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2_jenny_9

  • 3 years ago

How do you integrate this using substitution ? ∫sin (3pi/2 + pi/4)dx

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  1. lgbasallote
    • 3 years ago
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    \[\large\int \sin (\frac{3\pi}{2} +\frac{\pi}{4})dx?\]

  2. Mimi_x3
    • 3 years ago
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    I think it's missing a \(x\)

  3. 2_jenny_9
    • 3 years ago
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    yea thats the question

  4. baddinlol
    • 3 years ago
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    Would the answer be sqrt(2)/2 x?

  5. 2_jenny_9
    • 3 years ago
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    the answer at the back is -2/3pi cos (3pi/2 + pi/4) +c

  6. Mimi_x3
    • 3 years ago
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    Are you sure that it's \[\int sin\left(\frac{3\pi}{2}+\frac{\pi}{4}\right) dx\]?? I think that it's missing a \(x\) somewhere

  7. 2_jenny_9
    • 3 years ago
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    yea thats the question

  8. baddinlol
    • 3 years ago
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    Ok so the answer is -sqrt(2)/2 x

  9. baddinlol
    • 3 years ago
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    Just simplify sin ( (3pi/2) + (pi/4))

  10. baddinlol
    • 3 years ago
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    sin ((3pi/2) + (pi/4)) = -sin(pi/4)

  11. baddinlol
    • 3 years ago
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    Then if you remember your exact values, sin(pi/4) = sqrt(2)/2

  12. baddinlol
    • 3 years ago
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    So -sin(pi/4) = -sqrt(2)/2

  13. baddinlol
    • 3 years ago
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    Then integrate sqrt(2)/2

  14. baddinlol
    • 3 years ago
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    I mean integrate -sqrt(2)/2 with respect to x

  15. baddinlol
    • 3 years ago
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    You will get integral(sin ( (3pi/2) + (pi/4))) = -sqrt(2)/2 x

  16. 2_jenny_9
    • 3 years ago
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    thank you :)

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