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Given that 5x^3 + 6x^2 x + 2 = (x+1) (x2) Q(x) + ax + b find the value of a and b.
Question on Identities :)
 one year ago
 one year ago
Given that 5x^3 + 6x^2 x + 2 = (x+1) (x2) Q(x) + ax + b find the value of a and b. Question on Identities :)
 one year ago
 one year ago

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Ishaan94Best ResponseYou've already chosen the best response.2
Q(x) is an unknown polynomial?
 one year ago

nphuongsun93Best ResponseYou've already chosen the best response.0
then... a = 1, b = 2?...dont think it should be this simple
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
that isnt the answer lol
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
answer is a = 20 b = 24
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
but i cant get it :(
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
o..o maybe you could work out the full solution and see if it matches my answer :P
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.2
\[ (x+1)*(x+2)*(5*x9) = 5x^3 + 6x^2 17x  18 + 16x +20=5x^3 + 6x^2 x + 2\]
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
oo then how should i carry on
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.2
hmm a is 16 and b is 20 for me
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
check for any careless mistake? :O
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
can you upload the picture of your working?
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.2
i didn't do it on my notebook, in head.
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.2
\[(x+1)(x+2)(5x−9) +ax + b = 5x^3+6x^2−17x−18+ ax+b\]
 one year ago

cwrw238Best ResponseYou've already chosen the best response.2
i did it also and got same result as ishaan
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
i need the working :(
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
or rather simple explanation towards the steps
 one year ago

cwrw238Best ResponseYou've already chosen the best response.2
equating coefficients of x gives 1 = 10  27 + a a = 2711 = 16
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.2
use q(x) as px +q, suggested by you earlier if you really need to show working
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
can i let Q(x) = px + q will i be able to get the answer?
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
oh but i cant seem to get the answer somehow :(
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
i get decimal numbers :(
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.2
show me your working i will try to guide you
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.2
well you can get multiple answers, maybe.
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
(x+1) (x2) *********
 one year ago

SgstudentBest ResponseYou've already chosen the best response.0
Ishaan i edited the question
 one year ago

cwrw238Best ResponseYou've already chosen the best response.2
i can see how ishaan got p = 5 because of the 5x^3 but the q = 9 is not obvious = 5x^3 + 15x^2 + 10x + qx^2 + 3qx + 2q + ax + b = 5x^3 + (15 + q)x^2 + (10 + 3q + a)x + 2q + b compare coefficients with 5x^3 + 6x^2  x + 2 of x^2: q + 15 = 6 so q = 9 of x: 10 + a + 3q = 10 + a  27 = a  17 and a 17 = 1 so a = 16 of x^0 : 2q + b = 2 so 18 + b = 2 so b = 20 a=16, b = 20
 one year ago
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