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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
you cannot, at least you cannot using rational numbers
 2 years ago

fluffyunicorn Group TitleBest ResponseYou've already chosen the best response.0
how do you solve it with quadratic formula? i dont think my answer was right?
 2 years ago

Monkeyball Group TitleBest ResponseYou've already chosen the best response.0
\[y=0.05x^2x+1 \] \[\begin{array}{*{20}c} {x = \frac{{  b \pm \sqrt {b^2  4ac} }}{{2a}}} & {{\rm{when}}} & {ax^2 + bx + c = 0} \\ \end{array} \]
 2 years ago

Monkeyball Group TitleBest ResponseYou've already chosen the best response.0
in this case a=0.05 b=1 c=1
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
if it was me, i would multiply everything by 20 and write \[x^220x+20=0\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
makes life a lot easier to deal with whole numbers instead of decimals
 2 years ago

Monkeyball Group TitleBest ResponseYou've already chosen the best response.0
so I did it wrong?
 2 years ago

fluffyunicorn Group TitleBest ResponseYou've already chosen the best response.0
i know the formula but after i did it it looked wrong i got 1+(sr).8/.1
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
no it is just easier if it is not clear where i got the 20 from, lets clear the decimal by multiplying everything by 100 you get \[5x^2100x+100=0\] then divide by 5 and get \[x^220x+20=0\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
you really do not want to take square roots of decimals or divide by decimals use whole numbers
 2 years ago

fluffyunicorn Group TitleBest ResponseYou've already chosen the best response.0
alright thank you!
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
for \[x^220x+20=0\] it is probably easiest to complete the square because 20 is even i would write \[x^220x+20=0\] \[x^220x=20\] \[(x10)^2=20+100=80\] \[x10=\pm\sqrt{80}=4\sqrt{5}\] \[x=10\pm4\sqrt{5}\]
 2 years ago

fluffyunicorn Group TitleBest ResponseYou've already chosen the best response.0
And its not factorable right?
 2 years ago
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