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anonymous
 3 years ago
Find the value of x: 2x^3  5x^2  x + 20 = 0
anonymous
 3 years ago
Find the value of x: 2x^3  5x^2  x + 20 = 0

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0would you like to go for a trignometric solution ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I just need the value of x :o the answers have 2 x values. Its a whole different equation but Ive added everything and I just needed help on finding the x values of this because It confused me

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you want soln,,i can provide hint : see shubhamsrg's soln : http://openstudy.com/users/shubhamsrg#/updates/4fed5f8ae4b0bbec5cfcc1ac

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0first you have to convert the eqn into depressed but..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01: x= 4/3, x= 5 2: x= 4/3, x= 5 3:x= 4/3, x= 5 4:x= 4/3, x= 5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=2x%5E3%2B5x%5E2x%2B20%3D0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I tried plugging it into wolframalpha already.. didnt work _

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0didn't work! there the ans. given is 1.6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok that gives me one answer but :o

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I guess ill just try Plugging 5 and negative 5 into the original thing.. Thanks :p

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wait can Someone actually Help me? Cause Ive tried plugging the two 5's in but Its not equaling out. @Wired @JohnHanShanghai , the original equation is this,

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1342092140095:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0have you tried 2 and minus 2?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But thats not a possible answer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think Im retarded because either 5 or 5 have to work . But I tried and of course I did something wrong

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wolfram says 4/3 and 5. Must've done something wrong when solving the equation.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0there are 2 answers with 4/3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wait where does it say 5?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=%282%2F%28x2%29%29%2B%287%2F%28x%5E24%29%29%3D5%2Fx

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well I didnt put int he original equation but thank you ! Again lol (:

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The correct eq. is 3x^211x20=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{2}{x2}+\frac{7}{x^{2}4}=\frac{5}{x}\] \[\frac{x+2}{x+2}*\frac{2}{x2}+\frac{7}{x^{2}4}=\frac{5}{x}\] \[\frac{2x+4+7}{x^{2}4}=\frac{5}{x}\] \[2x^{2}+11x = 5x^{2}20\] \[3x^{2}11x20 = 0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0When in doubt, go back to the beginning :)
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