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Rohangrr

  • 3 years ago

SIMPLE QUESTIONS FOR YOU ALL A bus was moving at a speed of 54 km/h. on applying brakes, it stopped in 8 seconds. calculate the speed acquired and distance traveled in this time.

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  1. baddinlol
    • 3 years ago
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    The speed acquired is 0m/s

  2. apoorvk
    • 3 years ago
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    Speed acquired?????

  3. baddinlol
    • 3 years ago
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    Because the bus stopped

  4. apoorvk
    • 3 years ago
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    That be zero, since it stops!

  5. Rohangrr
    • 3 years ago
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    plzzz do show u r solutions

  6. baddinlol
    • 3 years ago
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    distance use, x = v=0.5(u+v)t

  7. Rohangrr
    • 3 years ago
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    give answer in one comment please its my request

  8. baddinlol
    • 3 years ago
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    So x = 0.5* 15 * 8 = 60m

  9. apoorvk
    • 3 years ago
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    Well, you have initial velocity = u = 54 kmph = 54 x (5/18) m/sec = 15 m/sec Final velocity = v = 0 Time = 8 seconds. Use Newton Unkle's equation # 1 ---> \( a = \frac{v-u}{t}\), and fond out the deceleration 'a'. Then, use \(v^2 - u^2 = 2as\) to find out the distance covered, i.e. 's'.

  10. apoorvk
    • 3 years ago
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    (Note of precaution: Newton's equations are only valid for uniform-linear motion, as you may know.)

  11. King
    • 3 years ago
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    sry... use \[x=\frac{v+u}{2} \times t\]

  12. Rohangrr
    • 3 years ago
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    thanks aproov it proved my solution was wrong

  13. King
    • 3 years ago
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    where v is final speed=0 u is initial speed=15 and t=8

  14. apoorvk
    • 3 years ago
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    Yeah, using the average velocity funda is good actually, @King

  15. Rohangrr
    • 3 years ago
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    oKAY thanks king to u as well

  16. apoorvk
    • 3 years ago
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    In fact innovative. :]

  17. King
    • 3 years ago
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    yw...thnx @apoorvk

  18. Rohangrr
    • 3 years ago
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    lol

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