TuringTest
on behalf of @jrzyby1
solve the system
x+4yz=3 (1)
x+5y2z=5 (2)
3x+12y3z=9 (3)



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lgbasallote
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x + 4y  z = 3
x + 5y  2z = 5
subtract the equations
9y + z = 2 < (4)

UnkleRhaukus
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times the first equation by three,
then find the difference with the third equation

UnkleRhaukus
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(1),(3) are the same

UnkleRhaukus
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infinite solutions

emcwhat
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Since 1 and 3 are the same, aren't there an infinite number of solutions?

lgbasallote
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hmm yep equation 1 and 3 wont intersect

jrzyby1
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gotcha.

UnkleRhaukus
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there is an infinite line of solutions

jrzyby1
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I wass't sure and I tried to put the second equation into the first to see if it could be worked, hence the origin of all this. lol

jrzyby1
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cool. thank you much

TuringTest
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@jrzyby1 fyi to ask a new question you will have to close your old post (which I think you left open)