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Rohangrr Group Title

SIMPLE QUESTIONS FOR YOU ALL A bus was moving at a speed of 54 km/h. on applying brakes, it stopped in 8 seconds. calculate the speed acquired and distance traveled in this time.

  • 2 years ago
  • 2 years ago

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  1. baddinlol Group Title
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    The speed acquired is 0m/s

    • 2 years ago
  2. apoorvk Group Title
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    Speed acquired?????

    • 2 years ago
  3. baddinlol Group Title
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    Because the bus stopped

    • 2 years ago
  4. apoorvk Group Title
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    That be zero, since it stops!

    • 2 years ago
  5. Rohangrr Group Title
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    plzzz do show u r solutions

    • 2 years ago
  6. baddinlol Group Title
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    distance use, x = v=0.5(u+v)t

    • 2 years ago
  7. Rohangrr Group Title
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    give answer in one comment please its my request

    • 2 years ago
  8. baddinlol Group Title
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    So x = 0.5* 15 * 8 = 60m

    • 2 years ago
  9. apoorvk Group Title
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    Well, you have initial velocity = u = 54 kmph = 54 x (5/18) m/sec = 15 m/sec Final velocity = v = 0 Time = 8 seconds. Use Newton Unkle's equation # 1 ---> \( a = \frac{v-u}{t}\), and fond out the deceleration 'a'. Then, use \(v^2 - u^2 = 2as\) to find out the distance covered, i.e. 's'.

    • 2 years ago
  10. apoorvk Group Title
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    (Note of precaution: Newton's equations are only valid for uniform-linear motion, as you may know.)

    • 2 years ago
  11. King Group Title
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    sry... use \[x=\frac{v+u}{2} \times t\]

    • 2 years ago
  12. Rohangrr Group Title
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    thanks aproov it proved my solution was wrong

    • 2 years ago
  13. King Group Title
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    where v is final speed=0 u is initial speed=15 and t=8

    • 2 years ago
  14. apoorvk Group Title
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    Yeah, using the average velocity funda is good actually, @King

    • 2 years ago
  15. Rohangrr Group Title
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    oKAY thanks king to u as well

    • 2 years ago
  16. apoorvk Group Title
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    In fact innovative. :]

    • 2 years ago
  17. King Group Title
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    yw...thnx @apoorvk

    • 2 years ago
  18. Rohangrr Group Title
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    lol

    • 2 years ago
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