anonymous
  • anonymous
How do you integrate this using substitution ? ∫sin (3pi/2 + pi/4)dx
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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lgbasallote
  • lgbasallote
\[\large\int \sin (\frac{3\pi}{2} +\frac{\pi}{4})dx?\]
Mimi_x3
  • Mimi_x3
I think it's missing a \(x\)
anonymous
  • anonymous
yea thats the question

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anonymous
  • anonymous
Would the answer be sqrt(2)/2 x?
anonymous
  • anonymous
the answer at the back is -2/3pi cos (3pi/2 + pi/4) +c
Mimi_x3
  • Mimi_x3
Are you sure that it's \[\int sin\left(\frac{3\pi}{2}+\frac{\pi}{4}\right) dx\]?? I think that it's missing a \(x\) somewhere
anonymous
  • anonymous
yea thats the question
anonymous
  • anonymous
Ok so the answer is -sqrt(2)/2 x
anonymous
  • anonymous
Just simplify sin ( (3pi/2) + (pi/4))
anonymous
  • anonymous
sin ((3pi/2) + (pi/4)) = -sin(pi/4)
anonymous
  • anonymous
Then if you remember your exact values, sin(pi/4) = sqrt(2)/2
anonymous
  • anonymous
So -sin(pi/4) = -sqrt(2)/2
anonymous
  • anonymous
Then integrate sqrt(2)/2
anonymous
  • anonymous
I mean integrate -sqrt(2)/2 with respect to x
anonymous
  • anonymous
You will get integral(sin ( (3pi/2) + (pi/4))) = -sqrt(2)/2 x
anonymous
  • anonymous
thank you :)

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