anonymous
  • anonymous
Almost done!!!!
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
anonymous
  • anonymous
hmmm,Let's start by finding the area of a a semicircle with the tiled part
anonymous
  • anonymous
A=(pi*r^2)/2=(25pi)/2 ...

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anonymous
  • anonymous
Now find the area of just that untiled part: A=(pi*3.5^2)/2
anonymous
  • anonymous
Since if the radius is 5 and the width is 1.5 u'll subtract the width from the radius. Can you finish this off?

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