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2_jenny_9

How do you integrate this using substitution ? ∫sin (3pi/2 + pi/4)dx

  • one year ago
  • one year ago

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  1. lgbasallote
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    \[\large\int \sin (\frac{3\pi}{2} +\frac{\pi}{4})dx?\]

    • one year ago
  2. Mimi_x3
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    I think it's missing a \(x\)

    • one year ago
  3. 2_jenny_9
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    yea thats the question

    • one year ago
  4. baddinlol
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    Would the answer be sqrt(2)/2 x?

    • one year ago
  5. 2_jenny_9
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    the answer at the back is -2/3pi cos (3pi/2 + pi/4) +c

    • one year ago
  6. Mimi_x3
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    Are you sure that it's \[\int sin\left(\frac{3\pi}{2}+\frac{\pi}{4}\right) dx\]?? I think that it's missing a \(x\) somewhere

    • one year ago
  7. 2_jenny_9
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    yea thats the question

    • one year ago
  8. baddinlol
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    Ok so the answer is -sqrt(2)/2 x

    • one year ago
  9. baddinlol
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    Just simplify sin ( (3pi/2) + (pi/4))

    • one year ago
  10. baddinlol
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    sin ((3pi/2) + (pi/4)) = -sin(pi/4)

    • one year ago
  11. baddinlol
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    Then if you remember your exact values, sin(pi/4) = sqrt(2)/2

    • one year ago
  12. baddinlol
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    So -sin(pi/4) = -sqrt(2)/2

    • one year ago
  13. baddinlol
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    Then integrate sqrt(2)/2

    • one year ago
  14. baddinlol
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    I mean integrate -sqrt(2)/2 with respect to x

    • one year ago
  15. baddinlol
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    You will get integral(sin ( (3pi/2) + (pi/4))) = -sqrt(2)/2 x

    • one year ago
  16. 2_jenny_9
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    thank you :)

    • one year ago
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