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Sgstudent
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Given that 5x^3 + 6x^2 x + 2 = (x+1) (x2) Q(x) + ax + b find the value of a and b.
Question on Identities :)
 2 years ago
 2 years ago
Sgstudent Group Title
Given that 5x^3 + 6x^2 x + 2 = (x+1) (x2) Q(x) + ax + b find the value of a and b. Question on Identities :)
 2 years ago
 2 years ago

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Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
Q(x) is an unknown polynomial?
 2 years ago

nphuongsun93 Group TitleBest ResponseYou've already chosen the best response.0
then... a = 1, b = 2?...dont think it should be this simple
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
that isnt the answer lol
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
answer is a = 20 b = 24
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
but i cant get it :(
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
if Q(x) = 5x9 ?
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
o..o maybe you could work out the full solution and see if it matches my answer :P
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
Thank you.
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
\[ (x+1)*(x+2)*(5*x9) = 5x^3 + 6x^2 17x  18 + 16x +20=5x^3 + 6x^2 x + 2\]
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
@Sgstudent
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
oo then how should i carry on
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
hmm a is 16 and b is 20 for me
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
check for any careless mistake? :O
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
no i don't think so
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
can you upload the picture of your working?
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
i didn't do it on my notebook, in head.
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
\[(x+1)(x+2)(5x−9) +ax + b = 5x^3+6x^2−17x−18+ ax+b\]
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
i did it also and got same result as ishaan
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
i need the working :(
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
or rather simple explanation towards the steps
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
equating coefficients of x gives 1 = 10  27 + a a = 2711 = 16
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
use q(x) as px +q, suggested by you earlier if you really need to show working
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
can i let Q(x) = px + q will i be able to get the answer?
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
oh but i cant seem to get the answer somehow :(
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
i get decimal numbers :(
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
show me your working i will try to guide you
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
kk i try again
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
well you can get multiple answers, maybe.
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
only a and b
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
(x+1) (x2) *********
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
Ishaan i edited the question
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
sry about it
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
i can see how ishaan got p = 5 because of the 5x^3 but the q = 9 is not obvious = 5x^3 + 15x^2 + 10x + qx^2 + 3qx + 2q + ax + b = 5x^3 + (15 + q)x^2 + (10 + 3q + a)x + 2q + b compare coefficients with 5x^3 + 6x^2  x + 2 of x^2: q + 15 = 6 so q = 9 of x: 10 + a + 3q = 10 + a  27 = a  17 and a 17 = 1 so a = 16 of x^0 : 2q + b = 2 so 18 + b = 2 so b = 20 a=16, b = 20
 2 years ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
Thanks :)
 2 years ago
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