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Q(x) is an unknown polynomial?

yea

then... a = -1, b = 2?...dont think it should be this simple

that isnt the answer lol

answer is a = 20 b = 24

but i cant get it :(

if Q(x) = 5x-9 ?

o..o maybe you could work out the full solution and see if it matches my answer :P

Thank you.

\[ (x+1)*(x+2)*(5*x-9) = 5x^3 + 6x^2 -17x - 18 + 16x +20=5x^3 + 6x^2 -x + 2\]

oo then how should i carry on

hmm a is 16 and b is 20 for me

check for any careless mistake? :O

no i don't think so

can you upload the picture of your working?

i didn't do it on my notebook, in head.

\[(x+1)(x+2)(5x−9) +ax + b = 5x^3+6x^2−17x−18+ ax+b\]

i did it also and got same result as ishaan

i need the working :(

or rather simple explanation towards the steps

equating coefficients of x gives
-1 = 10 - 27 + a
a = 27-11 = 16

use q(x) as px +q, suggested by you earlier if you really need to show working

can i let Q(x) = px + q will i be able to get the answer?

oh but i cant seem to get the answer somehow :(

i get decimal numbers :(

show me your working i will try to guide you

kk i try again

well you can get multiple answers, maybe.

only a and b

(x+1) (x-2) *********

Ishaan i edited the question

sry about it

Thanks :)

yw