King
  • King
2 Identical wires A and B have the same length L and carry the same current I.Wire A is bent to form a square of side a.B1 and B2 are the values of magnetic induction at the center of the circle and center of the square respectively.Find B1/B2
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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King
  • King
@amistre64 @Callisto please help...
King
  • King
@Mimi_x3 @pratu043 @Diyadiya help
King
  • King
@UnkleRhaukus @experimentX help..

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King
  • King
@Mani_Jha
King
  • King
@amistre64 @Callisto
King
  • King
@.Sam. @apoorvk
King
  • King
???????
experimentX
  • experimentX
can you draw the picture??
King
  • King
they havent given one but wait i'll try...
apoorvk
  • apoorvk
So, okay, I got wire A 'square' and wire B 'circle' right?|dw:1342104894718:dw|
King
  • King
yeah...
experimentX
  • experimentX
are those independent??
King
  • King
and R=L/2pi ?rite?
apoorvk
  • apoorvk
Now, for wire A, magnetic field at 'O' will be the combined effect due to the four current carrying sides of the square loop.
King
  • King
yeah....
apoorvk
  • apoorvk
yes, radius 'r' for loop 'B' = L/2pi
apoorvk
  • apoorvk
Now, magnetic field for A at O = 4 x \(\mu_oI/(L/8) \)
King
  • King
isnt it mu i /2pir
apoorvk
  • apoorvk
That's the square loop, (according to the formula -> B = \(\mu_oI/2\pi l\)
apoorvk
  • apoorvk
Oh yes I missed the '2pi', am sorry please account for that.
apoorvk
  • apoorvk
Now for the circular loop, \[B= \mu_oI/2r\ = \mu_oI/2(L/2\pi) = \pi\mu_oI/L\]
apoorvk
  • apoorvk
And for the square loop, we found it out to be --> 4 x \(\mu_oI/2\pi(L/8)\) = 16\(\mu_oI/\pi L\)
King
  • King
so we get pi^2/16 but answer is pi ^2 /8sqrt2
apoorvk
  • apoorvk
Now you can find out the ratio! \[\frac{B_A}{B_B} =\frac{16 μ_oI/πL}{πμ_oI/L} = \pi^2/16\] Now where are we going wrong hmmm?...
King
  • King
even i got this answer i was wondering hw this is wrong...... :(
King
  • King
:__(
apoorvk
  • apoorvk
Lol there may just be a printing error in the book. Or. Did you copy out the question correctly?
King
  • King
yeah its not a book its a worksheet..okay so thnx didi!!
apoorvk
  • apoorvk
DIDI??? o.O *facepalm*
King
  • King
:D
apoorvk
  • apoorvk
Arey Sirji, I am a guy! (ab Bhaiya bolne ki zarurat nahi hai lekin :P )
apoorvk
  • apoorvk
And whatever worksheet or book, please do check out what's wrong and let us know. :]
experimentX
  • experimentX
what's the answer anyway??
apoorvk
  • apoorvk
@experimentX I seem to get (pi^2)/16, but his book says (pi^2)/(8sqrt2).
experimentX
  • experimentX
magnetic field due to circular loop is \[ \vec B_1 = {\mu_0I \pi \over L}\] Magnetic field due to square loop is \[ \vec B_2 = {8\sqrt 2\mu_0 I \over L \pi}\] \[ B_1/B_2 = \pi^2/8 \sqrt 2\] http://www.scribd.com/doc/56083415/3/Example-9-1-Magnetic-Field-due-to-a-Finite-Straight-Wire

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