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anonymous
 3 years ago
Find the volume of the solid formed when the area bound by the curve y=4x^2 and the x axis is rotated one complete revolution about the y axis
anonymous
 3 years ago
Find the volume of the solid formed when the area bound by the curve y=4x^2 and the x axis is rotated one complete revolution about the y axis

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0first find the critical points and use integration

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1or just consider one side of it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you just tell me the answer , because i am getting the wrong answer. I got 16 pi units but the answer is 8 pi units and i don't know where i went wrong.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1please dont ask for "just an answer"

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1342094312271:dw this can be done by shells or disks; which way are you most comfortable with?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1i think i know why youre twice as big as the answer; your prolly integrating the whole thing across

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1your in effect sweeping the same volume twice when you do that

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1342094460320:dw if we do shells:\[\int_{0}^{2}2pix(4x^2)dx\] \[2pi\int_{0}^{2}x(4x^2)dx\] \[2pi\int_{0}^{2}4xx^3\ dx\] \[2pi\left(\frac{1}{2}4x^2\frac{1}{4}x^4\right)_{0}^{2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh i think i understand. I apologise amistre64 if i sounded rude before. I had no intentions whatsoever to offend you.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@amistre64 i thought it was around y axis, shouldn't be dy not dx ?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1depends on your method; i used the shell method, which opens up along the x axis the disc method would travel along the y

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1teh disc method we would have to convert y=x into its inverse x=y, which isnt that hard to do, but just takes extra steps :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh i see, so for the shell method where does the x come from in x(4x^2)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1think of the shell method as finding the area of a sheet of paper, or a flattened out tin can. the width of the paper is the circumference of the base circledw:1342095061762:dw the height of the paper is the function that it hits along the way. Area = base (2pi x) * height (f(x))

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1342095194082:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0OH I GET IT NOW ! thanks @amistre64
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