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on behalf of @jrzyby1 solve the system x+4y-z=3 (1) x+5y-2z=5 (2) 3x+12y-3z=9 (3)

Mathematics
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x + 4y - z = 3 x + 5y - 2z = 5 subtract the equations 9y + z = -2 <-- (4)
times the first equation by three, then find the difference with the third equation
(1),(3) are the same

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Other answers:

infinite solutions
Since 1 and 3 are the same, aren't there an infinite number of solutions?
hmm yep equation 1 and 3 wont intersect
gotcha.
there is an infinite line of solutions
I wass't sure and I tried to put the second equation into the first to see if it could be worked, hence the origin of all this. lol
cool. thank you much
@jrzyby1 fyi to ask a new question you will have to close your old post (which I think you left open)

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