ?? so, 0.2 = (v-0)/ (5* 30) v = 150 * 0.2 V = 75 m /s..

    • one year ago
  6. Rohangrr
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    okay is that alllllll

    • one year ago
  7. Rohangrr
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    @baddinlol is he correct

    • one year ago
  8. baddinlol
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    @Ganpat, doesn't time have to be in seconds?

    • one year ago
  9. Rohangrr
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    okay

    • one year ago
  10. baddinlol
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    You used it in minutes..

    • one year ago
  11. Rohangrr
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    Your answer

    • one year ago
  12. baddinlol
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    Wait let me solve it.

    • one year ago
  13. baddinlol
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    For speed required

    • one year ago
  14. Ganpat
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    @baddinlol: yes, so i multiplied t by 60..

    • one year ago
  15. baddinlol
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    Use v = u + at

    • one year ago
  16. Ganpat
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    i have done calculation mistake.. sorry

    • one year ago
  17. baddinlol
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    ohh...

    • one year ago
  18. Ganpat
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    k, so t = 5 min.. a= 0.2, u = 0 and v = ?? so, 0.2 = (v-0)/ (5* 60) v = 300 * 0.2 V = 150 m /s.. this is right

    • one year ago
  19. Rohangrr
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    ooooooooppppppssssssssss

    • one year ago
  20. Rohangrr
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    |dw:1342008049684:dw|

    • one year ago
  21. baddinlol
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    Still wrong?

    • one year ago
  22. baddinlol
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    v = u + at = 300*0.2 = 60m/s

    • one year ago
  23. Rohangrr
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    okay then

    • one year ago
  24. Ganpat
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    ha ha, sorry, guys little messed up..

    • one year ago
  25. Rohangrr
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    lol

    • one year ago
  26. Rohangrr
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    its all f9999

    • one year ago
  27. baddinlol
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    Ok so you need to find distance now

    • one year ago
  28. baddinlol
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    Use x = ut+0.5at^2

    • one year ago
  29. Ganpat
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    x = ut + 1/2 * at2..

    • one year ago
  30. baddinlol
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    x = 0.5*0.2*(300^2)= 9000m

    • one year ago
  31. Rohangrr
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    can u give a solution in one comment

    • one year ago
  32. Rohangrr
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    plzzz @baddinlol or @Ganpat

    • one year ago
  33. baddinlol
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    x = 0.5*0.2*(300^2)= 9000m

    • one year ago
  34. Rohangrr
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    @lgbasallote plzzz help

    • one year ago
  35. Ganpat
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    @Rohangrr : what exactly u want ?? speed = 60m/s and distance traveled in 5 min = 9000m... at uniform acceleration of 0.2 m/s2

    • one year ago
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