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Calculate the following limit: lim h→0 (4 + h)3− 64 over h

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Ok Here is your problem : \[\Large lim h-->0 \frac{(f+h)^3-64}{h}\]
expand the cubic \[\lim_{h \rightarrow 0}\frac{64 + 48h + 12h^2 + h^3 - 64}{h}\] which simplifes to \[\lim_{h \rightarrow 0}\frac{48h + 12h^2 + h^3}{h}\] take out the common factor of h leaves \[\lim_{h \rightarrow 0} 48 + 12h + h^2\] give the limit of 48

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Other answers:

Here is a Hint : ______________ Add 4 and subtract 4 from the denominator : it will be \[\Large \frac{(4+h)^3-4^3}{(4+h)-4}\] Now its easy : The answer is 3/1*4^(3-1)=48
thanks yall

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