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TuringTestBest ResponseYou've already chosen the best response.2
what? no it's a math Q
 one year ago

pratu043Best ResponseYou've already chosen the best response.0
Diverge means separate, converge means meet.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
converge is to "settle down" on a finite falue
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
oh jeez, an algebra2 definition of "diverge" ? I kind of would like to know the context
 one year ago

hbaBest ResponseYou've already chosen the best response.0
@pratu043 it is maths not physics
 one year ago

petegutzBest ResponseYou've already chosen the best response.0
heres what the question is 1/5+1/25+1/125+1/625... Does the infinite geometric series converge or diverge?explain
 one year ago

MonkeyballBest ResponseYou've already chosen the best response.1
Does it go to infinity?
 one year ago

MonkeyballBest ResponseYou've already chosen the best response.1
Or does it go to a specific value?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
or does it settle on no value at all and oscillate forever?
 one year ago

nbouscalBest ResponseYou've already chosen the best response.1
Algebra 2 is an interesting time to learn about this. You should at least see the formal definition, so here's that (in my words): A sequence \(a_n\) converges to a limit \(L\) iff for any given \(\epsilon\), there exists an \(N\) such that \(n>N\implies a_nL<\epsilon\). That's the formal one. In english, that means, as you go on to infinity, the sequence gets as close as you like to a given value. Basically, like others have said, the sequence "settles down" to a value. Diverges simply means "does not converge."
 one year ago

MonkeyballBest ResponseYou've already chosen the best response.1
no it does not.....the reason being that the denominator is getting bigger which means that the overall number is getting smaller.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
@nbouscal I wish they taught me that in algebra2, but I don't think so...
 one year ago

MonkeyballBest ResponseYou've already chosen the best response.1
If it went to infinity then the sequence will increase exponentially
 one year ago

nbouscalBest ResponseYou've already chosen the best response.1
Oh no, I'm sure they don't. They would never do something crazy like teach real mathematics to secondary school students :P
 one year ago

nbouscalBest ResponseYou've already chosen the best response.1
Not saying I know pedagogy better than they do, but couldn't they at least flash it on the board? One slide of a powerpoint? No? *sigh* oh well.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
exactly^ @petegutz do you have a specific formula to use? there are a few...
 one year ago

petegutzBest ResponseYou've already chosen the best response.0
no all that it gave me was what i put up
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
\[\sum_{n=1}^\infty ar^{n1}=\sum_{n=0}^\infty ar^n=\frac a{1r}\]is maybe a formula you can use?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
the above is only true for \(r<1\), otherwise the series diverges so you must identify }r in your series
 one year ago

petegutzBest ResponseYou've already chosen the best response.0
so it converges and it has a sum right?
 one year ago
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