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Rohangrr

  • 3 years ago

A train starting from rest is moving with a uniform acceleration of 0.2 m/s^2 for 5 mins , Calculate the speed acquired and the distance traveled in this time... @Shane_B @angela210793 @lgbasallote @baddinlol

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  1. Ganpat
    • 3 years ago
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    in what time ?? i mean how much time.. ??

  2. Ganpat
    • 3 years ago
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    a= (v - u)/ t.. this might help..

  3. Rohangrr
    • 3 years ago
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    \[\huge NOW??\]

  4. Rohangrr
    • 3 years ago
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    you can solve it further @Ganpat

  5. Ganpat
    • 3 years ago
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    k, so t = 5 min.. a= 0.2, u = 0 and v = ?? so, 0.2 = (v-0)/ (5* 30) v = 150 * 0.2 V = 75 m /s..

  6. Rohangrr
    • 3 years ago
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    okay is that alllllll

  7. Rohangrr
    • 3 years ago
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    @baddinlol is he correct

  8. baddinlol
    • 3 years ago
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    @Ganpat, doesn't time have to be in seconds?

  9. Rohangrr
    • 3 years ago
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    okay

  10. baddinlol
    • 3 years ago
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    You used it in minutes..

  11. Rohangrr
    • 3 years ago
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    Your answer

  12. baddinlol
    • 3 years ago
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    Wait let me solve it.

  13. baddinlol
    • 3 years ago
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    For speed required

  14. Ganpat
    • 3 years ago
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    @baddinlol: yes, so i multiplied t by 60..

  15. baddinlol
    • 3 years ago
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    Use v = u + at

  16. Ganpat
    • 3 years ago
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    i have done calculation mistake.. sorry

  17. baddinlol
    • 3 years ago
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    ohh...

  18. Ganpat
    • 3 years ago
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    k, so t = 5 min.. a= 0.2, u = 0 and v = ?? so, 0.2 = (v-0)/ (5* 60) v = 300 * 0.2 V = 150 m /s.. this is right

  19. Rohangrr
    • 3 years ago
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    ooooooooppppppssssssssss

  20. Rohangrr
    • 3 years ago
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    |dw:1342008049684:dw|

  21. baddinlol
    • 3 years ago
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    Still wrong?

  22. baddinlol
    • 3 years ago
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    v = u + at = 300*0.2 = 60m/s

  23. Rohangrr
    • 3 years ago
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    okay then

  24. Ganpat
    • 3 years ago
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    ha ha, sorry, guys little messed up..

  25. Rohangrr
    • 3 years ago
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    lol

  26. Rohangrr
    • 3 years ago
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    its all f9999

  27. baddinlol
    • 3 years ago
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    Ok so you need to find distance now

  28. baddinlol
    • 3 years ago
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    Use x = ut+0.5at^2

  29. Ganpat
    • 3 years ago
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    x = ut + 1/2 * at2..

  30. baddinlol
    • 3 years ago
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    x = 0.5*0.2*(300^2)= 9000m

  31. Rohangrr
    • 3 years ago
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    can u give a solution in one comment

  32. Rohangrr
    • 3 years ago
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    plzzz @baddinlol or @Ganpat

  33. baddinlol
    • 3 years ago
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    x = 0.5*0.2*(300^2)= 9000m

  34. Rohangrr
    • 3 years ago
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    @lgbasallote plzzz help

  35. Ganpat
    • 3 years ago
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    @Rohangrr : what exactly u want ?? speed = 60m/s and distance traveled in 5 min = 9000m... at uniform acceleration of 0.2 m/s2

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