a train runs between two stations stopping at each. Its velocity V km/min, t minutes after leaving the first station, is given by v = 0.12t(6-t)

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a train runs between two stations stopping at each. Its velocity V km/min, t minutes after leaving the first station, is given by v = 0.12t(6-t)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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find the time taken to travel between the two stations
if something is stopped, its velocity is 0 right?
yes

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then for which ts does V = 0?
for t=0 and t=6 obviously...
obviously lol
so after first starting it stops again after 6 minutes
i was going to say 360 seconds, but 6 minutes sounds adequate
yup - lol
yup...the time difference between the two stations is 6mins...when the train travels at Vkm/min.
there you go
LOL @Akshat4-10 and @cwrw238 for impersonating me hahahas thanks guys ;)
so for this question how would we find ii- the maximum positive velocity attained iii- the distance between the two stations

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