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TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2what? no it's a math Q

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0Diverge means separate, converge means meet.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2converge is to "settle down" on a finite falue

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2oh jeez, an algebra2 definition of "diverge" ? I kind of would like to know the context

hba
 2 years ago
Best ResponseYou've already chosen the best response.0@pratu043 it is maths not physics

petegutz
 2 years ago
Best ResponseYou've already chosen the best response.0heres what the question is 1/5+1/25+1/125+1/625... Does the infinite geometric series converge or diverge?explain

Monkeyball
 2 years ago
Best ResponseYou've already chosen the best response.1Does it go to infinity?

Monkeyball
 2 years ago
Best ResponseYou've already chosen the best response.1Or does it go to a specific value?

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2or does it settle on no value at all and oscillate forever?

nbouscal
 2 years ago
Best ResponseYou've already chosen the best response.1Algebra 2 is an interesting time to learn about this. You should at least see the formal definition, so here's that (in my words): A sequence \(a_n\) converges to a limit \(L\) iff for any given \(\epsilon\), there exists an \(N\) such that \(n>N\implies a_nL<\epsilon\). That's the formal one. In english, that means, as you go on to infinity, the sequence gets as close as you like to a given value. Basically, like others have said, the sequence "settles down" to a value. Diverges simply means "does not converge."

Monkeyball
 2 years ago
Best ResponseYou've already chosen the best response.1no it does not.....the reason being that the denominator is getting bigger which means that the overall number is getting smaller.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2@nbouscal I wish they taught me that in algebra2, but I don't think so...

Monkeyball
 2 years ago
Best ResponseYou've already chosen the best response.1If it went to infinity then the sequence will increase exponentially

nbouscal
 2 years ago
Best ResponseYou've already chosen the best response.1Oh no, I'm sure they don't. They would never do something crazy like teach real mathematics to secondary school students :P

nbouscal
 2 years ago
Best ResponseYou've already chosen the best response.1Not saying I know pedagogy better than they do, but couldn't they at least flash it on the board? One slide of a powerpoint? No? *sigh* oh well.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2exactly^ @petegutz do you have a specific formula to use? there are a few...

petegutz
 2 years ago
Best ResponseYou've already chosen the best response.0no all that it gave me was what i put up

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2\[\sum_{n=1}^\infty ar^{n1}=\sum_{n=0}^\infty ar^n=\frac a{1r}\]is maybe a formula you can use?

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2the above is only true for \(r<1\), otherwise the series diverges so you must identify }r in your series

petegutz
 2 years ago
Best ResponseYou've already chosen the best response.0so it converges and it has a sum right?
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