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anonymous
 4 years ago
the front row of a stadium has 25 seats. each of the other rows has two more seats than the row in front of it. how many seats are there altogether in the first 20 rows?
anonymous
 4 years ago
the front row of a stadium has 25 seats. each of the other rows has two more seats than the row in front of it. how many seats are there altogether in the first 20 rows?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh wow, thanks for the quick response!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@timo86m :can u explain how did u get that ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im studying for the SATs and am struggling greatly with permutations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Megichu : U know A.Sequence basics ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02+2+2+2...=19*2 =38 25+(19*25)+38

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i understand what the basic formula is, but interpreting the problem at times can be difficult

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1342034133001:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Front row=a=first term=25. Each of the other rows has two more seats than the row in front of it ,thats mean that the difference between every two rows is 2 ,So d=2 ========================= a=25 ,d=2 Sum law : Sn=n/2[2a+(n1)d] where n = number of terms .. now lets fill up the rule S20=20/2 [2*25+(201)2]=880 seats .  Make sense ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0perfect. thank you so much for the great response! and yes, that makes much more sense

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Great,Inform me when you need help :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not sure why i have such a difficult time with these problems (considering that their are 2 main formulas XD) but i really appreciate the help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0also, this site is great. i look forward to using it more often!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just keep solving examples ,Then it will get much easier :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0definitely doing a lot of that right now! haha im taking an SAT course right now and have a packet to practice all of these lovely problems :3
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