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How do you integrate this using substitution ?
∫sin (3pi/2 + pi/4)dx
 one year ago
 one year ago
How do you integrate this using substitution ? ∫sin (3pi/2 + pi/4)dx
 one year ago
 one year ago

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lgbasalloteBest ResponseYou've already chosen the best response.0
\[\large\int \sin (\frac{3\pi}{2} +\frac{\pi}{4})dx?\]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.0
I think it's missing a \(x\)
 one year ago

2_jenny_9Best ResponseYou've already chosen the best response.0
yea thats the question
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
Would the answer be sqrt(2)/2 x?
 one year ago

2_jenny_9Best ResponseYou've already chosen the best response.0
the answer at the back is 2/3pi cos (3pi/2 + pi/4) +c
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.0
Are you sure that it's \[\int sin\left(\frac{3\pi}{2}+\frac{\pi}{4}\right) dx\]?? I think that it's missing a \(x\) somewhere
 one year ago

2_jenny_9Best ResponseYou've already chosen the best response.0
yea thats the question
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
Ok so the answer is sqrt(2)/2 x
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
Just simplify sin ( (3pi/2) + (pi/4))
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
sin ((3pi/2) + (pi/4)) = sin(pi/4)
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
Then if you remember your exact values, sin(pi/4) = sqrt(2)/2
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
So sin(pi/4) = sqrt(2)/2
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
Then integrate sqrt(2)/2
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
I mean integrate sqrt(2)/2 with respect to x
 one year ago

baddinlolBest ResponseYou've already chosen the best response.1
You will get integral(sin ( (3pi/2) + (pi/4))) = sqrt(2)/2 x
 one year ago
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