## Rohangrr 3 years ago A train starting from rest is moving with a uniform acceleration of 0.2 m/s^2 for 5 mins , Calculate the speed acquired and the distance traveled in this time... @Shane_B @angela210793 @lgbasallote @baddinlol

1. Ganpat

in what time ?? i mean how much time.. ??

2. Ganpat

a= (v - u)/ t.. this might help..

3. Rohangrr

\[\huge NOW??\]

4. Rohangrr

you can solve it further @Ganpat

5. Ganpat

k, so t = 5 min.. a= 0.2, u = 0 and v = ?? so, 0.2 = (v-0)/ (5* 30) v = 150 * 0.2 V = 75 m /s..

6. Rohangrr

okay is that alllllll

7. Rohangrr

@Ganpat, doesn't time have to be in seconds?

9. Rohangrr

okay

You used it in minutes..

11. Rohangrr

Wait let me solve it.

For speed required

14. Ganpat

@baddinlol: yes, so i multiplied t by 60..

Use v = u + at

16. Ganpat

i have done calculation mistake.. sorry

ohh...

18. Ganpat

k, so t = 5 min.. a= 0.2, u = 0 and v = ?? so, 0.2 = (v-0)/ (5* 60) v = 300 * 0.2 V = 150 m /s.. this is right

19. Rohangrr

ooooooooppppppssssssssss

20. Rohangrr

|dw:1342008049684:dw|

Still wrong?

v = u + at = 300*0.2 = 60m/s

23. Rohangrr

okay then

24. Ganpat

ha ha, sorry, guys little messed up..

25. Rohangrr

lol

26. Rohangrr

its all f9999

Ok so you need to find distance now

Use x = ut+0.5at^2

29. Ganpat

x = ut + 1/2 * at2..

x = 0.5*0.2*(300^2)= 9000m

31. Rohangrr

can u give a solution in one comment

32. Rohangrr

x = 0.5*0.2*(300^2)= 9000m

34. Rohangrr

@lgbasallote plzzz help

35. Ganpat

@Rohangrr : what exactly u want ?? speed = 60m/s and distance traveled in 5 min = 9000m... at uniform acceleration of 0.2 m/s2