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King
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2 Identical wires A and B have the same length L and carry the same current I.Wire A is bent to form a square of side a.B1 and B2 are the values of magnetic induction at the center of the circle and center of the square respectively.Find B1/B2
 2 years ago
 2 years ago
King Group Title
2 Identical wires A and B have the same length L and carry the same current I.Wire A is bent to form a square of side a.B1 and B2 are the values of magnetic induction at the center of the circle and center of the square respectively.Find B1/B2
 2 years ago
 2 years ago

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King Group TitleBest ResponseYou've already chosen the best response.0
@amistre64 @Callisto please help...
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
@Mimi_x3 @pratu043 @Diyadiya help
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus @experimentX help..
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
@amistre64 @Callisto
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
@.Sam. @apoorvk
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
can you draw the picture??
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
they havent given one but wait i'll try...
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
So, okay, I got wire A 'square' and wire B 'circle' right?dw:1342104894718:dw
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
are those independent??
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
and R=L/2pi ?rite?
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
Now, for wire A, magnetic field at 'O' will be the combined effect due to the four current carrying sides of the square loop.
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
yes, radius 'r' for loop 'B' = L/2pi
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
Now, magnetic field for A at O = 4 x \(\mu_oI/(L/8) \)
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
isnt it mu i /2pir
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
That's the square loop, (according to the formula > B = \(\mu_oI/2\pi l\)
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
Oh yes I missed the '2pi', am sorry please account for that.
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
Now for the circular loop, \[B= \mu_oI/2r\ = \mu_oI/2(L/2\pi) = \pi\mu_oI/L\]
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
And for the square loop, we found it out to be > 4 x \(\mu_oI/2\pi(L/8)\) = 16\(\mu_oI/\pi L\)
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
so we get pi^2/16 but answer is pi ^2 /8sqrt2
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
Now you can find out the ratio! \[\frac{B_A}{B_B} =\frac{16 μ_oI/πL}{πμ_oI/L} = \pi^2/16\] Now where are we going wrong hmmm?...
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
even i got this answer i was wondering hw this is wrong...... :(
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
Lol there may just be a printing error in the book. Or. Did you copy out the question correctly?
 2 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
yeah its not a book its a worksheet..okay so thnx didi!!
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
DIDI??? o.O *facepalm*
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
Arey Sirji, I am a guy! (ab Bhaiya bolne ki zarurat nahi hai lekin :P )
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
And whatever worksheet or book, please do check out what's wrong and let us know. :]
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
what's the answer anyway??
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
@experimentX I seem to get (pi^2)/16, but his book says (pi^2)/(8sqrt2).
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
magnetic field due to circular loop is \[ \vec B_1 = {\mu_0I \pi \over L}\] Magnetic field due to square loop is \[ \vec B_2 = {8\sqrt 2\mu_0 I \over L \pi}\] \[ B_1/B_2 = \pi^2/8 \sqrt 2\] http://www.scribd.com/doc/56083415/3/Example91MagneticFieldduetoaFiniteStraightWire
 2 years ago
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