anonymous
  • anonymous
A train starting from rest is moving with a uniform acceleration of 0.2 m/s^2 for 5 mins , Calculate the speed acquired and the distance traveled in this time... @Shane_B @angela210793 @lgbasallote @baddinlol
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Ganpat
  • Ganpat
in what time ?? i mean how much time.. ??
Ganpat
  • Ganpat
a= (v - u)/ t.. this might help..
anonymous
  • anonymous
\[\huge NOW??\]

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More answers

anonymous
  • anonymous
you can solve it further @Ganpat
Ganpat
  • Ganpat
k, so t = 5 min.. a= 0.2, u = 0 and v = ?? so, 0.2 = (v-0)/ (5* 30) v = 150 * 0.2 V = 75 m /s..
anonymous
  • anonymous
okay is that alllllll
anonymous
  • anonymous
@baddinlol is he correct
anonymous
  • anonymous
@Ganpat, doesn't time have to be in seconds?
anonymous
  • anonymous
okay
anonymous
  • anonymous
You used it in minutes..
anonymous
  • anonymous
Your answer
anonymous
  • anonymous
Wait let me solve it.
anonymous
  • anonymous
For speed required
Ganpat
  • Ganpat
@baddinlol: yes, so i multiplied t by 60..
anonymous
  • anonymous
Use v = u + at
Ganpat
  • Ganpat
i have done calculation mistake.. sorry
anonymous
  • anonymous
ohh...
Ganpat
  • Ganpat
k, so t = 5 min.. a= 0.2, u = 0 and v = ?? so, 0.2 = (v-0)/ (5* 60) v = 300 * 0.2 V = 150 m /s.. this is right
anonymous
  • anonymous
ooooooooppppppssssssssss
anonymous
  • anonymous
|dw:1342008049684:dw|
anonymous
  • anonymous
Still wrong?
anonymous
  • anonymous
v = u + at = 300*0.2 = 60m/s
anonymous
  • anonymous
okay then
Ganpat
  • Ganpat
ha ha, sorry, guys little messed up..
anonymous
  • anonymous
lol
anonymous
  • anonymous
its all f9999
anonymous
  • anonymous
Ok so you need to find distance now
anonymous
  • anonymous
Use x = ut+0.5at^2
Ganpat
  • Ganpat
x = ut + 1/2 * at2..
anonymous
  • anonymous
x = 0.5*0.2*(300^2)= 9000m
anonymous
  • anonymous
can u give a solution in one comment
anonymous
  • anonymous
plzzz @baddinlol or @Ganpat
anonymous
  • anonymous
x = 0.5*0.2*(300^2)= 9000m
anonymous
  • anonymous
@lgbasallote plzzz help
Ganpat
  • Ganpat
@Rohangrr : what exactly u want ?? speed = 60m/s and distance traveled in 5 min = 9000m... at uniform acceleration of 0.2 m/s2

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