Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

King

  • 2 years ago

2 Identical wires A and B have the same length L and carry the same current I.Wire A is bent to form a square of side a.B1 and B2 are the values of magnetic induction at the center of the circle and center of the square respectively.Find B1/B2

  • This Question is Closed
  1. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @amistre64 @Callisto please help...

  2. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Mimi_x3 @pratu043 @Diyadiya help

  3. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @UnkleRhaukus @experimentX help..

  4. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Mani_Jha

  5. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @amistre64 @Callisto

  6. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @.Sam. @apoorvk

  7. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ???????

  8. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    can you draw the picture??

  9. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    they havent given one but wait i'll try...

  10. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    So, okay, I got wire A 'square' and wire B 'circle' right?|dw:1342104894718:dw|

  11. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah...

  12. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    are those independent??

  13. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and R=L/2pi ?rite?

  14. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Now, for wire A, magnetic field at 'O' will be the combined effect due to the four current carrying sides of the square loop.

  15. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah....

  16. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, radius 'r' for loop 'B' = L/2pi

  17. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Now, magnetic field for A at O = 4 x \(\mu_oI/(L/8) \)

  18. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    isnt it mu i /2pir

  19. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    That's the square loop, (according to the formula -> B = \(\mu_oI/2\pi l\)

  20. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Oh yes I missed the '2pi', am sorry please account for that.

  21. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Now for the circular loop, \[B= \mu_oI/2r\ = \mu_oI/2(L/2\pi) = \pi\mu_oI/L\]

  22. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    And for the square loop, we found it out to be --> 4 x \(\mu_oI/2\pi(L/8)\) = 16\(\mu_oI/\pi L\)

  23. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so we get pi^2/16 but answer is pi ^2 /8sqrt2

  24. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Now you can find out the ratio! \[\frac{B_A}{B_B} =\frac{16 μ_oI/πL}{πμ_oI/L} = \pi^2/16\] Now where are we going wrong hmmm?...

  25. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    even i got this answer i was wondering hw this is wrong...... :(

  26. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    :__(

  27. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Lol there may just be a printing error in the book. Or. Did you copy out the question correctly?

  28. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah its not a book its a worksheet..okay so thnx didi!!

  29. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    DIDI??? o.O *facepalm*

  30. King
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    :D

  31. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Arey Sirji, I am a guy! (ab Bhaiya bolne ki zarurat nahi hai lekin :P )

  32. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    And whatever worksheet or book, please do check out what's wrong and let us know. :]

  33. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    what's the answer anyway??

  34. apoorvk
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @experimentX I seem to get (pi^2)/16, but his book says (pi^2)/(8sqrt2).

  35. experimentX
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    magnetic field due to circular loop is \[ \vec B_1 = {\mu_0I \pi \over L}\] Magnetic field due to square loop is \[ \vec B_2 = {8\sqrt 2\mu_0 I \over L \pi}\] \[ B_1/B_2 = \pi^2/8 \sqrt 2\] http://www.scribd.com/doc/56083415/3/Example-9-1-Magnetic-Field-due-to-a-Finite-Straight-Wire

  36. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.