Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

hooverst

  • 3 years ago

Calculate the following limit: lim h→0 (4 + h)3− 64 over h

  • This Question is Closed
  1. Eyad
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok Here is your problem : \[\Large lim h-->0 \frac{(f+h)^3-64}{h}\]

  2. Eyad
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    64=4^3

  3. campbell_st
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    expand the cubic \[\lim_{h \rightarrow 0}\frac{64 + 48h + 12h^2 + h^3 - 64}{h}\] which simplifes to \[\lim_{h \rightarrow 0}\frac{48h + 12h^2 + h^3}{h}\] take out the common factor of h leaves \[\lim_{h \rightarrow 0} 48 + 12h + h^2\] give the limit of 48

  4. Eyad
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Here is a Hint : ______________ Add 4 and subtract 4 from the denominator : it will be \[\Large \frac{(4+h)^3-4^3}{(4+h)-4}\] Now its easy : The answer is 3/1*4^(3-1)=48

  5. hooverst
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks yall

  6. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy