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Sgstudent
 3 years ago
Given that 5x^3 + 6x^2 x + 2 = (x+1) (x2) Q(x) + ax + b find the value of a and b.
Question on Identities :)
Sgstudent
 3 years ago
Given that 5x^3 + 6x^2 x + 2 = (x+1) (x2) Q(x) + ax + b find the value of a and b. Question on Identities :)

This Question is Closed

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.2Q(x) is an unknown polynomial?

nphuongsun93
 3 years ago
Best ResponseYou've already chosen the best response.0then... a = 1, b = 2?...dont think it should be this simple

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0that isnt the answer lol

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0answer is a = 20 b = 24

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0o..o maybe you could work out the full solution and see if it matches my answer :P

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.2\[ (x+1)*(x+2)*(5*x9) = 5x^3 + 6x^2 17x  18 + 16x +20=5x^3 + 6x^2 x + 2\]

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0oo then how should i carry on

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.2hmm a is 16 and b is 20 for me

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0check for any careless mistake? :O

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0can you upload the picture of your working?

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.2i didn't do it on my notebook, in head.

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.2\[(x+1)(x+2)(5x−9) +ax + b = 5x^3+6x^2−17x−18+ ax+b\]

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.2i did it also and got same result as ishaan

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0i need the working :(

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0or rather simple explanation towards the steps

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.2equating coefficients of x gives 1 = 10  27 + a a = 2711 = 16

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.2use q(x) as px +q, suggested by you earlier if you really need to show working

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0can i let Q(x) = px + q will i be able to get the answer?

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0oh but i cant seem to get the answer somehow :(

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0i get decimal numbers :(

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.2show me your working i will try to guide you

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.2well you can get multiple answers, maybe.

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0(x+1) (x2) *********

Sgstudent
 3 years ago
Best ResponseYou've already chosen the best response.0Ishaan i edited the question

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.2i can see how ishaan got p = 5 because of the 5x^3 but the q = 9 is not obvious = 5x^3 + 15x^2 + 10x + qx^2 + 3qx + 2q + ax + b = 5x^3 + (15 + q)x^2 + (10 + 3q + a)x + 2q + b compare coefficients with 5x^3 + 6x^2  x + 2 of x^2: q + 15 = 6 so q = 9 of x: 10 + a + 3q = 10 + a  27 = a  17 and a 17 = 1 so a = 16 of x^0 : 2q + b = 2 so 18 + b = 2 so b = 20 a=16, b = 20
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