A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Find the volume of the solid formed when the area bound by the curve y=4x^2 and the x axis is rotated one complete revolution about the y axis
anonymous
 4 years ago
Find the volume of the solid formed when the area bound by the curve y=4x^2 and the x axis is rotated one complete revolution about the y axis

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first find the critical points and use integration

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1or just consider one side of it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you just tell me the answer , because i am getting the wrong answer. I got 16 pi units but the answer is 8 pi units and i don't know where i went wrong.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1please dont ask for "just an answer"

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1342094312271:dw this can be done by shells or disks; which way are you most comfortable with?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i think i know why youre twice as big as the answer; your prolly integrating the whole thing across

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1your in effect sweeping the same volume twice when you do that

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1342094460320:dw if we do shells:\[\int_{0}^{2}2pix(4x^2)dx\] \[2pi\int_{0}^{2}x(4x^2)dx\] \[2pi\int_{0}^{2}4xx^3\ dx\] \[2pi\left(\frac{1}{2}4x^2\frac{1}{4}x^4\right)_{0}^{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh i think i understand. I apologise amistre64 if i sounded rude before. I had no intentions whatsoever to offend you.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@amistre64 i thought it was around y axis, shouldn't be dy not dx ?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1depends on your method; i used the shell method, which opens up along the x axis the disc method would travel along the y

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1teh disc method we would have to convert y=x into its inverse x=y, which isnt that hard to do, but just takes extra steps :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh i see, so for the shell method where does the x come from in x(4x^2)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1think of the shell method as finding the area of a sheet of paper, or a flattened out tin can. the width of the paper is the circumference of the base circledw:1342095061762:dw the height of the paper is the function that it hits along the way. Area = base (2pi x) * height (f(x))

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1342095194082:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OH I GET IT NOW ! thanks @amistre64
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.